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Sir, in current electricity Question 12, when ques say deflection falls from 25 division to 5 division that implies it is 1/5th deflection then can we use formula which you told for nth deflection in galvanometer = S/(S+G) where S is shunt resistance and G is galvanometer resistance. Please tell my thought is correct ?
Sir, in current electricity Question 12, when ques say deflection falls from 25 division to 5 division that implies it is 1/5th deflection then can we use formula which you told for nth deflection in galvanometer = S/(S+G) where S is shunt resistance and G is galvanometer resistance. Please tell my thought is correct ?
Sir, in current electricity Question 12, when ques say deflection falls from 25 division to 5 division that implies it is 1/5th deflection then can we use formula which you told for nth deflection in galvanometer = S/(S+G) where S is shunt resistance and G is galvanometer resistance. Please tell my thought is correct ?
9:35 resistance of ammeter 16:12 meter bridge 20:00 55:20 specific resistance 35:45 asking final temp 40:32 (as v=it and i being const) 53:44 59:57 circuit solving # ammeter is whole resistance box (at 9:35) # in meter bridge, if balanced length is not given from which side, by default take it from left side. 1:05:25 polygon 1:31:01 1:37:19 direction # if loops are perpendicular then find resultant magnetic field (resultant = √2 B) # θ=60° for triangle in octagon θ=45° for triangle in square
My first attempt for jee mains session1 2024 went not so well but above expectations(scored 92 percentile). After boards, I fell a little lazy. Thank you sir for rebuilding the momentum.
Sir kal mera jee mains ka exam h 4th apr 2nd shift....... And now i am realising every jee aspirant need such type of teachers like you..........mujhe abb regret ho rha h....aapka channel mujhe phle mil jata to better ho jata kux......😢❤❤.......but still love your lectures......and style of teaching 🎉❤❤
CONCEPT: 4: ANS THIK AAYA BUT YAAD RKHO KI AMMETER RESISTANCE = NET RESISTANCE 8: RESISTIVITY DEPENDS ONLY ON TEMPRATURE - MATERIAL DEPENDENT QUANTITY 38:11) 17: terminal potential across cell concept 41:18)when measuring across, voltmeter ko direct parralel me put karo 44:19) U&D APPLICATION 45:00) VERY GOOD Qw/ a spin
4:45. 7:01. 8:40. 11:47 14:59 (change in length nikalna h to minus) 18:30 20:33 lenthh doesnt change 21:33 parallel me voltage equal 25:00 again paraller v equal 31:33 again parallel me same voltage 32:49 simple 36:12 calculative 38:20 easy
Sir I'm regret feel ho raha..... Aaj mne itna questions kar liye ,block 1,2 and some 3 but revis krne ka ab time nhi .... Sir aise hi ahar mne har roz padha hota 95+ leke aa jata 2-3week mai hi.... I am dropper 😭... Perso exam ha ... Abhi chemistry start kiya nhi ache se ... Book khogyi meri sache se banyi thi .. and math ka mne kuch nhi kiya ha
revision of current electricity:- 1,6,8(silly),12,16,17(cell,same formula is being used as in question 1),18(when potential then dont use i2rdt),19,21,23.
Sir I got 90, in physics in Jan 29th shift 2, made 2 silly errors. I have been following you from that 3 month check list and attending your advanced course. Just delighted to see Jan 24 solutions, revising these for my boards
i have a doubt. r= ro l/a which can be written as ro l2/v. when length is halved, new r will become r/4 right for each right? so how is it r/2 in q 39:20. what changes would be done if they were in series? Please answer it will help a lot
@@samairamalik3404 In the question a wire is cut from the middle such that the cross sectional area will remain same. That is why when length changes to L/2, this resistance changes to R/2. You can also think, two identical wires if in series has resultant R, then each of the two components must have resistance R/2. If the similar setup was divided such that they were parallel, then each component will have resistance=2R because if you connect them again, they will give back R
7:22 redo 32:21 question samjhne mei dikky 44:39 important question 1:11:29 good theory question 1:17:22 silly error in angle 1:20:20 really goodddd. Formula of dipole moment of B required 1:27:00 silly mistake 1:30:58 the force due to any structural= assume it to be a straight line
moving charges 1:06:00 imp va1riety keep on forgetting square ke andar take equilateral triangle and do 1:14:10 bery easy ques but remember to not do silly mistake while taking d it will be d/2 at P between two parallel/anti-parallel wires 1:26:27 take 45degree always better to draw diagram even tho direction not asked 1:28:40 similar to 1st ques
5 days ago Started from zero watched formula marathon and started solving 2024 for confidence . completed nearly 220/300 questions from 2024 jan attempt . Thanks mohit sir aapne bacha liya aur mera confidence ab next level pe h . Hatts of to you
01:05:17 the solution to this question has a specific formula for direct answer. the formula goes like- B= [(mu naught × no. of sides × current) ÷ 2π × length of one side] × tan (π/no. of sides) quite non understandable here😅 but will definitely help you if it comes in your shift🤗
↪MOVING CHARGES 🛡NOTES: NIAB=Ctheta , C=NIAB/theta, R=MV/QB, F=Q(V*B), F=qVB, F=ILB, REV QUESN 6 1:18:05 semicircle formula Bnet=meuonotI/4🔑 7 1::19:44 formula based🔑 12 1:28:17 do again⚙ 15 1:37:21 do again⚙ 16 1:41:11 do again⚙ khela hi khatam has a separate fan base😂😅😂😂🥰😇
2:00 ideal voltmeter 11:10 shunt ke R ko ammeter ka R samjhne ki galti 23:40 no overthinking 25:45 30:45 rev 32:20 overthinking avoid 34:00 44:00 error 44:40 good ques 56:00
i have a doubt. r= ro l/a which can be written as ro l2/v. when length is halved, new r will become r/4 right for each right? so how is it r/2 in q 39:20. what changes would be done if they were in series? Please answer it will help a lot
No, sir is right in this question when the wire is cut into two half parts then resistance of both wire will also be half........ Then their equivalent resistance will be r/4
@@samairamalik3404let's assume aapke paas ek wire hai jiski total resistance R hai agar aap usko 2 half parts me cut kar deti ho toh unki resistance R/2 and R/2 ho jayegi clear......... When you try to find out their equivalent then it will be R/4
@@Purva874 bhai hmne thodi bola tha nta walon ko easy paper dalne ko toh hmari kya glti hai...............mein itni mehnat se 203 marks laya tha aur meri siraf 97.4%ile bni .....ab mein kahan jaun .....2nd attempt ke liye bhi padhne ka maan nhi kar rha 😓
11:16 resistance of ammeter mean R eff of shunt and Rg 13:35 shunting mean parallel meh lagaya 14:42 read qn properly da change in balance is asked 39:21 when put in parallel voltage stays same so use voltage formula rather than current formula of power 56:31 in meter bridge probs only lengths matter (fk area and resistivity)
Thx sir is baar physics 1 st attempt me mera 16 percentile aya tha physics is bar me app se consistent effort marunga or is ko 99 percentile me convert karunga
So far completed: 1. KTG 2. THERMODYNAMICS 3. CURRENT ELECTRICITY 4. MAGNETIC PROPERTIES OF MATTER AND MAGNETIC CURRENT 5. SEMICONDUCTOR 6. MODERN PHYSICS 7. EMI 8. AC. THANK YOU SO MUCH SIR ❤LOADS OF LOVE AND RESPECT ❤️. sara aapse solve kiye hai question itna achha explain krte hai aap 😊
Electrostatics Capacitor Current electricity Magnetic effect of electric current Modern physics Semiconductor Kinematics Nlm Wpe Thermodynamics Gravitation ❤completed sir from 2020 to 2024
2,4,5(shunt mtlb parallel mai lgana),11(only question lang.) ,12(not done yet),16 - mai final temp. nikkaalna hai , 21(done but good question),22,25(got answr but sir ne jo circuit o break iya hai) magnetism - 1(6 se multiply krna b hul gya), 8,
one thing that I have noticed is that nta doesn't give a clear response of question asked...like in CE question 5 they said to shunt the unknown resistance with 2 ohm but didn't clarified whether to place another identical one with 2 ohm or to shunt the given unknown in the circuit with it... So this is very much frustrating for me... Even CBSE and Advanced gives a very clear depiction of what is asked,NTA should work on this loophole..
1:13:21 sir u wont believe, how pathetic solutions had been given by my coaching and google as well. definitely never recommending someone to go for any other source of pyqs. your channel is simply the best for this.
Earlier when i came to know that pyqs are being done by a channel named eduniti i was like how now this channel will be but now after my every search I type '''by eduniti '''❤
i have a doubt. r= ro l/a which can be written as ro l2/v. when length is halved, new r will become r/4 right for each right? so how is it r/2 in q 39:20. what changes would be done if they were in series? Please answer it will help a lot
QUESTIONS TO REVISE CURRENT ELECTRICITY 3:00 12:52 SPECIFIC RESITANCE = RESISTIVITY AND IT DEPENDS ONLY ON TEMPERATURE 39:24 54:00 MUST TAKE CARE OF SHORT CIRCUIT 55:30 58:23 MAGNETIC 1:11:32 1:32:31 DEKHO SIR NE KAISE WO SEMICIRCULAR KI WAJAH SE FIELD NIKAL LI
Current 1 thoda confusing lga 4 bn gya but resistance of ammeter puchha tha ye dhyan nhi tha kewal shunt nikal diye 12 exam me bhi nhi bna tha 16 good question 18 repeat 23 resistance per cm mtlb resistivity 24 repeat
For revision 2:49 5:54 (galvanometer problem 🙂) 9:08 (galvanometer problem 🙂) 12:34 (meter bridge 🥲) 16:27 (meter bridge 🥲) 24:15 (gal..... Problem) 25:59 (") In mock 28:40 39:06 to end
❤Resistance of ammeter and shunt resistance ARE NOT the same. Parallel resistance formula use crow to find ammeter ka resistance ❤changes by means final minus initial 😅 19:49 silly mistake. 40:44 got stuck 43:43 imp und 46:47 equivalent resistance write properly 53:49 56:27 resistance per cm is resitivity 57:58 power is illumination 1:06:47 check crow formula 1:11:49 concept 1:16:21 just see 1:17:45 formula 1:19:57 formulae 😅 1:26:06 imp 1:31:09 imp 1:38:04 imp q
Maja aagya sir got 39 correct , 1 incorrect and 1 silly mistake ❤❤❤ in the first attempt i got 71 marks in physics and i had made 5 silly mistakes😢 now i am aiming 100 percentile in physics in session 2 sir. Bless us sir ❣️❣️❣️
1:43:40 I was feeling very ashamed😢 bcoz of boards i was not able to attend your daily sessions of 2024 pyqs But now I completed all of them ,we will be always supporting u sir 😊
i have a doubt. r= ro l/a which can be written as ro l2/v. when length is halved, new r will become r/4 right for each right? so how is it r/2 in q 39:20. what changes would be done if they were in series? Please answer it will help a lot
Bro pehle ek resistor tha jiska resistance R tha, then usko Kaat diya gaya ab do resistor hogaya of R/2 resistance each and Isko parallel me kr diya gaya so Req = R/4 Agar series me hota to R/2+R/2 = R only yani overall koi change aata nhi agar v^2/R me put krte to kyuki R to ab R hi hai koi change hai nhi isme@@samairamalik3404
2:56 easy but repeat 5:10 ammeter 9:31 ammeter 23:18 ez but ammeter 26:25 good ques 30:29 very ez but look at the approach he does it with 37:00 again ez but look at approach
40:31 good ques look at approach 53:50 short circuit concept ez but repeat 55:12 BEVERY CAREFUL it says resitance per cm i.e RESISTIVITY balancing length is independent of resistivity so it remains unchanged
4:44 i have started this chap now in drop year straight with pyq so my marked ques will be more 7:03 10:18 14:57 yhi glti ki thi exam me 20:44 easy 23:26 23:26 26:07 28:17 30:33 34:04 37:00 41:32 44:35 59:48 1:00:21
52:11 .... calculation mein kho gyaa 43:18 ....Aisa mistake kaun kaise kar sakte ....sirf main hi aisa mistake kar sakta hu 😂😂😂😂 21:36 ...wah mere sher wah....yeh kaise kar diya 22/25 😢 magnetic effects of currents 1:20:37 ...wrong formula applied 1:40:29 ....although i did correct, still do it....because its a good question
current elec Q1 Q2 Q4 concept Q5 Q8 resistivity is material property Q14 redo Q19 Q21 mug this up Q23 balancing length is independent of resistivity Q24 repeat, use P = i^2R in this lamp question done revised 5:03 am 18;3;24
Current done. Doubt Q1 E-ir. Q4 Q5meter bridge good question (shunting means in parallel) Q12 galvo Q14 parallel me volt same Q16 Rf = Ri(1 + alpha deltaT) Q17 E+ir Q19 voltmeter
4:02 saare series me kyuki sb opp polarity se jude hai and v=e- ir lagaya, bade dande se nikal reha toh e-ir 27:29 good quesn 31:34 basic knowledge hai prr dimag lagao 36:24 37:43 current direction 39:40 42:05 i hate this quesn but gotta do wat i gotta do 58:52 illumination of lamp is power only yr 1:02:14 very easily done by sir
