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Math Olympiad Logarithmic Equation | Exponent Simplification #exponent#olympiad #simplification#exam
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Комментарии : 40   
@walterwen2975
@walterwen2975 20 дней назад
Math Olympiad Logarithmic Equation: (x - 5)^[log(5x - 25)] = 2; x = ? (x - 5)^[log(5x - 25)] = (x - 5)^log[5(x - 5)] = (x - 5)^[log5 + log(x - 5)] log(x - 5)^[log5 + log(x - 5)] = [log5 + log(x - 5)]log(x - 5) = log2 [log(x - 5)]² + log5[log(x - 5)] - log2 = 0 Let: y = log(x - 5), y² + (log5)y - log2 = y² + [log(10/2)]y - log2 = 0 y² + (log10 - log2)y - log2 = (y - log2)(y + log10) = 0 y - log2 = 0, y = log2 or y + log10 = 0, y = - log10 = log(1/10) y = log(x - 5) = log2, x - 5 = 2; x = 7 or x - 5 = 1/10; x = 5 + 1/10 = 5.1 Answer check: x = 7: (x - 5)^[log(5x - 25)] = 2^(log10) = 2¹ = 2; Confirmed x = 5.1: (0.1)^(log0.5) = 2; Confirmed The calculation was achieved on a smartphone with a standard calculator app Final answer: x = 7 or x = 5.1
@kassuskassus6263
@kassuskassus6263 15 дней назад
Nice job !
@superacademy247
@superacademy247 15 дней назад
Thanks!
@UKPEINDANIELU.
@UKPEINDANIELU. 20 дней назад
Fantastic
@superacademy247
@superacademy247 20 дней назад
Thank you so much 😀
@user-tb7nd2ut9t
@user-tb7nd2ut9t 5 дней назад
Nice job ❤
@superacademy247
@superacademy247 5 дней назад
Thanks 😆 I'm glad you like it 👍
@hossamwalid3599
@hossamwalid3599 5 дней назад
Amazing
@superacademy247
@superacademy247 4 дня назад
Thanks!
@carlosharmes2378
@carlosharmes2378 8 дней назад
Nice 2 & 5 equation... 💌
@superacademy247
@superacademy247 8 дней назад
Keep watching
@rfnobando
@rfnobando 6 дней назад
When you have this: log(5m) * log(m) = log(2) you can do this, 'cause log(10) = 1: log(5m) * log(m) = log(2)^log(10) then, you have log(5m) * log(m) = log(10) * log(2) log(5m) * log(m) = log(5 * 2) * log(2) then m = 2, 'cause the expressions on both sides are the same so: x - 5 = 2 x = 7
@superacademy247
@superacademy247 6 дней назад
Yes. And there's one more solution x=5.1
@tristan583
@tristan583 7 дней назад
Great but results need verification, X can’t have two different acceptable values
@masoudghiaci5483
@masoudghiaci5483 17 дней назад
❤❤
@miffyLake
@miffyLake 21 день назад
That`s great teacher.
@KT-vi7gd
@KT-vi7gd 14 дней назад
Detailed explanation ! Good !
@superacademy247
@superacademy247 14 дней назад
Glad it was helpful!
@naakatube
@naakatube 3 дня назад
Solved it in my head in 30 sec!
@superacademy247
@superacademy247 2 дня назад
Can you solve it overhead for the second solution?
@umutkargili3617
@umutkargili3617 22 дня назад
Appriciated, that's why computer is invented
@RealQuInnMallory
@RealQuInnMallory 14 дней назад
(5x)^2(25x)= {25x^2 625 x^2}= 600x (x (minus ➖ 3x+2)
@joserubenalcarazmorinigo9540
@joserubenalcarazmorinigo9540 17 дней назад
Excelente, pero en el discriminante también se puede cambiar 2 = 10/5 y trabajar con log 5, entonces: log2 = log(10/5)=log10-log5=1-log5
@yifengxiao
@yifengxiao 14 дней назад
multiplying both sides by 5, then let y=5x-25. we have (logy)^2=1, ....
@SidneiMV
@SidneiMV 15 дней назад
ln(x - 5)[ln(5x - 25)]/ln10 = ln2 ln(x - 5) = u u(u + ln5) = (ln2)(ln2 + ln5) u² + uln5 - (ln2)(ln2 + ln5) = 0 u = (-ln5 ± √[ln²5 + 4ln²2 + 4(ln2)ln5]/2 u = [-ln5 ± (ln5 + 2ln2)]/2 u = ln2 => ln(x - 5) = ln2 => *x = 7* u = -ln10 => x - 5 = 1/10 => *x = 5.1*
@user-ee7nw2rx9s
@user-ee7nw2rx9s 21 день назад
А проще нельзя? Логарифмировать по основанию 10 Получаем log(x-5)* log(5*(x-5))=log2, Есть формула log (a*b) =loga+log b Отсюда log (x-5)*(log(x-5)+log5) =log2 И замена log (x-5)=a Получаем обычое квадратное уравнение а*(а+log 5)=log2
@victorfildshtein
@victorfildshtein 14 дней назад
Тут фишка не в том, чтобы привести к квадратному уравнению, а в том, чтобы извлечь корень из дискриминанта.
@user-ee7nw2rx9s
@user-ee7nw2rx9s 10 дней назад
Дискриминант (log5)^2-4 log2 Если учесть что 10=5*2, а log 10=1 и log(a*b) =loga+logb, то Получаем полный квадрат, как в решении и гораздо быстрее
@ludmilak9396
@ludmilak9396 21 день назад
Надо было сразу указать, что log -- это ln, то есть логарифм по основанию 10.
@mmdexperiments3828
@mmdexperiments3828 21 день назад
ln - это натуральный логарифм, по основанию е. А логарифм по основанию 10 пишется lg. Согласна, что тут непонятно в условии, что за логарифм, т.к. написано просто log без основания. Так что либо автор ошибся, либо это местная форма записи такая, мол, без основания это значит по 10. Но я сомневаюсь.
@user-bs8mi3qw7g
@user-bs8mi3qw7g 21 день назад
This is to challenge our brain and math concepts. Dependence on computers is for people who don’t think for themselves. It’s for zombies! Dr. K
@kevinmadden1645
@kevinmadden1645 20 дней назад
AKA Democrats.
@kevinmadden1645
@kevinmadden1645 20 дней назад
You could read "War and Peace" three times cover-to-cover and he would not have solved this problem .After logging both sides to base ten, work with ratios. Much easier!
@ardayavuz9806
@ardayavuz9806 18 дней назад
i found 7 without pencil or page. but 5.1? oh no i can't do that lol
@sirajzama8080
@sirajzama8080 17 дней назад
Same here
@sunil.shegaonkar1
@sunil.shegaonkar1 16 дней назад
the integer solution is x = 7.
@maxk6856
@maxk6856 3 дня назад
Why you dont write 10 in log index ?
@superacademy247
@superacademy247 3 дня назад
The convention I use in the video to write log 10 is also acceptable
@baselinesweb
@baselinesweb 17 дней назад
Or, you could just say let's try x=2 and see what happens.😄
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