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.join() method in python | Lec-20

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In this video, I have talked about the fundamentals of programming and Python. If you complete this, you will be well-versed in using tuples for different use cases.
Directly connect with me at:- topmate.io/man...
Q1. Secure the PII data.
Input = ["mverma6250@gmail.com","ramesh02@hotmail.com",
"sohansingh@gmail.com","swatirahane@outlook.com"]
Input = ["m********0@gmail.com","r******2@hotmail.com",
"s********h@gmail.com","s*********e@outlook.com"]
Q2. Print the list of all unique ip addresses?
Input:-
["/region//us-east-a/north/resource/vminsatnce/subsid/ae-456-df/server/10.168.155.2",
"/region//us-east-b/north/resource/vminsatnce/subsid/ae-456-df/server/10.168.156.2",
"/region//us-east-c/north/resource/vminsatnce/subsid/ae-456-df/server/10.168.151.2",
"/region/japan/north/resource/vminsatnce/subsid/ae-456-df/server/10.168.155.22",
"/region/india/north/resource/vminsatnce/subsid/ae-456-df/server/10.168.167.2",
"/region//us-east-a/north/resource/vminsatnce/subsid/ae-456-df/server/10.168.179.28",
"/region//us-east-b/north/resource/vminsatnce/subsid/ae-456-df/server/10.168.155.31",
"/region//us-east-c/north/resource/vminsatnce/subsid/ae-456-df/server/10.168.151.2"
]
Output:- ["10.168.155.2","10.168.156.2","10.168.151.2"
"10.168.155.22","10.168.167.2",
"10.168.179.28","10.168.155.31" ]
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29 авг 2024

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Комментарии : 18

@AnuragRaut-ry2oq 2 месяца назад

Sol 2: ip = [] for i in input: parts = i.split('/') ip_address = parts[-1] ip.append(ip_address) print(ip)

@pravinnadar3275 3 месяца назад

Q1: Without any inbuilt function result_email = [] for i in email: temp = i[0] for x in range(1,len(i)): if i[x+1] == '@': temp += i[x:] result_email.append(temp) break else: temp += "*" print(result_email)

@home5871 4 месяца назад

Bhaiyya teach and guide us python only needed for data engineering plzzz

@MukeshKumarBehera-cb1pv 4 месяца назад

Q2. Solution s1=set() pattern=r'\b(?:\d{1,3}\.){3}\d{1,3}\b' for ch in l1: filtered=re.findall(pattern,ch) s1.update(filtered) print(list(s1))

@manishagarwal6780 4 месяца назад

Q1 soln: sec_data=[] for mail in piid: last_index=mail.index('@') replacement_str='*' * last_index mail=mail.replace(mail[1:last_index-1],replacement_str,1) sec_data.append(mail) print(sec_data)

@ShekharBhide 2 месяца назад

I have one doubt In SQL query correct format is below state= 'bihar' and department= 'IT' in you case its state = bihar without ' ' qoute I think its not valid query

@abhijeetsinghbatra8143 8 дней назад

This should help with that dr.append(f'{key} = "{value}"')

@AkhilVlogs2000 4 месяца назад

soln 2 ip_addresses=[] for input_str in input: parts=input_str.split('/') ip_address=parts[-1] ip_addresses.append(ip_address) print(ip_addresses)

@kushchakraborty8013 4 месяца назад

Guru Ji, thank you a lot for this explanation. Ek sawal tha boss, interviews de toh raha huun and Spark,PySpark vagera sab ke jawab theek se de pa raha huun but SQL dikat ban raha hai, Kabhi kabhi complex querry likh ne ko bolte hai kabhi kabhi seedha table de dete hai aur bole joins perform karo. SQL aur Querry likh ne ke toh production experience hai nhai, zara resources suggest karo na jisse SQL mai aacha kar sake

@manish_kumar_1 4 месяца назад

Baat production me code likhne ka nhi aapke confidence ka hai. Aap leet code ke database questions solve kijiye. Confidence aa jayega

@MukeshKumarBehera-cb1pv 4 месяца назад

Manish Bhaiya , Can you please make a detailed videos on regular expression ?

@manish_kumar_1 4 месяца назад

Sure

@manishagarwal6780 4 месяца назад

ans_li=set([i.split("/")[-1] for i in lis]) print(ans_li)

@vinu11sharma 4 месяца назад

@manish_kumar_1 result not match This is our result:- AND state=Bihar OR department=IT OR state=Delhi OR department=Marketing Expected result: AND state='Bihar' OR department='IT' OR state='Delhi' OR department='Marketing' Value should be under ' '

@manish_kumar_1 4 месяца назад

Yes you are right. Mistake ho gaya hai. Aap code ko accordingly change Kar lijiyega

@vinu11sharma 16 дней назад

@@manish_kumar_1 final_condation = [] for i in state_dept_info: for key,value in i.items(): final_condation.append(f"{key}='{value}'") print(final_condation) final_condation = " OR ".join(final_condation) print(final_condation) final_query = query + " AND (" + final_condation + ")" print(final_query)