A line AB contains a point C on it such that the ratio of the distance of the CB:AC is 2:1. The end A is 20 mm above H.P. and it is in 1st quadrant. And the other end B is in V.P. The point C is 35 mm above H.P. The line is inclined with the H.P. at an angle 30°. The elevation length of the line AB is 70 mm. Draw the projections of the line AB.
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Sir in the question it is written line inclined to hp and vp is 30 and 60 degree, but in 2d drawing you are taking opposite angle ie 60degree to hp and 30 degree to vp . Why not according to question.
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Sir if lines PQ. Plies in 4th quadrant and Q lies in 2nd quadrant and theta+phi=90. Then what we should we do if measurements of P from HP and VP are given
hi sir, i have been struggling to solve a problem on logarithmic spirals. The data given is 40 degrees vector angle and length of vectors are 18mm and 25mm. Can u help me in solving this problem...Thanks
A line AB contains a point C on it such that the ratio of the distance of the CB:AC is 2:1. The end A is 20 mm above H.P. and it is in 1st quadrant. And the other end B is in V.P. The point C is 35 mm above H.P. The line is inclined with the H.P. at an angle 30°. The elevation length of the line AB is 70 mm. Draw the projections of the line AB.
A line AB contains a point C on it such that the ratio of the distance of the CB:AC is 2:1. The end A is 20 mm above H.P. and it is in 1st quadrant. And the other end B is in V.P. The point C is 35 mm above H.P. The line is inclined with the H.P. at an angle 30°. The elevation length of the line AB is 70 mm. Draw the projections of the line AB.
A line AB contains a point C on it such that the ratio of the distance of the CB:AC is 2:1. The end A is 20 mm above H.P. and it is in 1st quadrant. And the other end B is in V.P. The point C is 35 mm above H.P. The line is inclined with the H.P. at an angle 30°. The elevation length of the line AB is 70 mm. Draw the projections of the line AB.
