Why is {A,E} not a closed frequent itemset? It has a count of 1 while its immediate supersets {ABE}, {ACE}, {ADE} all have 0 count. Please do correct me if I am wrong.
Because if it doesn't pass the minimum support, you can't call it frequent. Here it is mentioned that the minimum support is 50% , which means 50% of the number of transactions. Here, the number of transactions is 4, hence minimum support is 2 (50% of 4). Since AC OCCURS JUST ONCE, IT IS NOT FREQUENT. If it's not frequent, it can't be closed frequent and maximum frequent. Hope this helps.
Hi, I have a question, If we only construct maximal frequent search (without searching anything else from data), can we find all positive statistical associations. tks
Surya Aniketh yes ACD is 1. But the remaining itemsets u mentioned evaluates to 0. I didn't include them because they are not part of closed frequent itemset and maximal frequent itemset. Also, this example aims at finding the maximal frequent itemset and closed frequent itemset. Anyways Thanks.
the best part about the whole learning from youtube experience is the horrible audio. thank you for your content and terrible sound. please dont get a better microphone or even speak closer to it - it'll ruin the experience.
additionally thank you for the clarifications. i came here for the content and you delivered. it took a while for someone to explain the difference between closed & maximally frequent itemsets.
