Thank you so much for this video! I was stuck in a question of my surveying assessment for days, and you basically saved me! your video is fantastic, clear explanation and an easy way to explain the details, I wish you were my examiner.
I've generalized the process to eliminate the need for a worksheet, eliminate the need to determine +/- 180 each step, and eliminate the problem of negative angles. it is also more amenable to automation via programming or spreadsheets. Here it is: Label all points in the direction of the traverse numerically from 1 (so 1, 2, 3... instead of A,B,C...) For Clockwise (CW) direction and Left Hand Angles (LHA) use the expression: A(n) = [A(n-1) - LHA(n) + 540]MOD360 Where An is the nth Azimuth, LHA(n) is the nth Left Hand Angle and MOD360 is the modulo operation (i.e divide by 360, throw out the quotient and keep the remainder. In simple terms, keep the the final angle result within the primary 0-360 degree circle.) For Clockwise (CW ) direction and Right Hand Angles the equation is: A(n) = [A(n-1) + RHA(n) +180]MOD360 A similar pair of equations can be derived for the complementary operation of finding the angles of turn given the Azimuths. I've confirmed they work for angle turns > 180 as well. These equations are elegant, closed form, and eliminate the plague of errors due to trying to keep track of all those sign changes etc. I'm sure I'm not the first to figure this out, but it's odd to me that everyone seems to teach this as you have. I understand that it's useful in cementing what the underlying mechanics are, but for real work, it's much too laborious. Maybe that's just me.
sir i am punching in the numbers on my calculator as you speak and im getting different answers by one .....ive concluded either im doing something wrong or you didnt make some rule clear to us......
I was confused for a while but my boss who's a surveyor helped me figure out the issue so I'll break it down and try to clear it up. Begin calculating Right to left starting at the seconds and carry over into the minutes then minutes carry over into degrees. So 25 27' 53" subtracted by 112 54' 17". Again begin with the seconds 53"- 17" = 36". So now we have 25 27' 36" subtracted by 112 54' 00". Now we subtract the minutes 27'- 54' but think of it as a clock going backwards and there's no negatives on a clock. We then get to 25 00' subtracted by 112 27' which then becomes 24 33' subtracted by 112 00'. So now we're at 24 33' 36" minus 112 00' 00" which then equals -88 00' 00". An Azimuth is 0-360 degrees so we take -88 + 360 = 272 degrees. And now we have our answer of 272 33' 36". 25 27' 53" 25 27' 36" 25 00' 36" 24 33' 36" -88 33' 36" -112 54' 17" --> -112 54' 00" --> -112 27' 00" --> -112 00' 00" --> +360 00' 00" = 272 33' 36" is our answer. I hope this clears things up a bit.
I understand how to get the degrees, but the minutes and seconds, i don't. Im confused how you subtracted 27 with 54 and came up with 33, but with 53 - 17 it came out correctly, as 36. Just a bit confused there.
Hey there! Idk if it'll help you or not but I found how he did that. So basically it was 25°27'53'' he added 360°00'00'' to it making it 385°27'53''. The interior angle is 112°54'17''. So basically if you do the regular math and subtract 112 from 385, 54 from 27 you'll get wrong answers. If you have a scientific calculator there is a button through which you can enter values in degrees second minutes. In your calculator put (385°27'53'') - (112°54'17") you'll get 273°33'36'' Hope this helps:)
