Keto Enol Tautomerism - Acidic & Basic Conditions 

isko dekhne ke baad tu air 1 aur main air 2 😁

air 1,2 k liye practice bahut chaihe bhai but concept wise ye channel really acha smjha rha h @@yaminyaminyaminn

Kya hua Bhai kitne number aaye,plz reply

Main bhi prepare ho rha hu jee ke liye is channel se this guy is far more better than others,he is providing free content 😅

😂😂😂😂

which exam.. !! NEET?

@@ipshita792 not likely he is not an Indian

Bro failed

​@@cashboys-j9m 😂 lol

did you pass the exam?

whether u passed bro

you passed bro?

Guys, I passed. GOOD LUCK EVERYONE

May I know that why acetone is much more stable than it's enol form??

YES SIR HE IS THE GOAT

Coreect

😘😘😘

India

Is phenol shows ketoenoltautomer

OMG YES!!

Yeah!!!

yes due to resonance (conjugation) and also due to a hydrogen bond between the keto and enol group. The keto-enol tautomer has 76% appearance. I think he made a little mistake there.

Bond energy(C=O) >Bond energy(C-O) This makes keto form more stable as compared to enolic form.

@Nissipriya Anandhakrishnan Energy is inversely related to stability . More energy in a substance,the less stable it is.😄

Might be,Enols form enolate ion where the -ve charge on oxygen atom made it reactive towards a reaction,destabilising the enol structure..

@Nissipriya Anandhakrishnan he means bond dissociation enthalpy ( which is basically the energy required to break a bond) more energy is required to break a strong bond like c=o as compared to the c=c bond hence in most cases (not every case)the keto form is more stable than the enol form

@@chitranshjawere4953 yeah but he is referring to bond dissociation energy which is negative so what more in magnitude is lesser You get the point right but your statement is correct stability and energy arr inversely related

Because a carbon-oxygen double bond (ketone) is more stable than a carbon-carbon double bond (enol).

@@metroidfan77yes65 but why that c double bond carbon is more stable than c double bond oxygen? I cannot relate this point as my teacher also has told the same

I guess it's because of the electronegativity difference. There is a partial negative charge on O and a partial positive charge on C.

@@metroidfan77yes65 ohk thanks

I laughed for a second and then thought ......he is joking right? Are you?

Good question Stability means the tendency to resist any change in structure due to external force

After the reaction you find the H3O+ in the same form as it was before the rxn, so even though it is used in the reaction, it isn't consumed permanently and you get is back in it's original form so basically it is used to speed up the process, and that is the definition of catalysts: they are the substance that increases the rate of a reaction without itself being consumed. we get them back in the final product. i might be wrong since i'm also a student.

​@@ihaveagoal4665 U are correct ! The amount of h30+ used for reaction is gotten back after the reaction so it can be cancelled out as being on reactant side of first reaction and on product side of second while practically performing experiments it always seems that the h30+(or anything else in similar situation) isn't even used and just acted as a catalyst

I always play his videos at 1.25 or 1.5 speed. I hope this helps

This is exactly why people can't have nice things.

it doesn't matter the time all the matter is that you are understanding the mechanism ,well I do not feel that the professor is in hurry all he is care about that we are receiving the information correctly