@@sauravsingh7271 but still for vedic math to work fast for higher numbers needs u to know other numbers square and addition to top that. I mean just look at his speed. And I doubt that if u learnt vedic maths they must have thought the derivation to u.
Ye Vedic maths hai kabhi Apne Sanatan dharma ke arth shastra ko bhi padh lo 1.एकाधिकेन पूर्वेण अर्थ: पूर्व वाले से एक अधिक प्रयोग: आवर्ती दशमलव भिन्न[recurring decimal fraction],वर्ग ज्ञात करने में,आंशिक भिन्नों द्वारा समाकलन[integration by using partial fractions]. उदाहरण: --वर्ग निकालने के लिए--(यहाँ केवल 5 से अंत होने वाली संख्याओं की बात की जा रही है)-- 25 का वर्ग:यहाँ पूर्व का अंक(संख्या) है 2 .----->2 का एकाधिक है 3. अब अंतिम हल है 2x3\25------->वर्गफल के दुसरे भाग में हमेशा 25 ही होगा. इस तरह 25 का वर्ग=625. 35 का वर्ग=3x4\25=1225, 175 का वर्ग=17x18\25=30625, 995 का वर्ग=99x100\25=990025.इत्यादि.
Diwana Kavi still it takes LOTS of practice. Let's say now we know how it works, then how long do you think you need to practice it to solve 8463 squared that fast?
@FACTS & knowledge He's still very well at articulating and explaining it. It really doesn't matter whom invented the method; if they don't have the platform or aren't able to explain it in a way that is easily conveyed and understood to the audience, then it is for nothing. This guy is a great proxy for the original work. Also, faulting this guy for teaching the methods in said book, is akin to badgering any other math teaching video for copying the teachings of the ancient Babylonians.
@Hitesh chourasiya maybe he discovered it on his own? It's not so hard to find out this "trick". Heck, I discovered this myself in high school. For a professor like him? Fnding this would've been a piece of cake
For those of you watching this and thinking that you'll never bee able to do it it's because you need to improve your basic math skills first. You may have to practice 3 by 3 subtraction, 3 by 3 adding and 2 by 2 multiplication. Just time yourself on 20 problems in each subject and if you're around 1 to 2 minutes for the 20 problems you're ready to start learning this method for squaring.
When this guy was a student at Mayfield High School (Ohio), he was brought into my 8th grade algebra class at Mayfield Middle School (1978-79 school year) and taught the class his methods for squaring numbers, and I still use them today.
You sir just taught me something no teacher ever could. I literally just successfully found the square route of 76 and checked it to be correct. My cat was jumped as I shouted YESSSS! haha
For those of you who would like the last problem in slow motion: 4913^2. He chooses 87. so now it is 5000x4826=5x4826x1000=(5x4800+5x26)x1000=(10x2400+10x13)x1000=(24000+130)x1000=(240130)x1000=24130000. Memorizes 130000=Dime. (Probably his mnemonic involves rules where 1 stands for nothing, 2 stands for something, 3 stands for dime etc. and then he combines them. So for example if it was 23000 it would be some other word plus Dime). Now he does 87x87=90x84+3^2=(9x84)x10+3^2=((9x80)+9x4)x10+3^2=(720+34)x10+3^2=(756)x10+3^2=7560+9=7569 now add that to 24000000+Dime (which is 130000)+7569=24137569
Except for the slight typo (240130), perfectly summed up. Although I do think he went around 5000x4826 a different way: 5000x4826 means 4826/2 and add 0000 so 24130000. Feels easier and quicker.
Nice job! One slight correction. He said he was doubling 4826. As he referenced earlier with doing 51^2, he's dividing it by 2. So, he said doubling for 4826, he's dividing it by 2 to get 2413 (x 10) = 24,130... Keep the "dimes" is using peg system. d = 1, m = 3, s = 0.
If it was published under a channel named Arthur Benjamin it probably would have. If MAA could show they have possession of this guy’s prowess then the million are earned.
@@3acreations So , he applied that not like you Indians who never respect Veds and Vedic Maths , now when others are using it you are getting jealous . Ya , he should mention that , but it will be of more use if he teach them that , as knowledge is important more than its source . If you had respected your Vedas , then India would have been developed more than others . you sing of Ancient Glory . But don't understand that what you are now matters , not what you were. Most of you , I mean don't even believe them , thatswhy Vedic Maths books are found lying in trash which is one of least selling books. P.S. I don't hate India or you , I just meant to say that come out of your bubble as no one gives a damn about your past . Only what you are now matters , which I called the hub of wasteful students supporting terrorists and politicians too backing them like hell .While criticising your government for even trying to get into NSO or bring uniformity in your country . That's the impression I got of your country .
Mathematics has always been my favorite subject and it's you sir, who made me go crazy for Mathematics... Love from India ❤ I'm sure that I'm gonna meet you in 2025... You are my best teacher...
+Matthias Köhler (MattK269) good job! try now practice with finance questions in Finmath app itunes.apple.com/us/app/finmath-financial-mathematics/id1085429075 i hit just Associate level
There is no magic though. This is simply (a)^2-(b)^2 = (a - b)( a+ b). Adding b^2 both sides: a^2=(a-b)(a+b)+b^2. Anyways, this video is very helpful. I appreciate him for putting this up.
Professor Benjamin has improved my mathematics so much LOL. I wish I knew how to do it this way 50 years ago LOL but now my son benefits from this! Fantastic and I just subbed!
It's Vedic math brother 🇮🇳 1.एकाधिकेन पूर्वेण अर्थ: पूर्व वाले से एक अधिक प्रयोग: आवर्ती दशमलव भिन्न[recurring decimal fraction],वर्ग ज्ञात करने में,आंशिक भिन्नों द्वारा समाकलन[integration by using partial fractions]. उदाहरण: --वर्ग निकालने के लिए--(यहाँ केवल 5 से अंत होने वाली संख्याओं की बात की जा रही है)-- 25 का वर्ग:यहाँ पूर्व का अंक(संख्या) है 2 .----->2 का एकाधिक है 3. अब अंतिम हल है 2x3\25------->वर्गफल के दुसरे भाग में हमेशा 25 ही होगा. इस तरह 25 का वर्ग=625. 35 का वर्ग=3x4\25=1225, 175 का वर्ग=17x18\25=30625, 995 का वर्ग=99x100\25=990025.इत्यादि.
you are a genius i surprised my teacher like when she called me dumb.. and she asked me square of 19 and we get 361 and everyone clapped but then she asked 99 and I answered after couple of seconds 9801 and I gained my respect 😎
We can generalize the equation at 8:30 to multiply two arbitrary integers A and B. Notice that (A+d)(B-d) = AB-dA+dB-d^2 = AB - d(A-B+d), hence AB = (A+d)(B-d) + d(A-B+d), and notice that if A=B we retrieve the eq. at 8:30. For example consider: 26*33. The nearest easy number is 30, so subtract 3 from 33 and add 3 to 26: 29*30. Then add 3*(26-33+3) = 3*(-4), so: 26*33 = 29*30 - 3*4 = 870-12 = 858.
You are an amazing professor. Hopefully I can find a video of you teaching us how we can find the root of numbers without using calculators. I’m also looking for tricks for division problems.
Same I dont concentrate either I remember back in first grade my teacher used to teach like take 1 in your finger and 6 in your mind and shit which I did not use to calculate I used my brain
The teacher used to give us a whole page of simple maths as HW in first grade and I hated HW so I did it in the class itself with my friends i calculated so fast that after i finished my friends had completed 2 columns out of 10
You can save time by memorizing all the squares from 10 to 100 to begin with. Since you already know how to square numbers ending in 0 and 5, there are only 70 left to memorize. So it is not that impossible if you think about it. In less than a week you should have it done. To calculate addition faster you can visualize that you read the numbers from a whiteboard, you see the numbers there, just like when you see them written with your eyes open. I think that's why he closes his eyes while doing the addition in his mind. But you also need to learn how to do subtraction quickly in your mind, for the first step when you go down. 71 to 100 -> you see easily that it is 29, but the other way: 71 - 29 is not that fast unless you have learnt how to do that quickly in your mind. And the arm and body movements help him increase the brain's speed to jump to the next step and the next step and so on. Our human brain likes to take pauses, but you must force it to continue with the calculations, step by step, there is no need to freeze the thought on a specific result when you have more steps to do. I think this is the hardest part to master.
i worked out that x^2 + y^2 +2xy= the square of any number. if the number is (xy)^2. hence 51^2 is 50^2 + 1^2 + 2*50*1. This works equally for every number. So a 3 digit number can be expressed as 124^2= 120 ^2+4^2 +2*120*4 Although id never get to it as fast as this practitioner, and wonderful educator x. however there must be a formula for 3 digits, 4 digits as well.. just never worked it out yet..
Wouldn't the x^2 + y^2 +2xy method defeat the purpose of squaring any complicated number more than 100? I mean, you still have to square a 3 digit number to find the square of another 3 digit number. Like, to find 124^2 you have to do 120^2. Also that method is pretty simple because it's basically the regular (x+y)^2 formula.
Thank you so much for this...!!! My stats teacher is going to piss herself when I can complete half of a one-way anova by the mind alone!! hehe....Now to find the video on how to multiply 2 digit numbers like 24 x 39 etc...
start from left to right, we have 2 x 3 (20 x 30) so we have 600 record the 600 in your head and continue, 2 x 9 (180) add to 600 is 780 and add 3 x 4 (120) 780 + 120 = 900 ok still have the 900 in your head and add 4 x 9, 936. this is the answer, the method is multiply straight, cross, straight, I X I. so if we have 43 x 67 we start with 4 x 6 = 2400. and we add 4 x7 = 280 we have 2680 and we add 3 x 6 is 180 so 2680 + 180 is 2860 + 3 x 7 = 2881
It's Vedic math brother 🇮🇳 1.एकाधिकेन पूर्वेण अर्थ: पूर्व वाले से एक अधिक प्रयोग: आवर्ती दशमलव भिन्न[recurring decimal fraction],वर्ग ज्ञात करने में,आंशिक भिन्नों द्वारा समाकलन[integration by using partial fractions]. उदाहरण: --वर्ग निकालने के लिए--(यहाँ केवल 5 से अंत होने वाली संख्याओं की बात की जा रही है)-- 25 का वर्ग:यहाँ पूर्व का अंक(संख्या) है 2 .----->2 का एकाधिक है 3. अब अंतिम हल है 2x3\25------->वर्गफल के दुसरे भाग में हमेशा 25 ही होगा. इस तरह 25 का वर्ग=625. 35 का वर्ग=3x4\25=1225, 175 का वर्ग=17x18\25=30625, 995 का वर्ग=99x100\25=990025.इत्यादि.
ive been practicing this for the past 2 years and can now square any number between 0 and 100.000.000. it takes me 20 minutes but i can do it! memory is the hardest part
Indeed, you are a number wizard. This video is very informative. I have tried up to 4 digits okay; but I couldn't come out as fast you you do! It's God'd gift to you. It's great that you are sharing to others; it is really good.
I spent a few months pondering about it and no joke i kind of figured it out on my own.. But there was always something missing.. Your video brought my memories backs RN explains where i went. wrong.. Thank you for sharing this
I always thought I'm best at mathematics and then I saw you. I'm no where near you, I know about tricks and all but doing it that quick in mind is something I won't be able to do. Respect sir 🙏
Sir my 5 grade kid watch your video.....your way of delivering the lecture is very nice even kids can understand thank you very much......so please make video for mental maths decimal division,patterning and long multiplication......
