LADDER FRICTION SOLVED PROBLEM 1 IN ENGINEERING MECHANICS IN HINDI  

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Shandar Dil jit liye

Step 1. *Free body diagram.* Step 2. *Equilibrium:* {B. Σf(x)=0; Σf(y)=0 A. Resolve inclined forces into their components along x and y axes. C. F in “→”, “↑” direction = +ve, &, F in “←”, “↓” direction = -ve D. ΣMx = 0; ΣMy = 0; i.e. sum of moments = 0. Moment = Force × ⊥ distance w.r.t a point. Also = Component of Force ⊥ to the distance from that point. Any Force F passing through that point during finding moment w.r.t that point = 0. So, always take moment w.r.t a point which makes maximum number of Forces 0.} Step 3. *Formula of Friction:* { *F = μR* , where μ is the coefficient of friction which is the ratio of the force of friction F to the normal force R, F/R. F always acts opposite to the motion of the body and along the surface. Angle of friction is the angle between the resultant R' (say) of F and R with respect to R, denoted by φ. hence *μ = tan⁻¹(φ)* } Step 4. Lami's Theorem: { *When three forces (T1, T2, T3 acting at a point P are in equilibrium, then each force is proportional to the sine of the opposite angles (A, B, C respectively) to that force in that system* The forces must be in same plane, and they all must be in same direction otherwise this theorem is not applicable. *T1/sin(A) = T2/sin(B) = T3/sin(B)* } Step 5. *Resultant of Friction:* {The resultant R' (say) is the resultant of the Frictional force F & the normal force acting ⊥ to the surface against the weight, R. It can be used to solve Wedge problems when angle of friction is given it makes it easier to solve, also Lamis theorem might be applied too, (read step 3 and step 4)}.

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30 minutes of explanation is huge for this question

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love from amritapuri

ayenga ayenga kr kr aap bhut achha samjhate ho

Love from Bangladesh, Sir.

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A ladder of 5m length is supported against a rough wall at angle Q(theta) with the floor the coefficient friction at Wall and floor is 0.2 if the weight of the ladder is W and acts as a center of the ladder find the angle Q(theta) with the floor when the ladder is at point of slipping

Good

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Sir which force is responsible for slipping of the ladder as there is no force in right direction and wall's normal give a torque to the upper side of the ladder so which force act towards right at the bottom of the ladder for slip.

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You could have resolved weight horizontally and vertically in terms of angel.

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Sir hume angle nikalne ke liye point B par hi moment lena hoga ya fir point A par moment laga ke bhi sahi answer (angle theta) aayega ?

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Excellent concept clarity Thank you sir

a 5 metre long ladder is resting on a smooth vertical wall with it is lower end 3 m from the wall what should be the coefficient of friction between the ladder and the floor for equilibrium .

Sir clockwise moment is negative and anticlockwise positive liya to chalega kya?

Sir ji iska solution btao plz Ladder is resting on a horizontal floor leaves against a vertical wall at an angle 60 degree with the floor. If the coefficient of friction is 0.25 at the wall and the floor, what percentage of length of ladder a person can asend without causing the ladder slip? Neglect the weight of ladder.

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Sir wedge friction par problems kab daloge

Sir mene padha hai ki clockwise negative aur anti clockwise positive hota hai

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sir confused while taking normal reaction direction....?when ladder goes beyond the wall...please make its video

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Sir can you please make a video on virtual work topic?

Belt friction concept is needed please🙏