33:15 there are 2 ways to find it 1) in a triangle sum of all angles is 180 90 + 36 + x = 180 126 + x = 180 x = 180-126 = 54 2) Angles on straight line x + 36 + 90 = 180 x + 126 = 180 x = 180 - 126 x = 54
35:59 Sir we can also find it out as angle TSR is equal to angle SRA and angle QRA is 70 degress so angle QRS will be equal to 130 degrees - 70 degrees so angle QRS will come out to be 60 degrees
hi bro your answer is correct but the reason will not be alt. interior angle but it will be linear pair your answer is correct but the reason is not I just wanted to tell u 👍
Sir 54 degree because those angles are forming linear pair on a straight line so, the sum of two angles on a straight line is 180 degree and 180-126 we get 54
19:45 Sir iss question me hamare teacher ne aisa sikhaya hai In angle SOQ AngleSOQ= angle SOR+ angle ROS----------> (1) In angle POR Angle POR= Angle SOR + POS------------> (2) Adding (1) nd (2) Angle SOQ + angle POR= 2angle SOR +angle ROQ + angle POS Angle SOQ+90°= 2angke SOR + 90° + POS SOQ=2SOR or ROS+ POS (90° is cut) 2ROS=SOQ - POS ( turning LHS nd RHS) ROS=½(SOQ-POS) It was kinda difficult but i somehow leatned it ❤️
Doubt :Sir 4th question ka answer scl walo ka kuch alag hai aapka alag hai hmm aapke wale trike se b krrr skte hai na plzz reply ❤aapke trika bhot easy hai ❤
33:21 Contruction(draw AB parallel to PQ) AngleSRB+TSR(130°)=180°(co-interior angles) AngleSRB=50° IIILY AngleQRA=70° And angleQRS+QRA(70+SRB(50)=180°(anle on straight line) So angle QRS=60°[180-(70+50)] SO LENGTHY
Given - AB PARALLEL TO CD EF PERPENDICULAR TO CD AND ANGLE GED=126° GED=GEF +FGE 126=GEF+90° GEF=126-90 GEF=36 AGE=GED(ALT INT ANGLES) FGE+AGE=180°(LINEAR PAIR) FGE=180-126 FGE=54° SO AGE=126 GEF=36 FGE=54 Hence proved