Moment of a Force | Mechanics Statics | (Learn to solve any question)

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Learn about moments or torque, how to find it when a force is applied at a point, 3D problems and more with animated examples. We talk about the line of action, breaking forces into components and using that to find moments, and resultant moments. We also go into using the cross product to figure out the moment as well.
🔹Breaking 2D forces into components: • Vector Addition of Cop...
🔹Forces Along a Line (3D forces): • Force Vectors Along a ...
🔹Finding the Cross product: • How to Solve a Scalar ...
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Intro(00:00)
Determine the moment of each of the three forces about point A. (02:24)
The 70-N force acts on the end of the pipe at B. (04:30)
The curved rod lies in the x-y plane and has a radius of 3 m. (05:25)
Determine the moment of this force about point A. (06:28)
Determine the resultant moment produced by forces (06:58)
Find more at www.questionsolutions.com
Book used: R. C. Hibbeler and K. B. Yap, Engineering Mechanics Statics.
Hoboken: Pearson, 2017.

Опубликовано:

1 июл 2024

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Комментарии : 512

@QuestionSolutions 2 года назад

⭐⭐If you'd like to see more examples covered and at the same time support the channel, please see: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-nPvG1bYFbko.html ⭐⭐ 🔹Clockwise moments positive, or counter-clockwise positive? ru-vid.comP029mqnp4XY 🔹Please note there is a typo at 6:23. The "k" term is negative, not positive, so it's {-128.34i + 128.34j - 256.68k} 🔹At 6:31, there is a typo in the question, we are finding the moment about point B, NOT A. This is a typo in the question only, all steps are correct. 🔹When to use sine or cosine: ru-vid.comvynnKlJD_Jo

@moonbunnies5216 2 года назад

Hi sorry for bothering. For the j term in the same timestamp you've provided, I can't seem to get positive j. 4(-42.78)-(-2)(21.39) = -128.34

@moonbunnies5216 2 года назад

btw thank you so much for these videos. Its really helping me a lot you have no idea how thankful I am to have found this channel.

@QuestionSolutions 2 года назад

@@moonbunnies5216 Since this is the second multiplication, it will have a negative in front first, so it will be like this: -[4(-42.78)-(-2)(21.39)]. You can always double check using this website: onlinemschool.com/math/assistance/vector/multiply1/ . Simply plug in the 2 vectors. And you are very welcome, glad to hear these videos are helping :)

@moonbunnies5216 2 года назад

@@QuestionSolutions oh my god I totally forgot about the formula for that, should've checked myself before commenting, thank you so so soo much for letting me know.

@QuestionSolutions 2 года назад

@@moonbunnies5216 Happens to everyone I think :) Best wishes on your studies!

@alienx097 2 года назад

Completing my Engineering from RU-vid University of Engineering and Technology

@QuestionSolutions 2 года назад

Best wishes with your studies!

@divineobot1605 8 месяцев назад

For realll😂😂😂😂❤

@aadhilhasan7815 7 месяцев назад

Best RU-vid professor😊 thanks a lot

@user-dh9ry2hj5z 6 месяцев назад

Same condition same place 😂

@user-ro8gk9tf2k 5 месяцев назад

Which engineering program?

@1Katula 3 года назад

well I'm obviously subscribing. I have been struggling with this topic for a while and your video just helped me get it. 1 step closer to becoming an engineer thank you : )

@QuestionSolutions 3 года назад

That's really awesome and I am super glad you got it :) Thank you so much and I wish you the best on your journey to become an awesome engineer!

@j.d.b.7581 Год назад

Same here✨

@ivoryas1696 4 месяца назад

@@QuestionSolutions Awesome. Thanks dude. 👌🏾

@adinadjiressem6669 Месяц назад

@@QuestionSolutions Very Smart

@zoelogan1841 2 года назад

Thank gosh I found you! I was struggling so much with moments and now I know it's the PERPENDICULAR distance. Thank you so much :)

@QuestionSolutions 2 года назад

Haha, yes, perpendicular distance :) Glad to hear this helped!

@BigSmokeEnthusiast Год назад

Your honestly one of two best tutoring channels for physics in all of YT. Continue making quality vids bro!! (also new sub)

@QuestionSolutions Год назад

Thank you so much for your kind words! Really nice of you :) I will do my best to continue the channel.

@brownbearedurardo 2 года назад

I am here just for the recap since most of the engineering lessons I took required this procedure to solve problems. Thank you! You discussed better than my college instructor. Specific and concise!!!

@QuestionSolutions 2 года назад

I try my best to make them as concise as possible :) Best wishes with your finals!

@danconte954 2 года назад

You deserve my subscribe! I hope all students trying to learn this lesson would see this video. Thanks for the tutorial. Keep it up.

@QuestionSolutions 2 года назад

Thank you very much! :)

@kidusteshome8440 3 месяца назад

you explained the whole topic and worked all possible types of problems related to this topic in just 8mins! you're amazing!

@QuestionSolutions 3 месяца назад

Thank you very much!

@bigiron4018 2 года назад

Awesome, so helpful. I was having trouble with this topic, watched the video, worked some practice stuff out on paper and cruised through the rest of my homework on this subject. Thank you!!

@QuestionSolutions 2 года назад

You're very welcome. You're doing exactly what I hoped students would do :)

@RedSarGaming 2 года назад

Coming from a class with a curriculum that doesn't follow the book to the T, this is such a great way to get study/example problems. THANK YOU SO MUCH!!!!

@QuestionSolutions 2 года назад

You are very welcome! I hope you gain a firm grasp of the materials and do amazingly on your exams!

@nicerice9689 2 года назад

You are doing god's work my man, bless your soul holyyyyyy, Keep doing what you're doing man

@QuestionSolutions 2 года назад

Many thanks! I wish you the best on your studies.

@sbarz106 2 года назад

Thank you so much you've saved me, in just minutes you managed to explain better than hours of lectures!

@QuestionSolutions 2 года назад

I am really glad to hear that :) Best wishes with your studies!

@Tay7r Год назад

Same bruh, my professors can't teach shit

@sadhananarendar2992 2 года назад

Excellent explanation. Thank you very much. Very well explained. The best part is explaining the solution really fast and also clearly.

@QuestionSolutions 2 года назад

Thank you so much for your nice comment. I really appreciate it.

@randomname1392 2 года назад

tysmmmm I've been trying to figure this out on my own for an hour now and you just made it all clear now I'm definitely going to like and subscribe

@QuestionSolutions 2 года назад

Thank you so much, really glad to hear it was helpful! Keep up the awesome work.

@BilboBagends 2 года назад

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@QuestionSolutions 2 года назад

Many thanks!! 👍👍

@pimientopicante3870 2 года назад

Thnx so much for explaining it! I had mix feelings about this topic since my professor went over it fast

@QuestionSolutions 2 года назад

I hope it was helpful to you. Best wishes with your studies!

@Eng.ZeinYassin 5 месяцев назад

May God bless you, your family, and your knowledge that you spread. You have made me understand, so I ask God Almighty to increase you and bless the goodness in you and increase you. Syria🇸🇾🥇

@QuestionSolutions 5 месяцев назад

Wow, thank you very much, that was a really nice comment. I wish you the best in your studies and all your future endeavors!

@vincentadams686 2 года назад

You made this subject come out so easy, thank you! I'ma go pass a test!

@QuestionSolutions 2 года назад

Awesome! Give it your all and I wish you the best on your test!

@ummiaisyah7560 2 года назад

I cant be thankful enough to came across ur vids!! definitely helps me to understand it like whatttt soo much better than my actual lecture. And the fact u r replying to all the comments is amazing and i get to learnt from others comments too! great job really, keep doing what u r doingg thank u veryy muchhhh

@QuestionSolutions 2 года назад

Thank you for your kind comment and I am very happy to hear that these videos help. Keep up the awesome job and I wish you the best with your studies! :)

@ummiaisyah7560 2 года назад

@@QuestionSolutions Will do my best and thank youu for the wishh!!!

@QuestionSolutions 2 года назад

@@ummiaisyah7560 You're very welcome!

@nobodywillsner1063 Год назад

Thank you! Been sitting in class not understands a thing and saw this video and now i get it.

@QuestionSolutions Год назад

Glad it helped! Best wishes with your studies.

@A1M2099 3 года назад

5x faster than my prof.

@QuestionSolutions 3 года назад

👍😁

@aaqibkhursheed9523 3 года назад

And its easier to understand 😃😂

@d7o0myalshlaly59 Год назад

5x better

@trevorclark7985 Год назад

honestly, my professor makes this stuff seem like rocket science with how bad he is at teaching it

@muhammedyamenabdulhadi8840 2 года назад

thanks for the awesome explanation methods you just made the subject extremely easier

@QuestionSolutions 2 года назад

I am really glad to hear that! Best wishes with your studies.

@jesustheodore5126 2 года назад

Thank you so much, Great Video! it was very helpful for my statics exam!

@QuestionSolutions 2 года назад

I am very glad to hear that :) I hope you did well on your exam.

@cr7kambole422 2 года назад

I have been struggling with this chapter in Applied Mathematics, Thank you very much, now i trust myself fully in Moments, i also subscribed to your channel and sent the link to my fellow varsity mates

@QuestionSolutions 2 года назад

I am really happy to hear that and I really appreciate your subscription and the share. Means a lot and I wish you the absolute best with your future studies! Keep up the good work 👍

@abillejadzrich5551 2 года назад

i love the way of ur teaching where u focus on concept

@QuestionSolutions 2 года назад

Glad to hear :) Best wishes with your studies!

@patrick-mn6du Год назад

Well, I am subscribing, your precise and clear, exactly what I have been looking for.

@QuestionSolutions Год назад

Thank you very much! :)

@koala1084 2 года назад

Gorgeous explanation, thank you!

@QuestionSolutions 2 года назад

You're very welcome!

@easymoney7344 3 года назад

Damn man im really happy i found your channel man💓💓 i read a lot of book but its kind of confusing. While you explain it very simple. Thank you man I already shared your videos to my classmates since it is very helpful💓

@QuestionSolutions 3 года назад

Thank you so much 💓 I really appreciate your comment and the shares, super nice of you! 💓💓💓💓

@justinbailes9576 9 месяцев назад

been lost for so long dropped the class once already and watched this video and now everything makes sense

@QuestionSolutions 9 месяцев назад

I’m really glad to hear that the video was helpful for you! It’s not uncommon to feel lost when learning something new, and it’s great that you didn’t give up. Do you best, keep going, you’re doing great! 😊

@blans316 2 года назад

Your videos are so amazing, thank you!

@QuestionSolutions 2 года назад

Thank you for your kind comment! I hope they are very helpful to you.

@fish9008 2 года назад

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@QuestionSolutions 2 года назад

You're very welcome! Keep up the great work, best wishes with your studies.

@janecm6136 18 дней назад

Thank you. I think I get it now. I’ve been stressing and struggling summation of forces and moments. I think I finally got the principle. It’s just that the figure is overwhelming me but I think I’m almost at it now. I’m definitely subscribing ❤

@QuestionSolutions 18 дней назад

Thank you very much. I am sure you will get it, just practice a few problems and follow along the examples :) I wish you the absolute best with your studies!

@balajivelpula2435 3 года назад

Crystal clear explanation

@QuestionSolutions 3 года назад

Many thanks!

@GurbetciAri 7 месяцев назад

Great examples, thanks!

@QuestionSolutions 7 месяцев назад

Glad it was helpful!

@nataliatothemoon 2 года назад

Praying Tanaka has a suggestion: may you include sample problems where we are given angles and not just lengths? It would be very helpful 🌝 🙏

@QuestionSolutions 2 года назад

I am not sure I understand what you mean? You need distances to calculate a moment, or you use the angles given to figure out the distances first. Could you elaborate on what you would like to see? :)

@carolineee359 2 года назад

It is soooooo helpful! Thank you!!!!

@QuestionSolutions 2 года назад

You're very welcome!

@kaankaraman9850 Год назад

You ara amazing man. I loved it. I was struggling but now i know what to do

@QuestionSolutions Год назад

I am glad to hear that! Keep up the good work.

@Evanescence29 2 года назад

dudee you're such a legend!!!

@QuestionSolutions 2 года назад

Thank you :)

@kiran4456 2 года назад

Great explainations 👏, hope for more videos 👍

@QuestionSolutions 2 года назад

Awesome :) Thank you so much! 👍👍👍👍

@clamp202 2 года назад

Clear explanation, thanks

@QuestionSolutions 2 года назад

You're very welcome!

@cemileceylan1017 Год назад

Perfect explanation!

@QuestionSolutions Год назад

Thank you very much!

@graceobeng4165 3 года назад

I really enjoyed it, thanks

@QuestionSolutions 3 года назад

Glad to hear :) You're very welcome!

@eiadm2047 2 года назад

Thx for your great effort! In the last problem, If we wanted to use position vector OA, what force should we use when doing the cross product?

@QuestionSolutions 2 года назад

The forces remain the same, only the position vector changes. So when doing the cross product, you would use rOA. 👍

@mohammedabdulnoor1615 2 года назад

You earned my subscription 👍

@QuestionSolutions 2 года назад

Thank you very much, I really appreciate it. 👍

@sujalbhatu999 5 месяцев назад

thank you so much brother

@QuestionSolutions 5 месяцев назад

You are most welcome.

@jordanchongo3752 2 года назад

absolutely fantastic 👏👏

@QuestionSolutions 2 года назад

Thank you :)

@azizalbassam3132 2 года назад

Wow, you are a lifesaver

@QuestionSolutions 2 года назад

Glad to hear!

@kyordannydelvalle523 Месяц назад

Wow, Even after graduating. I still remember how to do it. Just needed to refresh my memory a little.

@QuestionSolutions Месяц назад

Congrats on graduating and well done for remembering!

@ThecarsHQ 2 года назад

please i'd like to ask if the position vector could be from anywhere like Rac instead of Roc

@QuestionSolutions 2 года назад

Please kindly provide a timestamp to the place you're referring to.

@santiagoperez633 2 года назад

You are my hero. Thank you

@QuestionSolutions 2 года назад

Many thanks!

@ramkakaduke7423 4 месяца назад

God bless you man whoever you are

@QuestionSolutions 4 месяца назад

Thank you very much! Best wishes with your studies.

@atherbukharii 2 года назад

The best video on RU-vid, nothing better than this but could have been the best video in the galaxy if video was a bit slow. Edit: by bit slow i mean 10x slower

@QuestionSolutions 2 года назад

Thank you for your feedback. :)

@ichione732 Год назад

tyssm u ddont know how much youve helped me for this

@QuestionSolutions Год назад

You're very welcome! Keep up the great work and best wishes with your studies.

@user-hg5jv9nq9f День назад

Thank you so much ❤

@halleighfaulkner3963 3 месяца назад

for the fourth example, why are you using the position vector for BC if you're taking the moment about point A? would you not use AC?

@QuestionSolutions 3 месяца назад

There is a typo in the question, the moment was suppose to be about point B. I wrote a pinned comment about this too because I get asked it so many times. 😅

@humphrey6630 8 месяцев назад

Thank you so much.

@QuestionSolutions 8 месяцев назад

You're very welcome!

@yuzarsif3586 2 года назад

thank you so much, u r a holly person!

@QuestionSolutions 2 года назад

You're very welcome!

@footballclips5013 10 месяцев назад

Sir at 2:45,when finding the components of x and y for F1,why did you use sin for the x-component instead of cos and cos for the y-component instead of sin? Or am I mistaking please?

@QuestionSolutions 10 месяцев назад

Please watch this: ru-vid.comvynnKlJD_Jo?feature=share It'll clear up all your doubts. :)

@rorygame5835 Год назад

Great video! Really helped me wrap my head around this. With the curved rod question, wouldnt the k-value of the cross-product be -256.68k? ((4 x -64.17)-(0x21.39)=-256.68k) Otherwise it wouldnt be perpendicular to the plane created by the two vectors.

@QuestionSolutions Год назад

Glad to hear it was helpful. :) And yes, I have a pinned comment with the typo corrected. 👍

@SuperLions7 2 года назад

Hello, I have a little mental hurdle that I'm trying to overcome which is represented at 3:58 does the line of action change, and does it become parallel to the black line representing the support at point A?

@QuestionSolutions 2 года назад

I assume we are talking about the 400 N force? If so, the line of action is always with respect to the force. So if we extend the orange dashed line backwards and forwards, that is the line of action. If that line crosses point A, then it can't create a moment. Here, that line of action is 5 m away from point A.

@coylezxs 2 года назад

@ 7:50 I think the j in MOB is - 0j since the j should be negative (not that it matters since the value is still 0)

@QuestionSolutions 2 года назад

I don't assign negatives to zeros. It's neither positive or negative, it's just zero because -0=0 also, to me, positive "looks" nicer 😅

@adriannavarro1345 Год назад

I love this man

@QuestionSolutions Год назад

❤

@btw_itachi_uchiha Год назад

amazing helpful

@QuestionSolutions Год назад

Thank you very much!

@ashlynraj6939 2 года назад

At 2:41 Why did you use the horizontal component of F2 for F2x instead of the vertical component like in F1?

@QuestionSolutions 2 года назад

Okay, so I think what you're actually asking is, why did I use cos for F2x, but use sin for F1x, and you are assuming cos and sin are related to horizontal and vertical components. If this is your question, please erase that thought out of your head. Sin and cos are NOT related x/y/horizontal/vertical components. They are purely based on the angle and it's corresponding side. I have no idea where students get this notion from, but please make sure you don't think like this. 😅I really encourage you to look at this video (ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-NrL5d-2CabQ.html), it's not long, and if you're really tight on time, just watch the first example. It will give a very good foundation for working with sin/cos and how to properly use them. I break it down step by step and by the end you will never get confused again but sin and cos. If this isn't what you're asking, I am not too sure I understand your question. Maybe rephrasing it might help me, if so, I am sorry :(

@mustakinahmedantuplasticst3912 Год назад

I love you as a teacher

@QuestionSolutions Год назад

Thank you very much! :)

@DARTH-R3VAN 2 года назад

Look at this legend

@QuestionSolutions 2 года назад

:) Many thanks!

@dennardleonard1228 Год назад

This is the best video

@QuestionSolutions Год назад

Thank you very much!

@mpadithyaanoopnambiar7835 3 года назад

You Deserve a Globe's Best Teacher Award 🤩

@QuestionSolutions 3 года назад

🤩 You're too kind!

@freakingik2781 3 года назад

Yes,he indeed deserves it. God bless u.....

@QuestionSolutions 3 года назад

@@freakingik2781 :)

@johnboeger595 2 года назад

Can you please explain where the line of action is in the flagpole example? I'm assuming the line of action is up and down the flagpole

@QuestionSolutions 2 года назад

Your assumption is correct. If we have a force directly along the flagpole, there would be no moment created.

@lostsky3631 8 месяцев назад

Was studying these same things for four hours and didn't understand a single thing. Can't believe I just understood everything in 8minutes😂😂I appreciate 🙏

@QuestionSolutions 8 месяцев назад

I am really happy to hear that! Well done and keep up the awesome work :)

@user-qo3yf8ge5z Год назад

A uniform metre scale of mass 200 g carries of a block of mass 800g at one of its end .At what distance from the same in end does does a knife and balance the scale?

@QuestionSolutions Год назад

Sorry, I don't solve questions like this because then I have to solve everyone's problems 😅 I encourage you to use math/physics forums if you need help with a specific question.

@nacure360 Месяц назад

For example 3, if r is the position vector from the point where we take the moment about to any point along the line of action of the force, can r be the position vector from O to A? if I do that i get -128.4i +128.4j -256.08k? (the only difference is the sign of the z component to your answer).

@QuestionSolutions Месяц назад

You absolutely can. I have a typo in my answer (see pinned comment). Your answer is correct.

@nacure360 Месяц назад

@@QuestionSolutions ohh thank u

@ZMANthegreat 2 года назад

great content..keep it up

@QuestionSolutions 2 года назад

Thank you very much!

@avinashmbhat4256 2 года назад

This is soo good

@QuestionSolutions 2 года назад

Thank you very much! I hope it was helpful.

@harshmangukiya91 5 месяцев назад

amazing!

@QuestionSolutions 5 месяцев назад

Thank you!

@itsmemags4778 5 месяцев назад

Isn't F1x be equal to cos(theta)? since cosine represents the x-axis while sine represents the y-axis?

@QuestionSolutions 5 месяцев назад

Please, take 1 minute and watch this video: ru-vid.comvynnKlJD_Jo That is incorrect, and you must erase that thought from your mind. You will lose so many marks on your exams from that view point, and I have no idea where students got this idea from.

@Hadi_Yahia 3 года назад

Thank you so much :D !!

@QuestionSolutions 3 года назад

You're very welcome!

@The.Wonderful.Inspiration.Of. 10 месяцев назад

Hello, I think there is a mistake at 6:23, Roc should be Roa since the starting point of the force is A no ? Or maybe I don't know the rule well ^^ Edit : Well I just heard "position vector from point O to any point of the line of force action", I learned that thank you :)

@QuestionSolutions 10 месяцев назад

Yes, as long as the vector goes to any point on the line of action of the force, you will get the same answer 👍

@Ijee12 3 месяца назад

Hi, i thought clockwise direction was negative and counterclockwise was positive or it doesn't matter?

@QuestionSolutions 3 месяца назад

See pinned comment.

@scofield1602 Год назад

THANK YOU

@QuestionSolutions Год назад

You're very welcome!

@chemicalvideobee2993 Год назад

bro helped me understand a whole chapter I skipped 2 hours before the test

@QuestionSolutions Год назад

That's great! Keep up the good work :)

@DraftingCADemy2023 8 месяцев назад

6:23 shouldn't be 256.68 a negative (-)? Since we alternate our operations in doing matrices + - + last term should be + [(4)(-64.17) - (0)(21.39)] which results to - 256.68. Please correct me if I'm wrong.

@QuestionSolutions 8 месяцев назад

Please see pinned comment. You are correct, it's a typo. 👍

@DraftingCADemy2023 8 месяцев назад

@@QuestionSolutions Thank you!

@ArmyLover-kn1qd 2 года назад

Your videos are great!! Would you please be able to do a video on torsion as well as equations of elastic curves (deflection/ flexure formula)?

@QuestionSolutions 2 года назад

Thank you very much and I will definitely add it to my list of videos to make :)

@ArmyLover-kn1qd 2 года назад

@@QuestionSolutions Thank you!

@ThunderGowPlayer 2 месяца назад

Hi, I have a question, why in 5:45 we get the position vector from OC and in 6:41 its from BC? That wouldn't mean that our position vector in 5:45 should be from O to A? I have tried that and it will change the values of the momentum vector

@QuestionSolutions 2 месяца назад

You can take it from O to A, and you will get the same answer. There will be no difference. You most likely wrote down an incorrect position vector. The position vector OA would be 3i+3j+0k. Keep in mind that there is already typo in the solution for that question as mentioned in the pinned comment. The answer for that problem is -128.34i+128.34j-256.68k. Whether you use a position vector from O to C or O to A, you will get the same answer.

@ThunderGowPlayer 2 месяца назад

@@QuestionSolutions Oooh, I just checked, and you are right! I was messing up with the position vector, but yeah, when you do it with 3i+3j+0k, you get the same answer. Sorry for the confusion. Thank you for your help and answering my comment, even though this video is 3 years old! New subscriber

@QuestionSolutions 2 месяца назад

@@ThunderGowPlayer You're very welcome. I am glad you got it :) Keep up the great work and best wishes with your studies.

@johnnym500 11 месяцев назад

For the first question, when solving the moment for M3: Shouldn't it be -300n(5m)+400N(4)?

@QuestionSolutions 11 месяцев назад

So remember, we are looking for the perpendicular distance. F_x is horizontal, so we are looking for the vertical distance from point A, that's the perpendicular distance, which is 4m. F_y is vertical, so we are looking for the horizontal distance from point A and that's 5m.

@ruxandradanetiu1726 2 года назад

For the last problem, why do we have to add the momentum of the two forces, if they are operating in opposite directions on the same tower?

@QuestionSolutions 2 года назад

The word "resultant" indicates that whatever you find, whether it's separate forces, moments, etc., must be added together. It's really just showing a single moment instead of 2. Another way to think about it, is to realize that the resultant shows the result of multiple forces/moments acting at a singular point.

@kriistyy. 4 месяца назад

in 6:13 , I used the position vector OA. Why the direction of Z axis of my moment is -256.62 and not 256.2. Is it wrong?

@QuestionSolutions 4 месяца назад

It should be negative. Please show me the position vector you got. Thanks!

@viva7416 25 дней назад

Sir,here is the moment when I use the position vector OA. Mo={ -128i + 128.34j - 256.68k } rOA= { 3i +3j +0k } So if there's not any mistake the Moment must be the same for both position vector rOA and rOC. isn't sir Thanks a lot for ur help 😊😊

@melyvaleriabanuelosvazquez959 Год назад

At 4:25 it was mentioned clockwise was positive, while I’m aware that counterclockwise is positive while clockwise negative, could you explain? as I’m confused now 😢

@QuestionSolutions Год назад

You can use whatever way you want to be positive. If you like counter-clockwise to be positive, you can solve it that way. Regardless, you will end up with the exact same answer. :)

@darrenwood3826 Год назад

Thanks for your help in this topic was wondering that isn't turning clockwise should be negative?

@QuestionSolutions Год назад

You can pick either direction, it makes no difference as long as you follow through with your positive and negative signs. So for example, assume you picked counterclockwise to be positive, then if you get a negative answer, the moment is clockwise. If you picked clockwise to be positive and you got a negative answer, then the moment is counterclockwise. If you picked counterclockwise to be positive and you got a positive answer, then the moment is counterclockwise. Lastly, if you picked clockwise to be positive and your answer is positive, then it is clockwise.

@darrenwood3826 Год назад

@@QuestionSolutions Thank you

@Ralphvanderburg Год назад

5:00, isn't the answer in NM? Since it is force times distance like you said before for moments?

@QuestionSolutions Год назад

Yup, that's a typo. Good catch!

@sewanusunday9605 2 года назад

Thanks Man👍

@QuestionSolutions 2 года назад

You're very welcome! 👍👍

@baktybek6454 2 года назад

2:45 where did you get this numbers like 250cos30, 300cos60, 500*4/5 , all this numbers?

@QuestionSolutions 2 года назад

So all of those numbers are forces broken into x and y components. If you need a refresh, please see: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-NrL5d-2CabQ.html

@HAYETMAAMEADWOAGYASIWAADABANKA Год назад

at 4:53 why isnt the fx+0 because its along the line of action pf the force plus how are you able to tell if the fx is clockwise or anticlockwise

@QuestionSolutions Год назад

It's not along the line of action. You need to look at it with respect tot he point where we are calculating the moment. In this case, it's about point A. You can tell if it's clockwise or counter-clockwise by imagining the piece rotate around point A. It's easier to visualize if you cut out a piece of cardboard, pin it at A, and then push with your fingers. See how it rotates and then you will get a feel for it.

@jordanchongo3752 2 года назад

If we take clockwise to be negative and anticlockwise to be positive we get different answers foe the moment, is it advisable to always take clockwise as positive unless stated otherwise?

@QuestionSolutions 2 года назад

What you are saying is not possible. The direction is simply an assumption. For example, you can assume clockwise to be positive. In that case, if you get a positive value, then your moment is clockwise, and if you get a negative value, it's counterclockwise. Now if you pick counterclockwise to be positive, then if your answer is positive, your moment is counterclockwise, and if your answer is negative, it's a clockwise moment. I pick clockwise to be positive because it's a preference. You can pick either to be positive. Make sure you follow through with your direction and use proper positives and negatives, you will end up with the same answer. 👍

@jordanchongo3752 2 года назад

@@QuestionSolutions ohk, thank you 🙏

@leulmak3468 2 года назад

thank you

@QuestionSolutions 2 года назад

You're very welcome!

@ponarapholo7885 4 месяца назад

How do I do the cos product, how do I apply that formula there

@QuestionSolutions 4 месяца назад

Please see: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-F8IHrg3pc7g.html

@Raniaska0306 Год назад

I'm still amazed by how you explained everything in 8 minutes which took my professor at least 2+ hours to explain XD

@QuestionSolutions Год назад

😅I hope it was helpful and keep up the good work!

@gangstashuckle Год назад

Top G lesson

@QuestionSolutions Год назад

Many thanks! 👍

@anasmalek4623 3 года назад

Hey sir at 4:12 wouldn’t both components be negative instead of just one coz the fy component is going down

@anasmalek4623 3 года назад

Nvm just remembered it moment so instead it’s whether it’s ccw or cw that determines the sign

@QuestionSolutions 3 года назад

@@anasmalek4623 Yes, it's based on clockwise or counter clockwise not the direction of the force. We just have to see whether the force, (doesn't matter which way it's pointing), will it create a clockwise or counter clockwise moment. 👍

@ewmx1255 Год назад

In the first problem, why does the x component of F3 create moment if the direction of the x component is parallel r to the line of action on A?

@QuestionSolutions Год назад

So you have to always keep an eye out for perpendicular distances. Notice how there is a perpendicular (vertical) distance of 4m between point A and the x-component of force 3.