sir u r awsome and incredible....youtuber like you are the legend for next generation education...this type of video are the revolution in education system...thank you...
i was curious to know about this MATHEMATICAL DESCRIPTION OF SIGNAL WAVEFORM as no textbook (as far as i know ) has taught it exclusively .It is of great help in understanding the other part of signals and systems.GREAT JOB SIR
Veryyy nicee explanation sir ....it's awesome 👏👏 👏 . Your videos are the best I have ever seen...i have understood this concept by seeing your lectures only.pleaseee upload video by taking some complicated examples sir...I am still confusing ....
Sir in this lecture when take the derivative of 2r(t) you write 2tu(t) and the next lecture 2r(t) = 2u(t) I have problem in this part if you could explain it thanks
@@PoluBalaji the slope was from -2 to 0. Thus, you subtract the final slope with the initial slope which is 0 - (-2) = 2. That is why it is 8/4 which is 2.
In the second Example, shouldn't it go down by -17u(t-4) ?? because, if we go down by just 16, then a unit step would begin at t=4, and that will make the value of the signal 1 from t>=4 ?? Please clear the doubt.
Sir my question is that -What happened when the slop of ramp become 90 degree.As we know that tan90 is not defined. Please reply sir as soon as possible Thank you
hi I guess it is way too late, but the reason for that is because it is represented as "step" signal beceause there is a discontinuity, and therefore only the level is changing from 16 to 0.
@@Sharmine_ 2tu(t)-2(t-1)u(t-1)-2u(t-1) Expand the (t-1) by Multiplying... 2tu(t)-2tu(t-1) Last 2 terms are Cancelled. Hence We only Left with 2tu(t)-2tu(t-1).
@neso academy u askss us to comment in comment section if we hve any doubt but ihve been seeing that you didn't replied to anyone.. and didn't clearer any doubts
Thank you sir for this clear and nice explanation :), I need to plot the following function: Hw(tau)=H[Cw(t-tau)-r],could you please help me to plot it?Thanks again :)
please can anybody plot 2nd in matlab? clc close all hold on t=-100:0.01:100; y= t>=0; r=t.*y; r1=(t-4).*y; x2= t-4>=0; p=4*y+3*r+-3*r1-16*x2; plot(t,p,'black') axis ([-5,10,-10,20]) xlabel ('Time,t') ylabel ('Exp. rising signal,sinc(t)') hold on t = -1000:0.01:5000; plot(t.*0,t) hold on t = -1000:0.01:5000; plot(t,t.*0) didn't work