JavaScript Mock Interview | Online Interview | Questions and Answers 

Good questions. Thank you for uploading.

Awesome as usual...

Thanks for the video

My answer for the first question const addMemberAge = ({ age, kids = [] }) => [age] .concat(...kids.map(addMemberAge)) .reduce((accumulator, currentValue) => accumulator + currentValue);

Can you recommend a good GIT and GIThub course

No offense to the interviewee, but I really wouldn't really start an answer to TechSith's questions with "it's a very simple question" :) Anyways, a potential recursive answer to the first question: (should be able to handle ages as keys or within nested arrays, objects etc ) function getSum(obj, sum = 0) { if(Array.isArray(obj)) { for(let ele of obj) { sum = getSum(ele, sum) } } else if(typeof obj === 'object') { for(let key in obj) { if(typeof obj[key] !== 'object') { if(key === 'age') { sum = sum + obj[key] } } else { sum = getSum(obj[key], sum) } } } return sum }

Can you make a video on career path in IT field... Thankyou for all your react and javascript videos , with best and simple way of explaining things.

A "neater" recursive solution to question 1: function addKidAge(kids) { let kidTotalAge = 0; for(const kid of kids) { kidTotalAge += kid.age; if(kid?.kids?.length > 0) { kidTotalAge += addKidAge(kid.kids); } } return kidTotalAge; } To run it, just do addKidAge([profile]) Notice that the profile object is inside an array :)

The first problem is just flat a tree. Using recursion is the first thing that pops into my head. However you can run away from the problem by using JSON.stringify, then all there left to do is analyse the json string, kind of like cheating

Can you direct me to video tutorial you're explaining these concepts deeply ? Thank you

Hi, I have asked to write code for write in ballots using JavaScript in my interview

This SHOULD be a bulletproof solution to the first problem! Accounts for when some ages don't exist const addAllAges = (profile) => { if (!Object.keys(profile).length) return 0; let totalAge = profile.age || 0; for (let kid of profile.kids) { if (kid.age === undefined) continue; if (kid.kids !== undefined) { totalAge += addAllAges(kid); } else { totalAge += kid.age; } } return totalAge; }

function totalAge({age,kids=[]}){ return kids.reduce((sum,kid)=> sum + totalAge(kid),age ) } console.log(totalAge(profile)); //Use reduce

asked me api has currency , value store value ony db by api request should not repeat for currency he told me solution 1/1 , 2/2 diagonal matrix solution for this problem

Hi Techsith, Thank you for Javscript and NodeJS videos. It would be great if you can please make a video on 'How to Monitor Log files Monitoring log files using some metrics exporter + Prometheus + Grafana'? Thanks a lot.

I'm just starting out in coding with Javascript... But regardless of coding language being used, I think it might be more efficient to write stubs & pseudo code first, explaining what your doing and why verbally as you stub it out... Once psuedo code makes sense, then write corresponding code for each stub... If one just jumps in and starts coding, even if one gets it correct first time, there's very lil interaction with interviewer.... Just a thought... I've always been of mindset that if one cannot explain it, then they don't really understand it... Plus during an interview psuedo coding & stubbing it as you explain gives interviewer an idea of your thought process and opportunity to explain as you're writing pseudo code why ( your rationale ) for implementing something a particular way... I'm not a professional programmer. I'm working on becoming one... Thanks for sharing video

hi techsit interviewer asked prime no program n no asked me optmize for loop for n=3000 for(i=0;i

2 yr exp solved all of them within 5mins, no google

It only took me 367 tries but I finally solved the first problem. (Feel free to suggest improvements.) function addUpAges(profile) { let total = 0; function addUp(profile) { total += profile.age || 0; if (!profile.kids) return; return profile.kids.forEach(addUp); } addUp(profile); return total; }

my answer for 2nd problem: function que(){ let first = Math.floor(Math.random() * Math.floor(10)); let sec = Math.floor(Math.random() * Math.floor(10-first)); console.log(`${first}+${sec}`); } for(let i=0;i

The first problem can be solved with one line. Easy JSON.stringify(profile).match(/\d+/gi).reduce((a, c) => {return a + parseInt(c)}, 0)

last problem solution : const generateRandomNumber = (max, min = 1) => { return Math.floor(Math.random() * (max - min) + min); }; const generateProblems = (max, n) => { for (let i = 0; i < n; i++) { const firstRandomNumber = generateRandomNumber(max); console.log( `${firstRandomNumber} + ${generateRandomNumber( max - firstRandomNumber )} = ` ); } };

my simple solution for the second problem. can i use a function that accepts 2 arguments? function game(num, num2){ for(var i =0; i

function sum(root) { return root.age + (root.kids || []).reduce((s, k) => s + sum(k), 0); }

Hi Techsith, It would be great if you can please show us how to read an email in outlook using Microsoft Graph API. Thanks in advance.

Hi sir , an interviewer asked me to find largest number can be form by concatinating the numbers . Eg Let arr =[ 90,95,9]; so after concat largest number would be like "99590" . Could you please suggest me solve this in easiest way .

Sir, please use a good mic, your sound creates echo effects soo much.

Hello sir I am a new coder in Javascript my level is beginner can I get a mock interview as I want to move to Javascript frameworks.

what is is viewencapsulation

This Indian guy was baad, does he work for a University ?

too slow

I think he is over complicating the problems. In a interview you wanna start with the simplest solution and then work up from it. My solutions : problem 1: const ageTotal = profile.age + profile.kids[0].age + profile.kids[0].kids[0].age + profile.kids[0].kids[1].age; console.log(ageTotal); Problem 2: function simpleMathProblem() { let number1 = Math.floor(Math.random() * 10); let number2 = Math.floor(Math.random() * 10); if (number1 + number2