The same video in Hindi with better sound and editing ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE--KVhMAILAVs.html Length = 120mm Width = 60mm and Height = 75mm
A straight line PQ, equally inclined to the HP and the VP, has its end P in front of the VP and 20 mm above the HP. End Q is behind the VP and 40 mm below the HP. A point on this line is in the VP and 10 mm below the HP. Draw the projection and finds TL and inclination of line with HP, if the distance between the projections ends is 60 mm.
+Sachin Pandy اريد ان أسألك يامستر ساشين هل يمكن استنتاج المنظور من مسقطين على برنامج الاوتوكاد مباشرة مع تمنياتي لك ولأسرتك بالتوفيق والنجاح المستمر وأكرر شكري وتقديري لشخصكم الكريم
Hola, tengo muchas ganas de hacerlo en más idiomas, pero no estoy seguro sobre el traductor de Google, así que no lo haré, pero veamos si lo estoy haciendo en un futuro cercano, se lo haré saber gracias
Sachin Pandya Yes I came across many questions which two views will be given and I am asked to draw a third view, without knowing what the object looks like.I had trouble "visualising" the object
Sir job ka second part vaala hissa base SE 15 mm uppar ki taraf hai aap bhul gaye aur side se 15 mm andar hai vo correct hai but second part job ka base SE uppar vaala kaam reh Gaya by mistake aapse incomplete 😂😂😂
crank OA rotates about O and the rod AB which is connected to crank OA at A is concentrated and to pass through the guide at p trace the locus of point B for complete revolution of the crank OA. OA =40 AB=120 OP=60