Na2CO3 + 2HCl = 2NaCl + H2O + CO2. Using this equation, what volume of carbon dioxide, measured at.. 

Hello everyone, in this video, we'll be solving the question below;
Na2CO3 + 2HCl = 2NaCl + H2O + CO2. Using this equation, what volume of carbon dioxide, measured at s.t.p is liberated when 53g of sodium carbonate is dissolved in hydrochloric acid? (1 mole of gas occupies 22.4dm^3 at s.t.p.) (Na = 23, C = 12, O = 16)
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