Java 8 Stream - How to Sort a Map using lambda | Example | Java Techie 

Thank you so much. Learning from your videos in realtime.

Thanks for the good explanation. The way examples were explained is awesome. Please continue to do the same.

Best explanation. I learnt a lot from this channel. Thank you so very much 🙏

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I've never seen this kind of detailed explanation on rare concepts. Very useful bro... Thank You so much for this video.. Keep it up :)

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great presentation with realtime examples!! please also cover Optional Class methods

Super Great Excellent explain

Thanks you cleared all my doubts

Great....God bless you.....Could you please make video on difference between interface and abstract class with example in Java 8. Would be highly appreciated.

Hello Java Techie, your explanation is the best ever. My request is that please make a video for Optional class as well. Thanks.

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Amazing explanation! Please make more video on java 8

Good explanation.. thanks

Thankyou nice explanation

Sir , found very late, but so helpful, please do videos on data structures and algorithm with same kinda explanation for time and space complexity

Please don't stop here .. make more videos on this type of concept.

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tq for doing this vedio, its useful.

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Great Tutorial

Covered most of my doubts

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Mr Dependable 🙌🏼

Nice tutorial

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Best video

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Can u detailed explanation for method reference

Nice one , I want to see how to debbug in java

Instead of using reverse() on comparingByvalue I have used like below .. dataMap.entrySet().stream().sorted(Map.Entry.comparingByValue(Comparator.reverseOrder())).forEach(System.out::println);

When will you upload more videos related to Java Stream API

It took me a while to understand that he used a list to stream list of strings and then map to stream employee objects

This example too you used (int) for Long. If you use actual Long values then this code will break. Very fuzzy logic to use Employee as key and value as Integer

I feel this hard as hell even though I practice a lot

sorry for the lame question...but we're using the entrySet() with employeeMap just to get it in list form(Map.Entry), so that we can use it for sorting, like entry.getKey()... right?

Hello, how can wirite program for passing employee object in hashmap as value and want to sort by value based on employee id?

Time stem 6:54 i try to add reversed() method but it gives error

i have tried the same but its not sorting not sure whats the issue

Line number 21gives Cannot infer type arguments for ArrayList error. I am using Java 17.

I am doing the same way, but i am getting an error like LinkedHashMap cannot be cast to class ProcessFlow (POJO) (LinkedHashMap is in java.base of loader 'bootstrap' ; ProcessFlow is in unnamed module of loader 'app'). I am stuck, can you please help here

How to sort more than one properties.?

Hi Sir can you tell how to collect map object using stream instead of sysout?

can we remove the comparator in the treemap constructor if we are sorting by streams

sir ClassCastException is coming when i am not passing lamda exp in TreeSet Constructor . when we are sorting using streams why i need to still pass lamda exp in TreeSet Constructor???

Hello, what to do if the map's key and value are both integer?

Hi Basant, map.entrySet().stream().sorted(Map.Entry.comparingByKey().reversed()).forEach(System.out::println); In the above line, reversed() method is not working. I am getting compile time error here in this case. But when I am trying the below approach, it's working. map.entrySet().stream().sorted(Entry. comparingByKey().reversed()).forEach(System.out::println); Please suggest exactly in which way we have to try?

Could you plese help me to sort like this Map using java 8

why you are using treemap here..any reason

entries.stream().sorted(Map.Entry.comparingByKey().reversed()).forEach(System.out::println); is not working at 6:53 please help

Comparing by value how to do ...

HashMap keyValuePairs = new HashMap(); var valuesList = keyValuePairs.Where(x => x.Value == keyValuePairs.Values.Max()).Select(v => v.Key).OrderBy(y => y).ToList();

// Sort map by values using stream Map myMap1 = new HashMap(); myMap1.put("a", 1); myMap1.put("d", 2); myMap1.put("b", 3); myMap1.put("f", 4); myMap1.put("h", 0); myMap1.put("g", 4); myMap1.put("e", 8); Map employeeMap = new HashMap(); employeeMap.put(5, new Employee(1, "Tom", 20)); employeeMap.put(9, new Employee(9, "Robert", 45)); employeeMap.put(1, new Employee(100, "Gita", 29)); employeeMap.put(6, new Employee(15, "Tara", 25)); employeeMap.put(3, new Employee(3, "Bal", 29)); employeeMap.put(2, new Employee(22, "Tarun", 39)); // Sorting using comparator //myMap1.entrySet().stream().sorted((a,b)->a.getKey().compareTo(b.getKey())).forEach(System.out::println); //myMap1.entrySet().stream().sorted((a,b)-> a.getValue()-b.getValue()).forEach(System.out::println); // Reverse order //myMap1.entrySet().stream().sorted((a,b)->b.getKey().compareTo(a.getKey())).forEach(System.out::println); //myMap1.entrySet().stream().sorted((a,b)-> b.getValue()-a.getValue()).forEach(System.out::println); // Objects //By age //employeeMap.entrySet().stream().sorted((a,b)->a.getValue().getAge()-b.getValue().getAge()).forEach(System.out::println);; //By name //employeeMap.entrySet().stream().sorted((a,b)->a.getValue().getName().compareTo(b.getValue().getName())).forEach(System.out::println);

Hi Java Technie map.entrySet().stream().sorted(Map.Entry.comparingByKey().reversed()).forEach(System.out::println); above code showing compilation error because of reversed method above map is string as key and int as value

Do we really need stream for sorting? I can write like below studentslist.sort( (o1, o2) -> o1.getFirstName().compareTo(o2.getFirstName()));