I'm an Air Craft mechanic and I must compliment you sir you are an exultant teacher thank you very much for making a com-plated subject easy for my students to understand they caught on the first tine with you after many attempts by my method failed
Thanks man very helpful video. You earned yourself a subscriber. I've been asked a question in a assignment and it goes like: Using LM317, design an adjustable voltage regulator with Output voltage: 5 to 12 V and Output Current: 1A. By this video I can figure out the voltage part, but how to fix the output current to 1A? It would be very helpful if you reply as early as possible.
I appreciate your job . But one is mendatory : you always should add component constrain first .Even I don't know this circuit will use at 12000 volt or 12volt . If I check data sheet I think I can get better idea . I am checking youtube cause I don't have much time to do it academically.
For maximum reliability keep the dropout voltage across the regulator at about 3v to 5v at 1.5 amp. A finned rail type heatsink will be called for (some have a H cross section labelled with a BW suffix). There's also the Low Dropout LD1086 regulator which do come in fixed 3.3v and 5v output versions.
LM317 VOLTAGE REGULATOR is supposed to have a minimum current output of 1.5A. what does it mean? I am only familiar with the idea of max current output. With this minimum current will it be safe to use this for replacing AA batteries in a wall clock?
It is actually called linear variable voltage regulator dude. The word "linear" has something to do with the output voltage and it desipate heat due to the dropout voltage...
1v is unfortunately below the minimum 1.25v reference level for the 317 regulator ic. Could use further reduction diodes on the output utilizing the diode voltage drop as a shunt regulator. Try using a ordinary diode with a Schottky diode in series.
My question is How ti measure current of source For example the battary chargre output is 5v and current is 100mA, 200mA and so on this current is printed on charger so how to measure this source current by using multimeter???
@ 4:05 for fixed outputs do the following simple steps, 1. just use a 10k or 100k pot to set the desired voltage and 2. check the resistance between the pots terminals with a voltmeter and note down the resistance 3. use the resistor instead of the pot. no crazy / fancy / sciency calculations to do........ ha ha ha
It should be noted that when choosing a variable resistor to use with LM317 that it should have enough wattage to handle the dropout current otherwise the life expectancy would be ahort.
Thanks for the video, it was very interesting and helpful for me; also well explained and easy to understand. Usually lifehack videos are pretty simple to understand i guess, even though they never actually say anything haha, but it was awesome to have you actually explain this in detail though instead.
+Electrical equipment repairing sir hindi mein bhi bana rhe hain ab video hum channel pe! Thoda time lagega lekin dheere dheere karke humare channel pe aur hindi videos dekhne ko milengi
