Invertible and Non-Invertible Systems (Solved Problems) 

Neso Academy u are the best I've prepared for my interview 2 days back using ur digital electronics tutorials 👏👌 can u start a new series about Microprocessors Microcontrollers and embedded systems

I believe there are both non avertible; many to one maping. for the first function you plug -1 and +1 you will get the same answerr which is one. for the second question, when you take the derivative of any constant it could be always zero.

Hello. When proving that a system is invertible, when should we use the step function instead of the impulse function?

HW PROBLEMS: 1. Non-Invertible 2. DEPENDS on wether dx(t)/dt is STRICTLY MONOTONIC or not EXPLANATION OF 2: dx(t)/dt is the slope of the function x(t). If this slope is STRICTLY MONOTONIC (i.e. if it is constantly increasing in value OR if it is constantly decreasing in value), then it follows 1 to 1 mapping ("1-1"). And thus it is INVERTIBLE. Otherwise, it is Non-Invertible. * How to find if dx(t)/dt is STRICTLY MONOTONIC: We have to check wether d2x(t)/dt2 maintains the SAME sign throughout its range (i.e. if constantly > 0 OR if constantly < 0). If it does, then dx(t)/dt is strictly monotonic, and thus "1-1", and thus INVERTIBLE.

Sir Thank you so much. I couldn't believe that I'm getting a world class tutoring for free. It would be nice if you do a series on microcontrollers microprocessors and embedded systems. Since you have given us a solid background in digital electronics

Sir,can we make a generalization here......that the systems which produce the output as the scaled version of input is always invertible...If not give me an example..@nesoacademy

Both are non invertable Please give me the solution

plz answer for HW problem

Q2.Differentiation of any constant is zero....so many to one .. so non-invertible Q1. When you put u(t) then you will get invertible

U have stopped ece branch lecture videos please continue networks and other subjects also sir???

can we use u(-t) as input to hw problem 1 such that its output in u(t^2)

Can we use 0&π to prove sine terms as non invertible

H. W. 1.non invertible 2.non invertible

Sir please share the answers in next video

how can we gurantee the invertiblity of system by only considering impulse or unit step function?

Hi, Could you please explain if the below system is invertible or not . And if it is invertible , what is the inverse system in this case ? y[n] = x[n]x[n-1]

Both r non invertible, bcoz many to one mapping. 1. Take x(t) = u(t) and u(-t) : output is u(t) for both. 2. Take x(t) = u(t) and -u(-t) : output is impulse(t) for both.

please add convoloution, fourier transform

Thanks sir

Hello sir Will plz explain it with numerical Value than it is better way to understand for us

1. Put x(t2) =t2 ... (-1)2 =(1)2. Hence many to one 2. Put x(t)= t. Diff we get y(t)=1. Hence many to one

both HW problems are non-invertible . in 1st problem if we take t=2 and t=-2 , then input will be x(2) and x(-2) and output for both will be y(t)=x (t^2) i.e x(4), so it is many to one mapping . in 2nd question if we take x(t) = u(t) and x(t)=u(-t) then output for both will be zero , so many to one mapping

1. Invertible 2. Non-Invertible

1 Non invertible & 2.Invertible

1).Invertible 2). Non-invertible

Sir, If in the 1st home work question, we take input as u(t) & u(-t) , will the output be x(t^2) ?, system is non - Invertible?

You told three properties to check if the system is dynamic or not? Can we say that those properties hold true for the invertible system too? Like if time scaling or time shifting is happening then the system is invertible?

your explanations are the greatest!! I even let the adds run for you! hahah

The third question is many to one mapping I guess. Because as we put different values of t we get same answer i.e. 1. Correct me if I am wrong.

1. Non invertible, since for negative and positive of some time 't' we get same value of y 2. Invertible, since for different values of x we get different values of y

Both should be non invertible

sir please give answer of HW problems

Both non invertible .. right?

can we use impulse signal in place of step signal

Delta(t) =1 at t=0

draw graph and check , both question is non-invertible

Both seems invertible

1.invertible 2.non invertible For the first one take u(t) & -u(t) as input will get one to one mapping For the second case take input 1 & 2 will get zero because Differentiation of any contast is zero so will get many to one mapping hence its non-invertible system

1.Non invertible 2.Non-Invertible

2nd ex. is invertible coz for x(t) = r(t) nd u(t) we gt different o/p. so 1-1 mapping . hence I.V.

y(t)=(2+sin⁡t)x(t) is invertible or not? plzz ans it

Can a system be invertible and non at the same time ?

1) Inv 2) Non Inv

Both are non invertible

Sir agar y(t)=x(2t) m x(t)=u(t) aur x(t)=u(2t) lenge to non invert aaga

for the first question if we give dirac (t) and -dirac(t) one will become dirac t square and other will be - dirac t square . so if t goes to 2 for both wouldn't to result be 0 because dirac (2)= 0 ? and dirac(4) is also 0 other than t =0 dirac would be 0 right or am i confused?

Both are Invertible

Non -invertible system and invertible system

How is the last example a proof of invertibility? How can you show only two examples of different inputs giving different outputs? Of course it is invertible, but isn't that not sufficient proof?

both are NI easy.

sir plz explain the homework sums

wt abt the system when y(t)=x(t+1)

#Neso Academy

Both are invertible

Invertible is first 2nd may or may not be invertible

y(t) = x(t-5) - x(3-t) What about this...invertible or not ???

Both r invertible ?........reply

Both are non invertable

1.non invertible 2.invertible

Both noninvertible

i think 1st one is invertible but 2nd is non invertible

sir if i take u(t) and u(2t) as two inputs in 3rd problem the system will not be invertible?

Both are non invertible Put x(t)=u(-t) and u(t) in first case Put x(t)= 2 and 1 in second case

Non invertible Invertiable

both invertible .

solve plz y(t )= ∫ 𝒙(𝟓𝝉)𝒅𝝉 𝟒 interate from -infinity to 4 is invertable or not??

1.Invertible,2.Non Invertible

Non Invertible both of them.

1)non-invertible 2)non-invertible

invertible non invertible

Both are non - invertible

both are non invertible

1) NI 2) NI

Both the problems having the time invertible property.

Both invertible...

if possible give ans to me .

@6:29 smj nii aaya sir kuch bhi

1.non invertible,2.invertible

1.Invertible 2.Non Invertible

Both are non invertible

both are invertible

1.Invertible,2.Non Invertible

1.invertible 2.non invertible

1.Non invertible. 2.invertible

1. Non-Invertible 2. Invertible

both are non invertable

1.Non invertible 2.Invertible

1.invertible 2.non invertible