MOSFET Common Gate Amplifier

Подписаться 60 тыс.

Просмотров 57 тыс.

50% 1

/ edmundsj
If you want to see more of these videos, or would like to say thanks for this one, the best way you can do that is by becoming a patron - see the link above :). And a huge thank you to all my existing patrons - you make these videos possible.
MOSFET common-gate amplifier gain, input resistance, and output resistance. This is one of the three core single-transistor amplifier configurations, and critical in understanding modern amplifiers.
Hope you found this video helpful, please post in the comments below anything I can do to improve future videos, or suggestions you have for future videos.

Опубликовано:

10 дек 2018

Ссылка:

Скачать:

Готовим ссылку...

Добавить в:

Мой плейлист

Посмотреть позже

Комментарии : 35

@omni3630 2 года назад

Wonderfully explained. I've 'studied' this amplifier many times over the decades, but this is the most elegant explanation!!

@manuelfreitas7165 4 года назад

Thank you sir. I learned more here in 12 min than in my 5 classes about this topic

@Harrygolfs 5 лет назад

Thanks for taking the time to make these

@patrickbuchanan2273 2 года назад

Thank you for taking the time to make this.

@keerthi5051 Год назад

Thank you soooo much for all the three videos on amplifiers using MOSFET

@UsamaAhmedZeki 4 года назад

Thank you VERY VERY VERY MUCH, i relied on memorizing the formulas instead of understanding, Thank you once more

@MohamedHassan-zi7ms 4 года назад

wow!! you made me take it easy .. all of thank from egypt

@MohamedFazal 4 года назад

Wow. You just made this a lot simpler.. thanks..

@armenpirenyan9455 6 месяцев назад

It was a really useful lesson, thank you)

@jasonlau6959 4 года назад

Thank you , really learned alot from this video

@foreverfugazi245 8 месяцев назад

7:55 Truth always comes out unexpectedly... 😢 Thanks for the content, and the warning

@Bingong556 Год назад

Great channel helped me out big time already

@Steve-GM0HUU Год назад

Very nice explanation, thank you.

@fatmacn724 4 года назад

Thank u sir. From Türkiye!!

@jamali-azmi 8 месяцев назад

Explained Well 💚

@adityaaman3231 Год назад

Very nice explanation 😁

@oguz8153 5 лет назад

Thank you sir.

@om8943 Год назад

Sir thank you so much , my professor just reads through stuff instead of explaining .

@huwinner2428 3 года назад

why cant my professors explain this like you do? They never told me that you could just "test" for the input and output resistance. My textbooks don't even mention it!

@aaronwilson1086 3 года назад

I'm brand new to diving into electric power supplying or anything , being spurred from car audio....twenty years later who knew I actually enjoy learning this stuff. And using a soldering iron. Lol

@nahsam 5 лет назад

This is great

@user-kb4eu7ex8g 3 года назад

you save my life

@bbhh-ud9zo Год назад

thank you so much

@harikaharika6842 Год назад

U helped alot sir thank you sooooo much🤩🤩

@yusufklc1184 5 лет назад

excellent

@user-yc2er6iu8f Год назад

I'm wondering what the six hidden videos're. WONDERING...... ;)

@user-mj3ef 5 лет назад

How can we see the list of all videos? Is there any video on biasing? If we become member through patreon are there other videos? But if so I would like to ser the topics before I do that. Is it possible?

@TechnicallyExplained 3 года назад

ru-vid.com/group/PLTzDL2E_M0E79Dp1zuSXL6rQ79F9TQhI7

@aishikdas 4 года назад

Just a confusion will not the drain or the output be grounded as if not then Itest will not be equal to gmvgs but will be kcled with Rd.

@shreyanarayan1333 2 года назад

Thanks for the video! Can you explain how the analysis would change for a PMOS vs. an NMOS?

@JordanEdmundsEECS 2 года назад

In a PMOS, you basically swap Vgs for Vsg and you swap the direction of the current. It ends up being very similar, so it usually gets short shrift.

@AvadaKedavra943 3 года назад

What if Vin is supplied with a voltage source Vsig with source internal resistance Rsig? How does Rsig affect the analysis?

@JordanEdmundsEECS 3 года назад

Great question. You'll have a resistive divider between the source and the amplifier. If you know the amplifier's input resistance (this is something you can calculate), then it's as if the voltage is just smaller by the factor of the voltage divider. Everything else is the same.