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Math Olympiad International | Solving A Challenging Simultaneous Equations. 

OnlineMaths TV
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Here is one of the toughest simultaneous equations ever.
In this video I will lead you through series of steps involving multiples substitutions, the application of some algebraic identities, application of the power law of indices and the power law of logarithm as well as the division law of logarithm and others.
This will take a while to actually get the final roots to this rhetorical math Olympiad challenge but every step is well touched for the keen understanding of every viewer.
Give the video a like, comment and share with your friends, school mates, colleagues, family members, loved ones and even your haters and enemies for by so doing you will know more...😂😂🤣🤣🤣😍😍😍😍
Another reason you have to share with your haters and enemies is because of the festive season we are into. The season depicted love and so show some LOVE to someone.
Let LOVE leads in all you do this season irrespective of your tribe, religion, color, field of endeavor etc.
Above all, never forget to subscribe to this channel if you have not done that and to my returning viewers and subscribers, Meeting you online is the VERY BEST thing that has actually happened to us all at Onlinemathstv in the year 2023.
We LOVE YOU all greatly and deeply and we will keep LOVING YOU till the end of the time ❤️❤️💕💕💕💖💖💖😍😍😍😍
Wish you all the best in life comes 2024.
Cheers 🥂🥂🥂🍾🍾🍾🍾

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4 окт 2024

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Комментарии : 58   
@worldfacts6414
@worldfacts6414 4 месяца назад
Sir you are true genius, i was expecting that this problem cannot be solve but you solve this with ease Support from India 🇮🇳❤
@charlesmitchell5841
@charlesmitchell5841 9 месяцев назад
Bravo! Nice work. So when all is said and done there are no solutions in the real world because of the iota.
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
No sir.
@edoarte9333
@edoarte9333 9 месяцев назад
Gracias estuvo muy bueno, hubo de todo; me hubiese gustado que no terminará en un número imaginario. Saludos desde México 👏👏👏Merry christmas.
@peterbyrne6394
@peterbyrne6394 5 месяцев назад
Thank you. Suppose very clever at maths
@onlineMathsTV
@onlineMathsTV 4 месяца назад
You are most welcome sir and thanks for this encouraging comment. We love you so so much sir...❤️❤️❤️
@FERNANDOALVAREZ-iz8nw
@FERNANDOALVAREZ-iz8nw 9 месяцев назад
Wonderful
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
Thanks a million sir.
@IAmSavier
@IAmSavier 6 месяцев назад
It is usually required to solve equations in real numbers, unless the condition specifically states that complex roots are needed. It is not clear why p,q = 1, -3, which can give real roots, are rejected.
@juliovasquezdiaz2432
@juliovasquezdiaz2432 9 месяцев назад
Entendido. Gracias por el video. Saludos desde Chiclayo Norte del Perú
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
we are glad you understood and gained some values from this, Thanks for watching and dropping this comment sir.
@gerhardb1227
@gerhardb1227 8 месяцев назад
Hi and thank you for your video. Another useful approach after minute 10:41 coud be: EQ1: (x+y)^3-3xy(x+y) = x^3 + y^3 = 10 EQ2: (x+y)^2-2xy = x^2 + y^2 = 7 ------------------------------- Set EQ1 = EQ2 by xy [(x+y)^2 -7]/2 = xy = [(x+y)^3-10]/[3(x+y)] ------------------------------- substitute (x+y) = u ------------------------------- 3u(u^2-7) = 2(u^3-10) ------------------------------- u^3-21u+20 find first solution and after that do division and solve qudratic equation u1=1; u2=4, u3=-5 solve u: 6 solutions ------------------------------- => x^2+y^2 = 7 from u=4: x+y = 4 y = 4-x x^2 + (4-x)^2 = 7 2x^2 - 8x +9 = 0 x12 = [8±j*sqrt(8)]/4 resubstitute
@onlineMathsTV
@onlineMathsTV 8 месяцев назад
Wow! Thanks for sharing this wonderful appreciate I will study it carefully and closely at my leisure time so that I can apply it in solving similar challenges of this kind in subsequent video tutorials sir.
@elmurazbsirov7617
@elmurazbsirov7617 9 месяцев назад
Əla həll etdiniz.Bakıdan salamlar.
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
wow! Thanks a bunch for this acknowledgement sir. Much love from all of us here at Onlinemathstv to you sir...❤️❤️💕💕😍😍
@mrjnutube
@mrjnutube 9 месяцев назад
Lovely stuff... This is a hangover BURSTER!
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
Thanks a million for watching and dropping this encouraging and wonderful comment here sir. Much love deeply💕💕
@BOGATISUSENI
@BOGATISUSENI 9 месяцев назад
Profeseur is briliant student teaching people
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
hahahaha...my good friend
@channelsixtyeight068_
@channelsixtyeight068_ 9 месяцев назад
...... I think I need a drink. That was epic. Thank you.
@therichcircle.8819
@therichcircle.8819 9 месяцев назад
This is mathematics. Thanks a big deal master.
@math_qz_2
@math_qz_2 9 месяцев назад
I like this problem. Good explanation
@charlesmitchell5841
@charlesmitchell5841 9 месяцев назад
Oh, by the way, Merry Christmas!😅. You are a great teacher.
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
Thank you! 😃 We all at Onlinemathstv you the very best in this festive season sir.
@nta_gaming
@nta_gaming 9 месяцев назад
I found all 6 complex solutions, it took me about 1 hour to sovle all
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
Bravo!!! You are the master here, maximum respect to you sir.
@BOGATISUSENI
@BOGATISUSENI 9 месяцев назад
If a is isolated in the left side And b and numbers in rigth side (8/4)^a=(..)/(..) 2^a=(..)/(..)will be introduced in first equation. This was in '75. French algebra translated books were simple
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
Noted, thanks a million sir.
@brunobuzzacchi1108
@brunobuzzacchi1108 8 месяцев назад
I didn't understand why you rejected (p,q) with negative p or negative q...
@danielfranca1939
@danielfranca1939 9 месяцев назад
This is beyond my scope I beg, anyway thanks for the video I enjoy your explanations teacher. Wishing the best of the season....🎉🎉🎉❤❤❤
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
Hahahahaaha....that is not true my good friend. Just give it a detailed study for few times and you will discover it is easier than you thank sir/ma.
@nagarajahshiremagalore226
@nagarajahshiremagalore226 6 месяцев назад
Excellently explained. But we can minimize writing time by not repeating, thus shorten the video. Thanks for uploading. 2024.3.26
@nyaenge
@nyaenge 9 месяцев назад
굿굿
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
Thanks for appreciating our little effort thus far.
@danielkyei7173
@danielkyei7173 9 месяцев назад
Brother, you have done so well but there's a little mistake that needs to be corrected, even though it didn't affect the answer. It has to do with the factorization of the quadratic equation p²+p -20=0. The parentheses in the next step are wrongly placed. That's (p²+5p) - (4p -20) =0 is supposed to be written as (p²+5p) + ( -4p -20) =0 Remember that if we expand these two equations we won't get the same result
@onlineMathsTV
@onlineMathsTV 8 месяцев назад
Thanks for appreciating our works here sir and thanks for the correction, it is well noted and I will be more careful in subsequent lectures sir. Maximum respect sir...👍👍💪💪💪
@leonznidarsic
@leonznidarsic 9 месяцев назад
Horner's algorithm seems to me to be better than polynomial division. Less writing, and a faster way to the zeros of a polynomial.
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
Ok, I will apply that in subsequent challenges sir/ma.
@StephenRayWesley
@StephenRayWesley 9 месяцев назад
Hello hope you are having a good morning 🌄 merry Christmas Eve
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
Sure sir, we all here are having a blissful morning. We hope you are having same over there, we wish you all the best in this season also sir. Much love from all of us at Onlinemathstv to you sir. 💕💕❤️❤️💖
@Viesto1980
@Viesto1980 9 месяцев назад
19:07 - If you multiply 4*(p+5) it will be equal to 4p+20 not 4p-20.
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
No sir, the minus at the back of 4 will change the plus sign to minus, so that expression is 100% correct. Thanks for watching and dropping this comment. Much love ❤️❤️💕💕
@harryfazekas4238
@harryfazekas4238 9 месяцев назад
Good work.Very nice problem, very ugly solution. Exactly the opposite of what Ramanujan would have done. Or not.😊
@onlineMathsTV
@onlineMathsTV 8 месяцев назад
Hahahaha....anyway thanks for dropping this comment sir. You made my day as I read you comment and laughing at this same time sir. Much love to you sir... 💕💕💖💖🥂🥂
@rahulgujar2843
@rahulgujar2843 9 месяцев назад
Wish you merry Christmas 🎅 🎄
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
Many thanks for the wishes and all of us at Onlinemaths tv love you dearly for this comment sir.
@StephenRayWesley
@StephenRayWesley 9 месяцев назад
1^1 2^5 (x+1x-1) (x+2x-5)
@nunoalexandre6408
@nunoalexandre6408 9 месяцев назад
Marry Christmas ❤🎉
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
Wishing you and your entire family the best of the season sir.
@Obitabaobenuovoabove
@Obitabaobenuovoabove 8 месяцев назад
Hi
@fananff
@fananff 9 месяцев назад
This is complexes math
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
Hahahaha...🤣🤣😂😂 Yes it is complex but can be learnt in few steps, just follow the steps carefully and you are good to go. Thanks sir.
@abdurrahim-gb8om
@abdurrahim-gb8om 9 месяцев назад
last line is irror
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
So so sorry about that, I will be more careful in subsequent time master. Thanks for the good observation sir.
@LeykunKassa
@LeykunKassa 8 месяцев назад
WHO and what is mathematics ??? 🌈🌈🌈🌈🌈
@neilmccafferty5886
@neilmccafferty5886 9 месяцев назад
too many errors. Redo.
@onlineMathsTV
@onlineMathsTV 9 месяцев назад
Really? we will appreciate it more if and only if you can point them out steps by steps so that we can amend and avoid such errors in the new video tutorial sir. Thanking in you in anticipation.
@Cptkelvin
@Cptkelvin 8 месяцев назад
You are wicked😂
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