Interpreting M+ Peaks in Mass Spectrometry

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18 фев 2015

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Комментарии : 67

@khodaniganeli8489 6 лет назад

i thought ill never understand mass spectroscopy but i was wrong, thank you Sir!!

@SandyLucy11 7 лет назад

Thank you, sir. Your explanation was splendid and cleared a lot of my misconception. Thank you!~

@Ajtraytray 5 лет назад

Your explanations are simply amazing. God bless you

@DSnowaws 2 года назад

These are probably the best Mass Spec explanations I’ve ever heard in my life

@rimshakhan9684 7 лет назад

thank you sooo much sir. your videos helped me a lot to get these spectroscopic techniques. i must say that u did an excellent job to help students like me :P stay blessed. may you get the best reward for doing these videos :)

@Knowbee 7 лет назад

Fantastic compliment! Too kind. Made my day!

@Sophia-sp7eb Год назад

this is the first time I understood any concept in o.chem 100%. thank you sir.

@shammahndzalama9731 3 года назад

This has literally helped me to understand this much better ... thank you so much sir God enrochly bless you

@victoriableecker8226 Год назад

2 minutes into the video I learned more than I did in lecture. Thank you so much

@user-tg1en3gk7k 4 года назад

Perfect explanation, THANKS ALOT!!

@swadhinchetia2792 3 года назад

Teacher should be like you. Great job. Hoping for more videos. Love from India

@Theperfectblabla 6 лет назад

Thank you! This helped so much!

@lexibexitextinexi 3 года назад

DUDE DESERVES A MEDAL FOR BEING SO CLEAR

@kavitadumaga1973 6 лет назад

Thanks sir.... It help me a lot.. Plzz prepare some more videos on organometallic chemistry

@aso1569 5 лет назад

thank you so much 😊 god bless you 🙏🏻

@brenna760 Год назад

This is an amazing video and I needed it for my final tomorrow so thank you so much!!!!!

@shushayhagos3190 6 лет назад

No words , it is great

@rajeshkumarbehera9834 5 лет назад

sir it is my luck that i found your video which helped me very much.thank you

@urwabajwa3502 3 года назад

Life savour kind of videos🥺❤

@MuhammadNaeem-mm8hk 5 месяцев назад

Thanks for the kind video sir. You have made my way of solving the spectroscopic problems very interesting. May you live long sir. ❤

@BilalAhmad-sr5uw 4 года назад

Sir you gave a lot of knowledge.thankss

@romulus2225 3 года назад

great video and example sample analysis

@SonuNigamUnofficial 6 лет назад

you are the best teacher I HAVE ever come through in my whole Chemistry Studying life... Your are blessed with the ability of teaching tough things like Fairytales ...wow stay healthy and spread knowledge .. you are my favourite ... where to get the links to have chat with you sir .... and lastly What is your name ?? thank u so much

@ayeshaasif20asif73 5 лет назад

Amazing explanation

@sammadsaeed3373 6 лет назад

Life saviour!!

@krishna795 2 года назад

This is smooth. Thank you

@towhidsmail 6 лет назад

Thank you very much for your well organized and easy explanations. It made my study easy.

@Knowbee 6 лет назад

You're welcome!

@shehanai123 4 года назад

Jijo2

@tuck295q 6 лет назад

I think you might mixed up methyl butane MS with pentane from the previous video. The MS looks more like methyl butane one or am I wrong?

@dhaneeshapb3154 6 лет назад

Thank you sir...

@wgdanmourad 5 лет назад

you are the best

@uzmabatool3437 2 года назад

Brilliant explanation

@goodluckgoody1366 5 лет назад

THANK YOU VERY MUCH SIR

@Carvel 4 года назад

THANK YOU!

@shammahndzalama9731 3 года назад

Sir if it happens that we dont have m+1 how can we determine the molecular formula?

@abrahamrivera5660 5 лет назад

very helpful!

@amandawramage5865 6 лет назад

I'm confused as to why pentane is displayed on the graph? I thought only ions were displayed? Pentane does not appear to have an electron removed. Can someone please explain??

@Junior-hq3hy 3 года назад

I may be incorrect but the way it works aswell is such that sometimes the whole molecule just becomes an ion due to the way an electron hits the molecule (by just knocking off an electron whilst simultaneously not changing the molecule structure) that’s what they call the parent/molecular ion (in this case pentane)

@mohammadhamza8942 4 года назад

thank youu legend

@akeedasharma4249 5 лет назад

I have a doubt. I agree that relative intensities of molecular ion peak involving both Br isotopes should be same. The doubt is that why this m+2 peak. Is there for molecular ion peak and for other peaks such as base peak. Why don't we have M+2 base peak of same intensity Pl. Answer

@ayeshasiddiqua2607 3 года назад

Plz explain what will be the relative intensity of m m+2 m+4 peaks for 2Cl if present instead of Br

@songohan393 2 года назад

thank you a lot

@benjaminhogan3157 3 года назад

BRAVO!!!!!

@chemistrysmystery8467 4 года назад

Thank you sir

@gildebertvonhaargert5327 4 года назад

THANK YOU

@zahoorahmad-rt1hl 4 месяца назад

Due to the presence of different isotopes of an element in a compound, the parents ions responded differently. How about the daughters ions? As the individual parent ion will generate different daughter ions of different m/z values.

@skylersorkin6129 2 года назад

thank you thank you thank you thank you

@dimitrisgkiousas8928 Год назад

super!!

@fenfentang2263 6 лет назад

can anyone tell me that why secondary has more relative abundance than primary?

@joanazanchetti228 5 лет назад

because its more stable

@rameshbanothu1058 5 лет назад

Tnq sir

@thomasmuntzer1004 4 года назад

But is there not a Chance that there are molekus that have 81br and 13C? So they weigh 125? By the way thank you very much!

@nazlikianersi727 3 года назад

it was usefull

@mukesh2400 2 года назад

super

@kondwanimwafulilwa5521 3 года назад

👏👏

@s.k.sameer2219 6 лет назад

Why value pridict0.055......

@comedydiary5988 6 лет назад

It's a given value for each isotope...

@s.k.sameer2219 6 лет назад

Where 0.055 value come plz someone help me????

@girlish911 6 лет назад

were trying to see how tall the M+1 peak is compared to the M Peak, so we mark our M peak as being 100% (it is 100% of its own height) we took the height of the M+1 peak (by viewing the vertical axis in this spectroscopy -in this case, we cant see it) and we divided it by the height of the M peak. That number is where the 0.055 is where that number comes from