Mechanical Engineering Thermodynamics - Lec 32, pt 1 of 3: Combustion - Excess Air 

No - it should be multiplied by 3. 0% excess air is the correct amount of air based on the stoichiometric balance, and thus it is 1*a_th. For 100% excess air it is 100% more air than you need, and thus it is 2*a_th. For 200% excess air it would be 3*a_th.

100% theoretical air = 0% excess air = a_th 200% theoretical air = 100% excess air = 2 a_th 300% theoretical air = 200% excess air = 3 a_th Am I right?

I was here for Heat Transfer but I'm back for Thermo! 😂 You are such a good lecturer!

why 200 % excess air deals with 3*theo air?

Thanks a lot. Why didn't you put the stoichiometric equation from the beginning if you knew that you have excess air? I mean you multiply the air by 3 and add the Oxygen to the right.

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a should be 4.5 6:55 ı dont know you still checking youtube but you are great sir

thx, greetings from Monterrey, México

thank you so much for the time sir

Sir how if the problem said "the amount of O2 provided in the form of air (21% O2 and 79% N2) should be twice of the amount needed from the reaction" does it mean we have to multiply the a_th by 2 or the excess air is 200% ?

Hi could you please make video about combustion for Foundamental test exam please help

for 200% excess air should a-theoretical be multiplied by 2?

mercii bcp

Propane gas is allowed to react with 80% theoretical air. Determine the theoretical equation for the reaction. what to do in this case?

Great video thanks for the help!!

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Thanks

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Thank you

Thank you so much for all your videos. I really appreciate it and rely on it, again thank you.