Kirchhoff's Rules (4 of 4) Circuit Analysis, Example No. 3 

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I understand it great!! thank you. But how is this applicable in designing the circuit? If you have to design how many ohms each resistor should be and what voltages, how many voltages, how would you start? Or is this only to figure out existing circuits only?

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thank you so much for this video , it really helped alot and i have one question witch kind of out of the subject maybe :) what program do you use to draw the circuit and put all those number and sighns ? thank you again

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for Loop3, for 40v source it shoudld be negative as the loop is going from +ve to -ve .. please check

Hello, I am a university student in the department of physics. How can I be very smart and expert in electricity?

What happens if you assumption for the direction of I4 was wrong? How would you know?

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Hello, i hope you answer my question. When i write equation for loop im very confused to "+" and "-" i still dont know i will write negative value or positive value

Hey would appreciate if you could let me know what software you used. Couldn 't find it in your description.

Thanks for making this awesome vid!!! I have a question on this example, hope u could answer me,thx! Could I change the direction of the current of Loop 3 which becomes anti-clockwise, it gives different value of i2. which is 4(i2)+40+3(8)=0, i2=-16. THANKS so much!

Hello! Is it possible to get a zero current in one of the junctions of a multi loop circuit?

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Very well explained, much thanks :) I'm wondering, is it possible to calculate currents in this kind of circuit without using Kirchoff's loops?

Thank you

I have big problems analysing the nodes and currents, ive seen your video about the analyse part (really good) but when theres more than two nodes it confuses me. Do you have any tips?

Is Kirchhoff's Rules Suitable for capacitors? How can we solve complicated circuits with capacitors? if in this example No 3 above we replace all resistances with capacitors what method we need to apply in order to solve it?

In the L3 equation you chose the V to be positive could you please expliane what is the different between the V in L3 and the V in L2?

My teacher used the same problem, but she did not say that I4 has a given of 3A. Can you tell me how to get the 3A? Is there a way to solve for that?

Hey i really liked your video. I'm an EE major and I love the way you teach but I noticed something wrong with the I5 current in the example. The I5 current should be 7 not -15 because 11-4 is 7 and subsequently the I6 current should be 10. I still love your videos nonetheless ❤

Thanks man

Sir Iam a first year chemical engineering student which website is good for reference please reply

Awesomre work

amazing

I4 is given 3A and you choose the direction arbitrarily. what if the direction of I4 u choose was wrong? How would u know!?

Please put another example a little bit of complex.

If the problem was to give us I1 instead of I4, would we still be able to solve this way?

Allah apko ajar de .. amin

I've seen some other people solving diagrams with three loops expressing I4, I5, and I6 expressing as sums of I1, I2, and I3 like Jesse Mason, how am I gonna do that in this diagram?

Confused: in video 3 in the addition 3,2 becomes 4,2 by adding both sides (1I2 + 3.2I2), in this example -4I2 stays -4, you don't add 1I2 to -4I2 in L3. ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-8gGEmrbURsA.html, and I1in L1 ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-8gGEmrbURsA.html. I don't get why in video 3 a 1 is added and not here. Sorry for the stupid question, i'm probably missing something.

is there any rules for choosing the Loop directions? or I can choose any direction I like? thanks.

Little quick, but I’m beginning to catch on! 😊

life savior!

Thnks 🙏❤️

I dont understand. You said the loop direction is arbitrary, thus if the resistance go against the current -> positive charge. But when it comes to battery, it look like the direction of the loop doesn't matter? - when go from neg to pos, it is pos sign??????

Can't thank you enough.