Тёмный
No video :(

JEE Main PYQ Function 30 January 23 (2) 

Sanjeev Sir
Подписаться 7 тыс.
Просмотров 30 тыс.
50% 1

Опубликовано:

 

4 сен 2024

Поделиться:

Ссылка:

Скачать:

Готовим ссылку...

Добавить в:

Мой плейлист
Посмотреть позже
Комментарии : 33   
@jyotishka
@jyotishka Месяц назад
In objective questions always try to use some short intuitive checks. Realizing that the domain is [-2,3] , check the value at the end points which is sqrt(5).Hence probably the correct choice is either (b) or (d). Next, equate the two radicals i.e. 3-x=2+x which gives x=0.5 which is a likely inflection point. This may not always be true but worth a check. Value at 0.5 is sqrt(10). Since this is one of the option hence you are pretty sure that's the answer. I use to do these tricks to quickly solve objectives when I cracked JEE in 1998.
@parthasarathirout6286
@parthasarathirout6286 Месяц назад
🙏asm....Give some more tips and trick for math
@surendrakverma555
@surendrakverma555 3 месяца назад
Excellent explanation Sir. Thanks and Regards
@mathematikawizard7787
@mathematikawizard7787 21 день назад
Sq.rt of ( x - a ) + Sq.rt of ( b - x ) is Minimum at boundaries of domain & Maximum at mid point of domain interval ..
@rohitsharma-uv6og
@rohitsharma-uv6og Месяц назад
Sum of two square roots cant be a prime number inside square unless one of the roots become zero, so by observation option D is the correct answer. For eg. √x+√y cant be √z where z is a prime number , unless either x is zero or y is zero
@DeepakKumar-sp1ph
@DeepakKumar-sp1ph Месяц назад
Sir aapko starting me positive nahi non-negative bolna chahiye
@harsh.mscrm991
@harsh.mscrm991 3 месяца назад
thank you
@daatphoklagaming6796
@daatphoklagaming6796 4 часа назад
Sir yeah too mera shift que the. jee ke yaad aa gaya
@HarmeetSingh-ou1eh
@HarmeetSingh-ou1eh Месяц назад
Just squaring both side and min value is when the root term is zero and max when the root term is max check via differentiate
@sanjaypandey3642
@sanjaypandey3642 3 месяца назад
Good morning sir , I am Anant dev student of class 12th F I liked your explanation a lot, Thank you sir
@sanjeevsir29077
@sanjeevsir29077 3 месяца назад
Thanks
@hvkeee
@hvkeee 14 дней назад
Super sir explana❤
@SakshiShreya-rr2mr
@SakshiShreya-rr2mr 3 месяца назад
Sir I am in class 10th now, a fiitjee student but I can understand the explaination of the question very well and also able to solve it by 1st method🙏🙏🙏
@Princesingh0004
@Princesingh0004 3 месяца назад
Bro I am in 10th class, I am not able to join any coaching because financial condition 😞. Can you pls send me modules of your coaching. Pls 🙏
@adityadas5934
@adityadas5934 3 месяца назад
​@@Princesingh0004 bro I will suggest u best RU-vid channel to study 😢 and app to
@mentosgamer1994
@mentosgamer1994 Месяц назад
Bhai mohit tyagi sir ke lectures dekhlo iit pakka h ❤​@@Princesingh0004
@preetchauhan1612
@preetchauhan1612 Месяц назад
Which centre....
@aditya-u7s9v
@aditya-u7s9v 3 месяца назад
Nice solution,but the question is trivialised by the Cauchy Schwartz inequality
@dakshgaming1037
@dakshgaming1037 3 месяца назад
Great explanation sir ❤️
@user-cu8vj8lt3g
@user-cu8vj8lt3g Месяц назад
Sir use differentiation it can solve fast
@hypertejas.p4110
@hypertejas.p4110 Месяц назад
Sir in second method differentiation is wrong... You forgot 2 in denominator in 1/√2+x.... But answer is still right how?
@vdisonair3668
@vdisonair3668 Месяц назад
Yeah….because 2 comes in the denominator but the lcm would be the same and also denominator is playing no role for giving critical points
@LaughingKing40
@LaughingKing40 2 месяца назад
Sir wavy curve mhi laga sakte kya
@Arpd94
@Arpd94 3 месяца назад
Sir aap maths ke eduniti ban jao 😂
@ravisankar8259
@ravisankar8259 3 месяца назад
How did you arrive at conclusion, sir, that the minimum is only at -2 or 3?
@MaheshKumar-lx1ku
@MaheshKumar-lx1ku 3 месяца назад
😂😂😂 because function is defined between-2 and 3 only
@MaheshKumar-lx1ku
@MaheshKumar-lx1ku 3 месяца назад
In Which standard u are
@goodvibez9415
@goodvibez9415 Месяц назад
Function has the addition of two square roots Square roots can never be negative so therefore we took 3 - x >_ 0 2 + x >_ 0 as the square root can be zero hence functioned is defined between -2 and 3 Im a 11th grader forgive me for any wrong logic
@adityasarraf3843
@adityasarraf3843 Месяц назад
Sir by using AM GM inequality the minima is coming as root 10 what's wrong here?
@sanjeevsir29077
@sanjeevsir29077 Месяц назад
@@adityasarraf3843 please keep in mind domain also
@adityasarraf3843
@adityasarraf3843 Месяц назад
@@sanjeevsir29077 sir the minima is coming on x=1/2 (using AM GM inequality) which is right well in domain)
@user-cu8vj8lt3g
@user-cu8vj8lt3g Месяц назад
Sahi hai bhai differentiation se bhi aa raha hai
@INSTASHORTS-jh1pc
@INSTASHORTS-jh1pc 3 месяца назад
Далее
Паук
01:01
Просмотров 2,4 млн
when you have plan B 😂
00:11
Просмотров 3,1 млн
JEE Main PYQ Function 25 July 2023 Shift 2
10:01
Просмотров 3,2 тыс.
Multiple times repeated in IIT, JEE Main, MIT
11:12
Просмотров 147 тыс.
JEE Main PYQ Function 7 May 2012
7:54
Просмотров 2,2 тыс.
USA Nice Olympiad Exponential Equation | Solve for X
6:38
IIT JEE advanced PYQ 2024 Paper 2
6:54
Просмотров 123 тыс.
Паук
01:01
Просмотров 2,4 млн