Limits - Free Formula Sheet: bit.ly/3T3dD2X Final Exams and Video Playlists: www.video-tutor.net/ Full-Length Videos & Worksheets: www.patreon.com/MathScienceTutor/collections Next Video: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-fml0-ELYLaE.html
I just want to say how much you've been a life-saver for all of my academic career. I've been watching you since middle school and I'm currently in my third year of my computer engineering degree, due to graduate next semester. The thing is - I have extremely bad ADHD and CANNOT pay attention in math lectures no matter how hard I try. The whole reason I'm even here now is because I KNOW exactly what I'm going to do after, and sometimes even during, each and every math class. "Organic Chem tutor..." is at the start of over half of my RU-vid searches. Something about your voice, the down-to-earth vibe, the colors, the dozens of examples - you just *make* it make sense. You are THE "it" girl in my eyes and I can't thank you enough.
You're a legend!... You explained it very clear, word by word... Thanks a lot for sharing knowledge and helping me out to understand mathematics easily
I really appreciate you Sir for your immense help to all our maths needs... You've also inspired me to make my own channel.. I've uploaded some more questions which could also help those looking here for help
4:33 Calc teacher always told us to just take the square root of the normal x. So just do (sqrt(x)-4)*(sqrt(x)+4) and then you can cancel out the sqrt(x)-4s. A lot easier and less confusing.
Taught me limits in 15 minutes while I sat clueless in class for 50 minutes coming away from nothing. If this doesn't describe you, I don't know what will
Been two years since I had decent lessons cause all we did are modules which are not really effective. Now my ass self decided to major in engineering lol. Big help Kuya. Thank u!
He multiplied by 3/3 so that he could manipulate the function to look like a function that we know the limit of. You can always multiply a function by a form of one like 3/3, (right, 3 divided by 3 is 1), and so by multiplying by 3/3, he can then have 3x in the denominator with sin(3x) so that he can say that the limit of sin(3x)/3x is 1. If this isn't making sense, I explain this much better that I did in this comment in my own video on this topic that I will link for you here. Hopefully this can help you understand! Link: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-KodmvDyGZpI.html
At 10 minutes and 30 seconds, the problem asks you to find the horizontal asymptote using limits. I don't understand how this is any different from finding the horizontal asymptotes without using limits it seems like the answer is 9 regardless of which method you use and the method is very similar to the algebraic method as well. Why does calculus teach a new method that is already taught in algebra regarding horizontal asymptotes?
In question 8 if we'd have multiplied and divided the equation with (1/x) that way everything will become 1 and then when x approaches to 0 answer should have been 1 I am.just confused
i keep getting c=5 for the last question. I used my own method and combined the like terms and then divided after the "x" values were on one side. i keep getting "3c=15" which simplifies into "c=5". Any ideas as to what im doing wrong?
#1.49 - decomposition is not performed correctly. should be performed x1 + x2 = −p, x1 · x2 = q substitute 5 in the numerator - 0, will not work. Correct: (-5) and 3
@@carlospereyra6144 Well the creator gets paid for having an advertisement displayed at all, so they do get money that way. I'm not sure if advertisement clicks help but it makes sense if they do
Referring to problem no.6, Are there specific conditions to be able to do the one when you put 3/3 after 1/5x ? or am I missing smth? I really don't get that part. tysm
I have been incredibly lost in my calculus class for (3) weeks now…..my first exam is Monday and until now, I had no clue how I was going to pass. Thank you! Truly!
I always watch your videos but never leave any comments. But today I decided to do so. Just thank you for your clear explanations, I don't know what would i do if there were not your videos!
Q.8 sir,I guess the answer may be 1 not 0 because xsin1/x =(sin1/x)/1/x , i,e sina/a which is 1 when the value of a is small Or a--->0 And yeah I love your voice