Interview Question: How many String Objects will be created? - String Objects & String Constant Pool 

How can someone explain with this level of clarity. I am amazed by your explanation skills, you are just the best👏

By far the best explanation of String objects!

With 10 mins a very important question got covered and for the same people will take sometimes ½ hour session, Thanks Naveen for the video 👍😊

These interview questions series is really very helpful. Thanks a lot sir.

Hello naveen... Thanku very much... I have worked as a manual tester... But only becoz of u i got a job in mnc as a automation tester.....

Love these interview question series.

Able to understand very clear. Really appreciating for your efforts. Thank you sir

New series is started. Thanks Naveen. Please upload more videos.

Thanks Naveen....... People with zero knowledge on Java can understand your explanation from basix.. You are different

Thanks a Lot for taking up this topic. Concept is clear now

Naveen 4:47 you said 4 objects created ...the same but here 8:49 you telling 3 objects. It quite confuse. Please clarify. Your videos are awesome thanks for your effort....

Naveen Ji, Thank you for sharing this information...👍👍🙏🙂

String str1 = new String("Hello World"); String str2 = "Hello World"; if(str1 == str2) System.out.println("Strings str1 and str2 are equal"); else System.out.println("Strings str1 and str2 are not equals"); //output : Strings str1 and str2 are not equals /* If the new String causes the string to be added to the string pool (as you claim) then the next if statement * should return true...which it does not ... * When you create a string using new ...yes its created in the heap but it does not get * added to the string intern pool unless actually added * * Look at the next e.g. and checkout the difference for yourself */ String str3 = new String("Blue Sky").intern(); String str4 = "Blue Sky"; if(str3 == str4) System.out.println("Strings str3 and str4 are equal"); else System.out.println("Strings str3 and str4 are not equals"); //output : Strings str3 and str4 are equal /* In order to add a string created using new to the string intern pool is to specifically add it...as in case of str3 * str4 is a string literal and has the reference of str3 - since str3 was in the string intern pool * */

Such a beautiful explanation...sir,please can you explain how many objects will be created if we concat 2 strings

Great series again Naveen!! Very helpful!! Thanks a lot!!

String st = new String("Hello"); String s = "Hello"; System.out.println(st == s); //false Can you please clarify this, if the first statement creates an object on heap and also in string pools, then when why st == s is false, instead of true? also can you please explain the use of String.intern() method.

Incredible job naveen, thank you very much 🙏

Hi Naveen, I really love the way you explain the stuff and concepts. Wanted to clarify one thing with you.. When we create an object using new keyword, it will create an object in heap but does it create the object in String pool as well? Since there is no reference pointing to object created in StringPool then why will it create the object in StringPool? Will it not lead to poor memory management? As per my understanding, intern method takes care of doing that if it is not already available in scp.

Very best explanation very nice concept I got concept from this video thanks..

Wow ! that was an amazing explanation. Nobody does it better ;)

Thank u Naveen Sir. Its's really cleared and helpful. :)

Total 3, from string literals 1object + 2more objects.

Amazing explanation, Naveen 😊 really hats off to you

Hello Naveen! In min 5:00. There is something that makes me confused. After creating the 3 objects using new key word you create 2 literals that already exist in String pool then will not be necessary to create 2nd "Hello World" in the pool so at the end it will be 3 objects no 4 in the entire program as you mentioned. In 2 different programs the total of objects are 4 but not in only. Actually, in your next example you dont create a extra "Hello World" because already exist in the pool. Please, correct me if I am wrong.

thank you very much naveen ...

it will create 2 objects one in heap area and another one is string constant pool area i.e SCP area(if the object is not there with the same content if object is already with same content i won't create new object) and string ref n1 is pointing to heap area object

Great explanation 👏

Awesome Naveen! Thank you for the interview series helping a lot..👍

brother can you make a video on how to build graphic library in c/c++ from scratch

Thanks Man👍 I really appreciate your effort Keep uploading more like this

Thank you sir. I have given wrong answer in an interview, now i realised what is the actual concept

Love this series👍

Sir Have a question. In java program If ( n1.hascode()==n2.hascode()) return true n1.equals(n2) true Then why n1==n2 return false. ( Its satisfy hascode and equals contract)

Could u make interview questions on business analysts junior.

Subscribed and liked.... Informative video... 👍

Thanks sir I got more clarification from this video❤❤❤

Thanks a lot it's very helpful

Very helpful 👍...

Please Clarify the Sequence of Memory allocation for Object and Reference in SPM , HEAP and STACK

Add these Java programs in new playlist

It will be create 2 objects .one create in heap memory and other create in string pool

Thank you ,awesome explanation..

Hi Naveen, 1 Query, On creating 2 string objects with new keyword and same string (ex: new ("Hello") and new ("Hello"), it will create 2 objects in Heap but how many will be there in SCP ? 1 or 2 ? Also and if there is already a string "Hello" present in SCP then will these statements create new String in SCP or will point to the existing one only?

@naveen , is it possible to count number of objects created in program? This is an question asked from me

String s = new String("New World").intern(); what will be the difference after adding intern() with new String? How many object created and what is the use case or purpose to use intern()

@2:10 one string object with literal as "new world" gt created without reference inside SCP. string objects present in SCP if not have reference variable are not applicable for garbage collection because a reference internally maintained by JVM.Is my understanding correct or not? Please clear my doubt.

Hi Naveen API automation Testing using bdd cucumber framework please upload the videos

Amazing series

Why String doesn't use scp only

thanks Naveen

Amazing!! Loved it!

why in case when we declare object first and then string literal it create total three objects not 2 in your first expression

what if String n1 = new String("Hello World"); String n2=new String("My World"); Now how many objects are created

Navven Please tell me how to solve this type of problems like input String s="Tommorow", output="T$mm$$r$$$w". another one is input=2**7***9, and output is =23578279

Super Naveen

Could you please prove how two objects are created when we just write String n1 = new String("Hello World");`

Two object. One is Heap and other in SCP For second case 3 objects

0:29 -- one object is created

0:22 2 Objects As The 'String' Class Is Used 2 Times In The Line, 1st in String n1, 2nd in new String("Hello World")

Your telegram invite link expire in About section of your channel can you please send me invite link please

while using string literals no Object is Create, but at video playback of 9:20 you are using String literal and saying one Object will be created. in the SCP. Since we are not using new keyword how can the Object be created. Correct me if I am wrong.?

Output->Only 1 string object

Naveen can you please send me your telegram channel link

Ossom sir

public class StrObjectCreation { public static void main(String[] args) { String s1 = new String("You cannot change me"); String s2 = new String("You cannot change me"); System.out.println(s1 == s2); String s3 = "You cannot change me"; System.out.println(s1 == s3); String s4 = "You cannot change me"; System.out.println(s3 == s4); String s5 = "You cannot "+"change me"; System.out.println(s4 == s5); String s6 = "You cannot "; String s7 = s6+"change me"; System.out.println(s4 == s7); final String s8 = "You cannot "; String s9 = s8+"change me"; System.out.println(s4 == s9); } } Please check.

Anybody help me to give answer of below scenario. If first statement is String str1 = new String(" hello"); String str2 = " hello" In this case how many literal will be present in stringpool If answer is 2 .then why str2 didn't use already existing hello which was created first time.

At 5:45 3 object will be created

It will create 2 object

1st comment good afternoon sir

2 one in heap and one in scp

2 object

One object

1 object

2 objects

2

one

2 object