Тёмный

Math Olympiad | 90% Failed to solve | You Should Know this Trick ! 

VIJAY Maths
Подписаться 9 тыс.
Просмотров 10 тыс.
50% 1

#matholympiad #maths #algebra

Опубликовано:

 

27 янв 2024

Поделиться:

Ссылка:

Скачать:

Готовим ссылку...

Добавить в:

Мой плейлист
Посмотреть позже
Комментарии : 20   
@honestadministrator
@honestadministrator 5 месяцев назад
(1 + 2 n) (1 + 2 m) = 1 + 2 ( m + n + 2 m n) = 99 = 1 * 99 = 3 * 33 = 9.* 11 Case I. ( 1 + 2 m. = 1, 1 + 2 n. = 99 Or 1 + 2 n. = 1, 1 + 2 m. = 99 ) Hereby m = 0, n. = 49 or m = 49, n = 0 Therefore, m + n = 49 Case II ( 1 + 2 m = 3, 1 + 2 n. = 33 Or 1 + 2 n. = 33, 1 + 2 m. = 3 ) Hereby m = 1, n. = 16 or m = 16, n = 1 Therefore, m + n = 17 Case III ( 1 + 2 m = 9, 1 + 2 n. = 11 Or 1 + 2 n. = 9, 1 + 2 m. = 11 ) Hereby m = 4, n. = 5 or m = 5, n = 4 Therefore, m + n = 9
@superiorlyrics8326
@superiorlyrics8326 5 месяцев назад
Great explaination !!
@vijaymaths5483
@vijaymaths5483 5 месяцев назад
Thank you ⚘️
@urmilas5356
@urmilas5356 5 месяцев назад
Nice👍
@nasrullahhusnan2289
@nasrullahhusnan2289 5 месяцев назад
As there are 2 unknowns m and n m+2mn+n=49 is a diophantine equation --> m and n are integers 49=±1×(±49) or 49=(±7)² 49=(±7)² is impossible as LHS is not a square. If m=1 then 49=1+2n+n --> n=16 If m=49 then 49=49+2×49n+n 0=99n --> n>0 m=-1 or m=-49 does not aplly. As the equation is cyclical then (m,n)={(1,16),(0,49),(16,1),(49,0)}
@fred8780
@fred8780 5 месяцев назад
i did a hard push; n=1 then m=16; 2&3 then m not integer; n=4 then m=5 .
@crazyguy1714
@crazyguy1714 5 месяцев назад
Thank you sir for such good questions and explanations
@vijaymaths5483
@vijaymaths5483 5 месяцев назад
Thank you
@JPTaquari
@JPTaquari 5 месяцев назад
It's easy to solve mentaly, M = 1 or 16 N = 16 or 1 Now, I'll try to get a arithmetic solution ...
@user-ri6rn7ti5h
@user-ri6rn7ti5h 5 месяцев назад
m+2mm+n=√49 (m+7n-7)
@sumit-mn6ys
@sumit-mn6ys 5 месяцев назад
👏👏👏
@vijaymaths5483
@vijaymaths5483 5 месяцев назад
Thanks for watching !!
@WhiteGandalfs
@WhiteGandalfs 5 месяцев назад
This is, again, a very complicated approach: Simply setting m to 1, then trivially calculating n (it's the most simple linear expression that exists) gets you directly to the first pair, then going up from there as long as m is lower than n yields another 3 trivial cases. Since the expression is symmetric, the solutions are as well. Then the thing is solved. I don't see how "90% failed to solve" could possibly fit into reality. Could it be that this wording is just clickbait?
@grrgrrgrr0202
@grrgrrgrr0202 5 месяцев назад
Have you worked out your method in its entirety? Because finding out what values of m you need to plug in sounds pretty painful. (On top of that, the method he presented also works for all Diophantine equations of the form am+bmn+cn=d)
@WhiteGandalfs
@WhiteGandalfs 5 месяцев назад
@@grrgrrgrr0202 There was nothing "painful" about the trivial approach. It had just 4 pairs of (m,n) to examine - MUCH LESS than what the author of the video presented in his approach. And AFTER having his complicated reforming of expressions, he ended up probing pairs of values anyways - he didn't reduce complexity at ANY stage, just to the contrary.
@grrgrrgrr0202
@grrgrrgrr0202 5 месяцев назад
Ok, so how would you figure out what values of m or n you'd need to examine?
@WhiteGandalfs
@WhiteGandalfs 5 месяцев назад
@@grrgrrgrr0202 The expression is symmetric to m and n, thus you need only values m
@grrgrrgrr0202
@grrgrrgrr0202 5 месяцев назад
​@@WhiteGandalfsYour method may be preferable in this case, but it would fall pretty flat if the right hand number was bigger or if m and n didn't have any coefficients. It is also worth noting that RU-vid videos like these go for extremely slow and overly detailed explanations (which I despise); the method listed here takes arguably less than 30 seconds to resolve.
@comdo777
@comdo777 4 месяца назад
asnwer=7 isit
Далее
Math Olympiad Problem, you should know this trick!
9:44
Many Students Failed To Solve This Geometry Problem
19:56
Functional Equation
14:15
Просмотров 377 тыс.
A Nice Math Olympiad Algebra Problem
14:37
Просмотров 804