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Newton's 2nd Law (3 of 21) Calculate Acceleration w/o Friction, Net Force Above the Horizontal 

Step by Step Science
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Shows how to calculate the acceleration of a mass using Newton's second law of motion. The mass is moving across a surface without friction and the net force is above the horizontal.
The acceleration of an object is directly proportional to the net force applied to the object and inversely proportional to the mass of the object. The second law can also be stated in terms of an object's changing momentum, such that the rate of change of momentum of an object is directly proportional to the net force applied and the change in momentum is in the direction of the net force.
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21 окт 2024

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Комментарии : 48   
@nickpetrowski7182
@nickpetrowski7182 4 месяца назад
finally, videos that make sense! Too often physics teachers talk in circles too much about the "what ifs" thank you for being direct.
@stepbystepscience
@stepbystepscience 4 месяца назад
You're very welcome! I'm glad it was helpful for you.
@lamnguyen-bi8jm
@lamnguyen-bi8jm 9 лет назад
Awesome! u have literally saved my life with all the videos! Thank a lot for ur contribution to our society with these amazingly educational video.
@stepbystepscience
@stepbystepscience 9 лет назад
+lam nguyen Just trying to take a topic that seems a little complicated and break it down into manageable steps. Thank you very much for the positive comment.
@mr.olorinthemaia
@mr.olorinthemaia 4 года назад
Sir, I must admit I watch your videos with love. I'm from Eastern Europe, Romania, and in our country physics isn't taught well. The fact that I can understand these types of problems so well from your, sir, is unbelievable. Much love.
@stepbystepscience
@stepbystepscience 4 года назад
Very nice comment, thank you.
@georgeathan9475
@georgeathan9475 4 года назад
Greetings from Greece , currently preparing for master's exams in Human movement sciences and your videos are like heaven. Thank you very much !
@stepbystepscience
@stepbystepscience 4 года назад
Wonderful! Good luck with the exams and thanks for the comment.
@Thumbsme12
@Thumbsme12 11 лет назад
I just want to tell you how much I love you and that you probably saved my life and my final exam
@Juicyvale14
@Juicyvale14 7 лет назад
Thank you for taking the time to make this videos. I watched a few for my last test and they helped me so much. For this test I was trying to find your channel and I couldn't remember the name of your channel on my subscription list lol but I'm glad I've founded it. Now I feel much better after reviewing with your videos.
@stepbystepscience
@stepbystepscience 7 лет назад
Hopw the test goes well, thanks for commenting. You can see a full listing of all my videos at www.stepbystepscience.com
@sankagrero2042
@sankagrero2042 9 лет назад
These are amazing video! So simple and I can follow along quite easily. Just wish I found you at the beggining of the semester. Keep up the great work Mr. Swarthout!
@stepbystepscience
@stepbystepscience 9 лет назад
Sanka Grero Thank you, I put a lot of time into that series of videos and I think they turned out pretty good.
@sankagrero2042
@sankagrero2042 9 лет назад
Brian Swarthout Absolutely sir! And thank you for doing so.
@bellajagitay9964
@bellajagitay9964 2 года назад
this is beautiful the only channel that made me switch to premium
@stepbystepscience
@stepbystepscience 2 года назад
Thanks, glad you are here.
@harmonicposting
@harmonicposting 5 лет назад
nothing against my current teacher (hes a cool dude) but you are just amazing, concise and short explanations, simple and clean. thank you
@stepbystepscience
@stepbystepscience 5 лет назад
I try to just get to the point and explain everything step by step.
@ev3rn1ght89
@ev3rn1ght89 3 года назад
Thanks so much your videos are extremely helpful
@stepbystepscience
@stepbystepscience 3 года назад
Glad you like them! Most welcome.
@AdmiredDisorder
@AdmiredDisorder 3 года назад
this was so easy to understand, thank you
@stepbystepscience
@stepbystepscience 3 года назад
You're very welcome!
@bienramos7587
@bienramos7587 3 года назад
Very clear and detailed explanation.. thanks
@stepbystepscience
@stepbystepscience 3 года назад
You are very welcome
@SomiVelu
@SomiVelu 6 лет назад
6 X 9.8 = 58.8 btw and good job 👌🏿
@breayonnapearson2596
@breayonnapearson2596 7 лет назад
Great breakdown
@andrewogden1480
@andrewogden1480 11 лет назад
Thank you for the help. Your voice reminds me of Dustin Hoffman which helps to keep my attention.
@musaadebisi9105
@musaadebisi9105 4 года назад
U are nothing but a genius to me bro ! Much love please I need you to help me with projectile motion
@stepbystepscience
@stepbystepscience 4 года назад
Thanks for the great comment. I have videos on projectile motion, just search "step by step science projectile motion"
@musaadebisi9105
@musaadebisi9105 4 года назад
OMG I HAVE SEEN PROJECTILE MOTION VIDEOS THANKS
@katherine3257
@katherine3257 6 лет назад
You have made this so clear, the only thing that would make this playlist better is if they were automatically in order! lol
@stepbystepscience
@stepbystepscience 6 лет назад
I believe they are in order in this playlist. Newton's 2nd Law ru-vid.com/group/PLcJ1NYursFxhzXs4bqmXaeSWvHbZrSjpQ
@katherine3257
@katherine3257 6 лет назад
Step-by-Step Science it starts at video 13 of 21 on that playlist link :)
@katherine3257
@katherine3257 6 лет назад
I guess the "(13 of 21)" is what is throwing me off
@user-cp3id7du9e
@user-cp3id7du9e Год назад
Thanks for the video. Can you explain again why Fay has an acceleration of 0 again?
@stepbystepscience
@stepbystepscience Год назад
Good question! Because the only motion of the object is horizontal, there is no motion in the y direction
@0.3nergy
@0.3nergy 7 лет назад
question, dont you have to use the acceleration on the y-axis? why are you only using the one Ax To find the acceleration over the Y-axis = the sum over the Y-Axis 50+ -58.6= -8.6 m/s2 Clarify please.
@rafaelalvarez1585
@rafaelalvarez1585 3 года назад
Thank you so much !!
@stepbystepscience
@stepbystepscience 3 года назад
You're welcome!
@stepbystepscience
@stepbystepscience 11 лет назад
thanks
@ann-mariekoger2907
@ann-mariekoger2907 5 лет назад
Why would the horizontal not be the surface of the table? I get the 35 deg from the horizontal, but why not make the horizontal bottom of the box? Does it make any difference?
@stepbystepscience
@stepbystepscience 5 лет назад
No it does not make a difference. When you pull something you usually do not pull from the bottom.
@biancaar8032
@biancaar8032 2 года назад
Does that mean the object will rise due to this force applied in an angle?
@stepbystepscience
@stepbystepscience 2 года назад
Only if the vertical component of the force is greater than the weight of the object.
@biancaar8032
@biancaar8032 2 года назад
@@stepbystepscience thank you
@gianny2977
@gianny2977 6 лет назад
Great video thank you, on to video 3
@stepbystepscience
@stepbystepscience 6 лет назад
you are welcome, thanks for watching and commenting.
@theusedblueandyellow
@theusedblueandyellow 10 лет назад
excellent videos.
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