Example problem using method of sections for truss analysis - statics and structural analysis. i) Calculate Support Reactions ii) Cut and Isolate iii) Apply Equilibrium Equations on the isolated FBD
It may be the fact that I've taken so many structures classes but it's amazing how simply you put that. In my Statics course I never understood how to do this but it just clicked! Great job.
Thank you for your AWESOME videos. They are thorough but quick! You dont take forever to explain stuff but you go over important points systematically! AWESOME!
+Layla Bz Thank you for the kind words on my teaching approach! On another note, your comment just pops with energy. I feel motivated to do more just from reading your words. I wonder if it's the word "AWESOME" in all caps...your comment is AWESOME! Mechanics is AWESOME! welcome back to structure fo rizzle AWSHIZZLE!
😭im so happy to find your videos. THANK YOU SO SO MUCH SIR.2022 ,10 years after your video but stil one of the most detailed explained video of static in youtube❤️ wish you bests. 6 June,2022 Civil eng dpt.Türkiye.hacettepe üniversity When I check comments of people here, they were like for 8,9 years ago. I was just thinking about all that people. How are they now?how was their exam back then? What are they doing? This circle of life is interesting. When you made this video I was about 10 and some people watched it,10 years later Im watching it.hahaha I cant imagine that little Aynil stepped on this way.fate... I think some people in future years may read my comment,want to say to you just stay strong in your way,if you get tired take a rest but dont give up. Look at your back,thousands of people walked in this way,you are one of them.you are not alone.its not the end of world dont worry keep calm. The stress of exam night believe me all of us exprienced that.keep calm. Wish you all bests.May Allah help us🌼
excellent, and clear! One of the more complex trusses I've seen on these videos, which is a good thing. (not many trusses have only 5 members) Thank you.
THANK YOU !!! I have to do this for my engineering class, and next week we have finals ! This helped me so much ! You made a couple mistakes, but I know what you meant. Thanks a lot man.
Hi, when you are calculating the sum of forces in the Y direction, why do you not take account of the 10k forces acting down and the 35k reaction force? thanks
After making the sum of Horizontal and Vertical forces = 0 , you only need to make the sum of the moments around joint (A) = 0 in order to find all the three req'd member forces.
Thanks for the question. Yes, you are right. I got sloppy at the end of the video with my algebra. I've considered taking the video down...but it seems to be helping more than harming thus far. You know, It's like owning an amazing house but a crappy bed...you may feel good but your back hurts after a while.
@structurefree, I'm not sure if anyone has pointed this out but when you sum the moments about N to get FDE the third term should be 10k x 10'. You have written it as 10k x 15'. Funnily enough when you calculated the force you have corrected it without correcting it on the sheet. Not that I'm trying to be a stickler, just thought you'd like to know. Thank you for the video anyway. Very informative. It's been a while since I touched this stuff.
woww thats really awesome explaining ... thank you and one thing i like about this video that you explain every little thing that we sometimes get stuck to continue solving the exercice... Anw thank u so much
No, I agree with you. Why throw out a great video over one tiny little thing? You could just put a message up at that time in the video letting people know I guess. All of your videos have been extremely helpful in MoM and statics. You always do a great job :-)
Wait! when taking moment about a why are you not taking into account the x and y components of Fde? aren't they also creating a moment about a? ....why am i expecting a reply... this video was made like 2 years ago.
I wonder if it's possible to use the equation you made in the summation of Fx and Fy to obtain the internal forces of the members FDE and FNE since you already have the internal force FNM? -By just obtaining the angles needed -and by using algebra(matrix) or by simply plugging in the values needed in the calculator? Is it possible?
by finding the value of force NM we can put the value in first two equations(sum of x forces equation and sum of y forces equation).then we have got two equations with two variables and we can find the angle. then solve the both equations and we have got the values .no need to find moments at A
Maybe I'm not getting this, but your last eq shows you taking the moments to the left of DE and you calculated with 5'x10k + 15'x10k - 15'x35k. I don't think you did that correctly. The second 10k load is only 10' away, not 15'.
Hi,, i just figured out that u r taking sum of forces along x axis=Fde=cos theta and then again for y direction u r taking it cos alpha again... shouldn't it be sin alpha???
Are you sure that your moment about point n equation is right? You have (10kip)(5ft) as well as (10kip)(15ft). Shouldn't that second 10kips have a moment arm of 10ft? Starting at 14:36
isnt the joint in compression if the force exerted by the joint goes outwards (ie positive in your explanation)? (Because its exerting an opposing force to that which is exerted upon it, like Newton said?) Our lecturer explain it to us that way and im slightly confused now haha
thanks for the help but I think u made a mistake while so I ng for the moment about N. one of the downward forces of 10 you wrote with a distance of 15 when it should be 10 . but other than that great video
i already gave this a subsrcribe but i have got a question why r u not takin in accoutn for the 10 n forces accting at the joints when u are doing the sum of the Fy compopnets at certain point?
at 9:46 I don't understand where you get all these numbers. I know they come from the Truss, but you just say them list them all without any explanation where they are coming from. I'm trying to do studies aboard in France and they only use letters for their equation and makes it even less clear. I was able to understand everything up to 9:46.
When you are taking the moment about N why do you have F(de) as a negative when both the x and y components are in the positive? Thank you for the videos by the way
If I take the moment about point N instead of point E, will I still be able to isolate the force DE by itself? Since NE and NM will be in the same line of action (?)
Hello, would it be possible to do this same problem but using the other half of the truss. I started it and got Fmn= 33.33 in tension, but i am having a really hard time finding the other two forces.
I got completely different answers. I don't think I did anything wrong. I got DE as -49.58k. NE as 325k and NM as 41.67k I first found the support reactions. Ax as 0, Ay as 35K, and Iy as 35k then I took the moments about point N Sum(M) at N -9xDEsin(59.036)+5x10+10x10-35x15=0 which gives me DE= -49.58k (in compression) then I took moments about point A Sum(M) at A -5x10-10x10-10x15+NEsin(67.38) NE=325k in tension After that I just took the summation of all the forces along x axis. Sum(F) along x -48.59Sin(59.036) + NM=0 which gave me 41.67k (in tension) Can anyone confirm if these answers are correct or not?.
I tried using truss solver softwares and its giving me 48.591 for DE (in compression) which is correct. 21.667 for NE (in tension) which is different from what I got. And 33.333 (in tension) for NM.
Figured out the mistake in my calculation. Didn't multiply NEsin(67.38) with the length 15. After making this correct I get the NE as 21.667 which is correct.