Merge Nodes in Between Zeros - Leetcode 2181 - Python 

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2nd approach is on different level!

my in-place solution: prev = head cur = head.next while cur: temp = 0 prev = prev.next while cur.val != 0: temp += cur.val cur = cur.next cur = cur.next prev.val = temp prev.next = cur return head.next

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Thanks, sir Could you please tell me the toll you use to take notes?

Thanks for uploading I was curious about the in place solution

5:13, we can initialize cur = head.next in the start to avoid first 0 and only update return list when we get node.val == 0 instead checking node.next.val == 0, to reduce complexity and typo and potential bug in the code.

class Solution: def mergeNodes(self, head: Optional[ListNode]) -> Optional[ListNode]: temp = head ans = ListNode(0) dummy = ans curr_sum = 0 while temp: if temp.val == 0: if curr_sum >0: dummy.next = ListNode(curr_sum) dummy = dummy.next curr_sum = 0 else: curr_sum += temp.val temp = temp.next return ans.next

I am recursively calling for each 0

It seems like your in-place solution is still a bit complicated, could have just keep adding node values to the 0s and delete the last 0, since when you reaching right before the last 0, you could delete the last 0 by "if not cur.next.next: cur.next = cur.next.next"

crazy🥵

🥳

I did it without any knowledges regarding linked list, and after reading my code I dont know why it works

second comment

Very confusing explanation!! Like if you agree...

My new list solution is simpler, skip the first 0, add a new node when we hit a 0 class Solution { public ListNode mergeNodes(ListNode head) { ListNode rc = new ListNode(); head = head.next; ListNode copy = rc; int cur = 0; while ( head!=null ) { if ( head.val == 0 ) { rc.next = new ListNode(cur); rc = rc.next; cur = 0; } cur += head.val; head = head.next; } return copy.next; } }

# Definition for singly-linked list. class ListNode: def __init__(self, val=0, next=None): self.val = val self.next = next class Solution: def mergeNodes(self, head: Optional[ListNode]) -> Optional[ListNode]: li=[] li1=[] while head: li.append(head.val) head=head.next i=0 head=None while i

/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode() {} * ListNode(int val) { this.val = val; } * ListNode(int val, ListNode next) { this.val = val; this.next = next; } * } */ class Solution { public ListNode mergeNodes(ListNode head) { ListNode ansNode = new ListNode(0); ListNode dummy = ansNode; if(head == null) return null; ListNode flag = head; while(flag != null) { boolean present = false; int sum = 0; ListNode temp = flag; while(temp.val != 0) { present = true; sum += temp.val; temp = temp.next; } if(present = true) { ListNode node = new ListNode(sum); dummy.next = node; dummy = node; } flag = temp.next; } return ansNode.next.; } } can somone help ?? why my ans list is 0->4->11 for the first testcase even when im returning ansnode.next