Maths Help: Finding Bearings - VividMath.com 

My teacher for math doesn't teach anything! She just expects us to understand. This helped immensely, thank you!

my exam is literally in 15 minutes and you have just saved me THANK YOU

Love how simple he lays it out, had no confusion and grasped it very well. Thank you sir.

My math teacher would only ask the smartest kids in class do the understand if they say yes he move on to hw leaving me soooo confused!!!

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Cleared up 2 years of confusion in a few minutes. Thank you

Yes - Some textbooks only require 2 digits and others require 3 digits. You might want to check with your teachers preferences. As you know e.g 38 degrees is the same as 038 degrees. Hope that helps ;)

Bearings are measured from the north or from the south towards the east or towards the west and does not exceed 90°. The measurements from north in a clockwise direction is an azimuth.

I have a test on bearings today and we haven’t even talked about bearings for months in class. Thanks so much for this refresher man!

Thanks man you're totally genius ...

Very helpful BUT it should be bearing 060degrees not 60degrees as they are written in 3 digit numbers :)

You have got a really nice way of explaining! Thank you!

2:00 Let's mark out the bearing so you can see it *visually* WOW

THANK YOU SO MUCH! YOU HELPED ME SOLVE MY HOMEWORK PROBLEMS!

Bearings is legit on my yr9 maths test tomorrow- and i have NO idea what im doing lmao

Great help for maths exam! Thank you!!!

Omg you explained it so easily my textbook made it so complicated THANK YOUU

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thanks, i also saw your other videos, they were all helpful!

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Thank you!! I now FINALLY get bearings!!

This really helped! Thank you!

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Thank you teacher realky appreciated your effor

Thank you so much sire, really helped

For basic concept. This is great Sir. 💯

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Thanks, that helped me finish my maths assignment.

So helpful continue to post more videos like this

This is actually a measurement of North Azimuths. Bearings are measured from directly North and South with East and West being used to determine the direction from North and South. A Bearing angle will never be larger than 90 degrees. Example: N65*W or S35*E.

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wow, i learnt more in 6 minutes than I have in 3 hours

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Im now learning this This makes more sense than my teacher

Remember this formulas are used to convert RB to WCB 1st Q: RB=WCB 2ND: 180-RB=WCB 3rd Q: 180+RB=WCB 4th Q: 360-RB=WCB

Outside of the USA they are called bearings. In the USA bearings are measured from N or S for example, in his first example it would be N60E

ok but that arrow was so neat. love that

Thank you this was helpful

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Thank you so much sir i have a test on this subject (Year 5) this week and i didn't understand till now ! Now i know how to do this just by seeing this video!

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thank you

Sorry, but the full website is not up yet. Should be up soon. Thanks for the enquiry.

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GOD loves you this helped a lot our exam is coming up

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This helped alot I have my exam

Thank you so much sir you just save me I now understand how to solve bearings l am ready for My mathematics test 👍👍

Good explanation 👌

Thank you so much great explanation this helped with my test

Can you do more bearing math videos..these videos do help me a lot!! thank you😊

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I enjoyed process.

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This can help me for physics

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life saver

Tnx sir 4 ur hlp

TEACHER!! I have question Why you Add 180 And 19 degrees but Subtract all others ??

why did you add the second one

2:01 i love You for saving my life ❤

In bearing when do you subtract and when do you add

11 years but still helps

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I like it

i really cant understand how the camera quality was sooo good litreally 9 years ago...

Sir this is so helpful and I would like to just say *THANK YOU !!* bcus my teacher is such a piece of sh*t *You saved me Sir* *I am going to gather all my 3 phones to hit that like button and subscribe !!*

2:10 i cant stop laughing xD

on the first problem. on our book it says on Quadrant 1 Northeast Bearing = Azimuth and vice versa. which is true?

1:02 haha ...beautiful bearings

Pls can teach the longer version of bearings at once

This was very helpful but can you tell me how to get the bearings cuz im kinda confused and i got exams

Actually, these are north azimuths he is describing. North azimuths are measured from (or the initial side being zero) the north in a clockwise manner, and can have a magnitude up to 359 degrees-59 minutes-59 seconds. Bearings on the other hand are measured from the North OR South (initial side being zero) towards the east or the west and can have a magnitude of up to 90 degrees. For example, a bearing of North 35 degrees East, is measured from the north being 0, clockwise towards the east a magnitude of 35 degrees. A bearing of South 35 degrees east would be measured from the south being zero, counter-clockwise towards the east a magnitude of 35 degrees. North-west; from the north 0, towards the west 90. Southwest; from the south 0, towards the west 90. If you are also doing latitudes and departures (change in x,change in y) of the bearing angle your right triangle that is formed is drawn by following the directions of the bearing. For instance using his diagram of point O to point A, a northeast bearing would be drawn from the point O north along the y axis, the due north cardinal equivalent of the length of line OA, then to the east the due east cardinal equivalent to point A. That forms a right triangle using the Y axis, and the hypotenuse of the triangle being line OA. Your bearing angle would then be the angle formed by the Y axis,O, A, thus making the Y axis your adjacent side. the north most line from the y axis to point A would be the opposite side. Therefore to find the length of the adjacent side, you would use cosine of the bearing angle multiplied by the length of the hypotenuse(OA), that would give you the change in Y, change in Northing, change in latitude or simply called your latitude from O to A. To find the opposite side, you would use sine of the bearing angle multiplied by the hypotenuse (OA) which would then give you the change in X, change in easting, change in departure or simply called departure from O to A. If one only had the latitude and departure or change in x, change in Y from O to A, using the same triangle, one would use the inverse tangent of change in X divided by change in Y or the opposite over the adjacent. The change in X or change in Y are also called delta's. Delta X, Delta Y.

I have my math exam tomorrow and I haven't attended a single class on bearing. I'll update on what marks I'll get after the exam!

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this is simple to understand but how do we do the other way round? like o from a or o from c? thats what i dont understand

please tell me how to show bearings in WCB of 0, 90, 180, 270 in QB/RB.

South to East Counterclockwise

u worked out onlly the basic concept of bearing. can u go abit deep in to it like reverting the angle and stafff???

How to Calculate WCB for 0° E?

Maths made easy. Thank you!

Bearing of A is right but I think the method is wrong. Because N E Co-odinate count from North zero so 0+60 = 60° is right answer, i think. Thanks u

Good

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