You are amazing! I just saw your videos. I have been having problem on Laplace Transform, especially the Inverse Laplace...but the way you solve it is very simple and well understood. Thanks...Jude from Nigeria
A great and subtle way to work the algebra in favor of a result consistent with Laplace tables. One thing I did not catch was why at aprox 45:54 you derive the denominator. Thank you!
Grabe naman po to maam! Napakalinaw po ng pagkakaturo nyo. May methods den po kayo na inintroduced na ngayon ko lang nalaman! Maraming salamat po maam. Sobrang malaking tulong po ito at may quiz kami mamaya abt Inverse Laplace! Rerecommend ko po tong channel nyo at mukha dito na ako lagi tatambay! Btw, new subscriber here!! Godbless you po Maam!
thank you maam napaka linaw po ng turo nyo tanong lang po maam sa prob3 what if yong senet po na value ng s is s=1 :A((1)-1)=9-9 -->. 0=0 po ba maam? salamat po
I know that I'm a month late, but might as well reply for someone else who needs it. On the left hand side, she took out "S" as common out of "AS+BS", resulting in (A+B) being the coefficient of "S". Then she compared said "A+B" with the S-coefficient on the left side of the equation ('1' in this case), resulting in A + B =1. Then she did the same thing for the constants and got 2A+B=4. Then simply subtracted both of the equations to get the value of A. Finally, she used the newly-obtained value of 'A' in one of those equations to obtain the value of B. Hope this helped.
Given: Y(s) = X(s)*(1-s^2)/(1+a*s)+X(s) Factor out X(s) on the RHS: Y(s) = X(s)*[(1-s^2)/(1+a*s) + 1] Divide both sides by X(s): Y(s)/X(s) = (1 - s^2)/(1 + a*s) + 1 We could stop here, as we've technically met your goal of isolating Y(s)/X(s). But, usually, it is desired to convert it to a single fraction. Simply form an equivalent fraction to replace 1, so we change to common denominators: Y(s)/X(s) = (1 - s^2)/(1 + a*s) + (1 + a*s)/(1 + a*s) Y(s)/X(s) = (1 - s^2 + 1 + a*s)/(1 + a*s) Simplify, and we have our result: Y(s)/X(s) = (-s^2 + a*s + 2)/(1 + a*s)
