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Intro to Relations | Discrete Math 

Wrath of Math
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What are relations? We'll be defining mathematical relations with examples - using set theory - in todays lesson!
Discrete Math playlist: • Discrete Math
Discrete Math exercises: • Discrete Math Exercises
We can define relations using sets, and set-builder notation is especially handy! A relation R on a set A is simply a subset of the Cartesian product AxA. Each ordered pair in the relation is thus of the form (x, y) where x and y are in A. The inclusion of (x, y) in R means that x relates to y under the relation R. For example, (2, 3) is in the less than relation on the integers because 2 is less than 3.
We also discuss reflexive, symmetric, and transitive properties of relations - as well as equivalence relations! We also briefly mention how functions are just special types of relations.
SOLUTION TO PRACTICE PROBLEM:
We let A = {0} and R = { (0,0) }. The relation R is in fact an equivalence relation. It is reflexive because every element of A relates to itself. It is symmetric because anytime x relates to y, we also have y relates to x. It is vacuously transitive, because it does not contradict the transitive property. In order to NOT be transitive, a relation must have ordered pairs (x, y) and (y, z) but not (x, z).
I hope you find this video helpful, and be sure to ask any questions down in the comments!
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8 июл 2024

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Комментарии : 35   
@azizhani33
@azizhani33 2 года назад
We let A = {0} and R = { (0,0) }. The relation R is an equivalence relation because: R is reflexive: for a ϵ A, (a, a) ϵ R, R is symmetric: for a, b ϵ A, if (a, b) ϵ R then (b, a) ϵ R, and R is transitive: for a, b, c ϵ A, if (a, b), (b, c) ϵ R then (a, c) ϵ R.
@fahadf_patel
@fahadf_patel 4 месяца назад
It isn't equivalent set ig Cuz see It ain't a transitive set, as it doesn't even have a,b,c to begin with So with that logic it can't be transitive, nay???
@skywalkerluke694
@skywalkerluke694 8 месяцев назад
my best math teacher ever, i watch every videos and i understand them all. Deadass there should be more recognition for him.
@WrathofMath
@WrathofMath 8 месяцев назад
Thanks a lot!
@Victual88
@Victual88 7 часов назад
Thanks Sean! btw I think there is a equivalence relation because it satisfies all three properties. for all x in A (x,x) is in the relation, Since we only have one element in the set, which is just a pair of zero's then we will have symmetry since both the first and last entry of the pair are the same, We fufill the transitive property automatically since there is only one element in the relation.
@MathCuriousity
@MathCuriousity 7 месяцев назад
How did you say cream shaft with a straight face bahahah 🙌
@TusharDeb
@TusharDeb 2 года назад
THIS WAS SO EASILY EXPLAINED! THANK YOU!
@WrathofMath
@WrathofMath 2 года назад
Glad to help! Thanks for watching!
@Chetulertusurunu
@Chetulertusurunu Год назад
Coming from my official Uni Script: So much this!!! I thought im just to stupid, turns out it was just not really explained there at all.
@charlesmaurice1047
@charlesmaurice1047 3 года назад
maybe you could talk about partial order and total order sets ? It's in the same theme ( and to be honest, I didn't fully understand it and you're the best maths teacher on the net, so... pls ? :) )
@jingyiwang5113
@jingyiwang5113 9 месяцев назад
Thank you so much for this detailed explanation! This is a lot better than what my professor explains in class. Thanks!
@WrathofMath
@WrathofMath 9 месяцев назад
Glad to help - thanks for watching!
@andrewjustin256
@andrewjustin256 10 месяцев назад
Mr. Shawn, please make a video on how to calculate all possible relations of a given non-empty set; additionally, how to calculate all possible, minimum and maximum reflexive, symmetric, transitive, identity relations.
@TranquilSeaOfMath
@TranquilSeaOfMath 2 года назад
This is explained well. It is an important topic which leads to deeper mathematics topics.
@WrathofMath
@WrathofMath 2 года назад
Thank you! Indeed it is, and there is definitely a lot more to say on the topic!
@AnoyingGamersNL
@AnoyingGamersNL 4 года назад
I think the relation on the set A ={0} does satisfy the equivalence class because if you take the (
@WrathofMath
@WrathofMath 4 года назад
You're correct, right on! Thanks for watching!
@safa-uc1mk
@safa-uc1mk 7 месяцев назад
Hi! could you expand on the (
@Gernexty
@Gernexty 3 года назад
Thx for this helpful video. I have a test on this today and I was baffled trying to read the book.😁
@WrathofMath
@WrathofMath 3 года назад
You're very welcome, so glad it helped and I hope your test went well!
@MathCuriousity
@MathCuriousity 7 месяцев назад
Absolute stunner of a video 🙏🏻 so for this new question I have on this new video (I also asked two on the equivalence relations video), what do you mean by vacuously true transitively? What would be a reflexive that’s vacuously true or a symmetric that’s vacumously true? Thanks kind god!
@christaylor6499
@christaylor6499 Год назад
This definition of relation is often given, but has drawbacks. Consider the pair-set R={(a,a)}. We can work out if it's transitive, symmetric, or irreflexive just by looking at it, so those are genuine properties of a relation defined that way. But we cannot know if it's reflexive or surjective without specifying a context, because {(a,a)} is a subset of infinitely many Cartesian products. So reflexivity and surjectivity are not properties of R. For example, R is reflexive wrt {a}, but not wrt {a,b}. A better definition of relation is as a triple (X,Y,P), where the pair-set P is a subset of XxY. Then reflexivity and surjectivity can be specified as properties of the relation, since the "context" Cartesian product is part of the object used to represent the relation.
@MathCuriousity
@MathCuriousity 7 месяцев назад
Hey lovely video and a second question: if we let A = {} do we then say that bill set is an equivalence relation because all three properties are vacuously true? Or is it a non starter since we can’t create an actual relation so no relation exists ? Or can the null set be a subset of null set X null set? Cuz then we can say R = {} also! Right?
@natsibm2488
@natsibm2488 2 года назад
it looks reflexve
@_kevin_wong_
@_kevin_wong_ 2 года назад
AMAZING!!!
@WrathofMath
@WrathofMath 2 года назад
Thanks Kevin!
@amydash796
@amydash796 11 месяцев назад
I love you man
@WrathofMath
@WrathofMath 11 месяцев назад
love you too
@labiribiri1901
@labiribiri1901 9 месяцев назад
I understood everything up until the transitive part in (0,0). I do not know where this comment section keeps getting the non-existent extra (0,0) from
@chiviza
@chiviza 7 месяцев назад
I think the reason you're getting confused is becasue you are looking for two elements in the set {(0,0)}. But if you remember, when we write down sets, we don't repeat the ordered pairs. So in this case, x, y, and z are all 0's. So yes, you could write { (0,0), (0,0)} but that is. the same as {(0,0)} we just don't write it twice like we also don't write down ordered pairs twice in functions, (because it leads to the same point). We could have all the letters of the alphabet in a set, if they are all the same number, then we just write it once.
@chiviza
@chiviza 7 месяцев назад
Sorry if my explanation is super wordy.
@labiribiri1901
@labiribiri1901 7 месяцев назад
@@chiviza thanks
@safa-uc1mk
@safa-uc1mk 7 месяцев назад
@@chiviza i was also confused by the same thing, but your explanation makes sense! Appreciate it :D
@TheBlimpFruit
@TheBlimpFruit 4 года назад
Cream Shaft
@WrathofMath
@WrathofMath 4 года назад
A good man, that cream shaft!
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