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log(2) = 0.30103 0.3log(5). A=log(5^4311)= 4311* log(5)>4311*0.7=3017.7 B=log 4^5311=log(2^110622)=110622*log(2)A.We used this trick often in physical chemistry classes. 0.30103 is a handy number to remember. Like some smileys with ears (3), eyes (0) and nose (1). When log(2) is known, we also know log(4), log(8) and log(5).😎
It's much easier to prove, because 4 power 6 is more than 5 power 5 and we also have 5311 divided by 6 is more than 4311 divided by 5 and that's enough to prove it
