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Math Olympiad | A Nice Exponential Problem | VIJAY Maths 

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17 июн 2024

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Комментарии : 7   
@roberthayter157
@roberthayter157 19 дней назад
I learned something there: the constant use of x²=x+3 to reduce the power. Really good. Thank you. 😊
@user-ee7nw2rx9s
@user-ee7nw2rx9s 2 дня назад
Неплохо бы разделить сначала на sqrt 3 В итоге получается (Sqrt 13+1)/2 С этим выражением удобнее работать
@crazyindianvines1472
@crazyindianvines1472 22 дня назад
great explanation
@anandm-lx6zc
@anandm-lx6zc 22 дня назад
It can also be solved easily by multiplying x^4 and x^3
@vijaymaths5483
@vijaymaths5483 22 дня назад
S
@suchaluch5615
@suchaluch5615 17 дней назад
Is this really faster and/or less error prone than 4 multiplications? You could just do the following: square the term (let's name it x2) square it again (let's name it x4) multiply the result with x2 (let's call this x6) and multiply it with the original term. Looks way easier, faster and less error-prone to me.
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