This definite integral could not be evaluated using the integration techniques learned in calculus2. I showed that the problem could be modified by appropriate substitution to facilitate the use of the gamma function for its evaluation.
Sir i solved this question at my first attempt and i used a substitution and then applied by parts and it was very easy to solve this . Thnks for sharing these interesting questions. My wishes to you from India
Hi, very nice video, extremely elegant solution. But I have a question: when you move to the left part of the blackboard, you seem to stay very close to the blackboard itself; is there an obstacle we don’t see? As I watch more and more videos of yours, my curiosity is gradually tending to infinity! 😊
y=sqrt(ln(1/x)) y^2=ln(1/x) e^y^2=1/x e^-y^2=x ye it's straight up just the inverse, which means you can use the following inverse function integration by parts formula: int(f^-1(x))dx=xf^-1(x)-F(f^-1(x))+C
Hello Mr. I'm University student in Ethiopia and first I want to thank you for your supportive videos and i want to ask you a video request that's about limit and derivative from applied maths 1 we have an exam in next weak and we want a exam based video if you agree please let me know and I will send you our course outline THANKYOU and sorry for my english😅
0:17 understood nothing but it is going to be funny :D 1:20 and one question can you please use brackets for things like integrals, sums, and such symbols i am everytime so confused to dont find them 2:04 if you say that 5:26 and also please use brackets if you multiply negativ numbers!!!! 6:02 it should work now 7:07 ok i still just understand the healve but ok 8:44 great! LG K.Furry
Hello brother, u have been a great help. I have a favour to ask, if u could provide me the pdf of aops introduction to algebra solutions manual i would really be grateful.
