Math Olympiad | A Nice Exponential Problem 🤔

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Math Olympiad | A Nice Exponential Problem 😊#Mamta maam #exponentialproblem #matholympaid#maths
Math Olympiad | x²-y²=9 , xy=20 , Find x+y=?? 🤔 #Mamta maam #exponentialproblem #matholympaid
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Maths Olympaid are held all around the world to recognise students who excel in maths.
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Опубликовано:

3 окт 2024

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Комментарии : 19

@arvindkulkarni6580 4 месяца назад

Perfect teaching method

@LaxmanKumar-yi4cv 4 месяца назад

Good teaching skills

@Maheshkumar-cw6un 4 месяца назад

Nice explanation mam

@aruntiwari5714 4 месяца назад

Very nice video ma'am 🤩🤩

@satyadev3848 4 месяца назад

nice 🙏🙏

@KeshavKulkarni-x1w 4 месяца назад

Brilliant thanks for the methods

@SALogics 4 месяца назад

Great video ❤❤

@harikishan1900 4 месяца назад

❤❤

@NithyaGhumare 4 месяца назад

You are really a very good Maths Teacher Ma'am

@harshpathak2359 4 месяца назад

Perfect theorem

@manojchaugule794 4 месяца назад

good explaination

@luciangv3252 4 месяца назад

06:19 tiny error but great video.

@harikishan1900 4 месяца назад

Very nice explanation 👌

@ichdu6710 3 месяца назад

ohter solution: let a = 3^x - 4^x the right side can be written as root(4^x)*root(a) --> a = root(4^x)*root(a) --> a - root(4^x)*root(a) = 0 with the comon factor root(a) root(a)*[ root(a) - root(4^x) ]= 0 Solution 1: 1. factor = 0 --> root(a) = 0 --> 3^x - 4^x = 0 --> x = 0 Solution 2: 2. factor = 0 --> root(a) - root(4^x) = 0 --> 3^x =2*4^x --> x = log(2)/log(3/4)