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Momentum thickness of boundary layer 

Amit Mandal
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Correction: 7:43 and ahead , kindly read u/U as U/u, Its a typo error.
When a fluid flows over some surface and boundary layer is formed, then the velocity of fluid inside the boundary layer becomes less than the free stream velocity. This lead to loss of momentum within the boundary layer. To compensate the momentum loss at a particular point of surface , we can increase the vertical height of free stream velocity up to some level called as momentum thickness. This lecture analyzes the same and derivation of momentum thickness is narrated...

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22 авг 2024

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Комментарии : 16   
@ashvanigupta5871
@ashvanigupta5871 5 лет назад
In dP(U) you take mass flow rate with small u while when there is no shear effect ( no boundary layer) mass flow rate should be taken with capital U i.e. dP(U)= §.b.dy.U^2
@johnysingh5023
@johnysingh5023 4 года назад
This is because the momentum loss is computed for that mass which is in boundary layer i.e. pbdyu , not for the free stream mass.
@-GDEEPAK
@-GDEEPAK 4 года назад
Sir please check the loss of momentum equation after taking U^2 in common It's wrong.. please check it once
@bijoybasumataryy8870
@bijoybasumataryy8870 2 года назад
What a God
@LuckyWitjaksono
@LuckyWitjaksono 4 года назад
Thank you for the Lecture, Helped me a lot since i cannot interpret the physical form of teta thank you
@numankumar6067
@numankumar6067 4 года назад
Lovely explanation Guru ji I was wandering here and there for displacement thickness But this diagram used for explanation is mind blowing 🥰🥰🥰🥰🥰🥰
@numankumar6067
@numankumar6067 4 года назад
I hope momentum thicknesses will get that momentum 😋
@EpicShowDailyOfficial
@EpicShowDailyOfficial 2 месяца назад
sir what is the reason of not putting capital U in the dPU why you took u in that equation i didint get it pls explain
@Dr.AmitMandal
@Dr.AmitMandal 2 месяца назад
U is a constant, u is variable, dU is 0.
@VIJENDRAKUMAR-mh6lk
@VIJENDRAKUMAR-mh6lk Год назад
Sir in finding momentum change you have taken U^2 common then in bracket we will gaye (u/U) not U/u
@Dr.AmitMandal
@Dr.AmitMandal Год назад
Yes typo mistake, kindly consider corrected i.e. take it u/U.
@ayeshasiddika1869
@ayeshasiddika1869 2 года назад
Thanks
@parthsharma2611
@parthsharma2611 5 лет назад
First of all it's mass flow rate and not just dm. And how did you write that momentum equation like that? Mass flow rate without boundary layer will be ¶(∆a)U Mass flow rate with boundary layer for same cross section should be ¶(∆a)u Now how do you write the momentum equation for varying mass and varying velocity.
@Dr.AmitMandal
@Dr.AmitMandal 5 лет назад
The analysis is for per unit time...
@sudipsingh2414
@sudipsingh2414 5 лет назад
Is mass flow rate same for both boundary layer and free stream condition
@Dr.AmitMandal
@Dr.AmitMandal 5 лет назад
No , its lesser
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