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Non-inverting op-amp circuit 

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An op-amp can be used to amplify a voltage. The gain is determined by the ratio of the resistors in the circuit.

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24 июл 2016

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Комментарии : 104   
@bigstuff52
@bigstuff52 7 лет назад
over 40 years in electronics and this is best explanation of op-amp that a beginner needs...
@rajnishkhare8451
@rajnishkhare8451 6 лет назад
john james true
@Leader_shift310
@Leader_shift310 5 лет назад
I have been trying to find some video lessons for optional amplifiers, But it turns out there is little in my country,, But in here I got so many I need, Thanks, man, :)
@rasraster
@rasraster 2 года назад
Totally!
@baderfarhan8810
@baderfarhan8810 7 лет назад
I appreciate that you are teaching well prepared and fully illustrated lectures, and I am thanking you for that. I suggest that you establish an independent course for Analogue Electronics. Best regards.
@agstechnicalsupport
@agstechnicalsupport 6 лет назад
Thank you for posting such a good lecture on non-inverting opamps.
@recursive_dream
@recursive_dream 6 лет назад
My god I've found the channel that can teach me this stuff. Everything was frustrating me and this is perfect
@cenzoll8441
@cenzoll8441 4 года назад
Great video, I couldn't understand half of what my lecturer was trying to get across with their explanation of op-amps but this has really helped
@johncrowe9171
@johncrowe9171 5 лет назад
Much better than any of the explanations my professor has given
@davidecalaminici2937
@davidecalaminici2937 7 лет назад
Great tutorials. I think one of the best source around. Could you please release some tutorial about Oscillators - wave shapers - schmitt's trigger?
@tuna3226
@tuna3226 6 лет назад
This is an excellent video. Thanks for the effort :)
@aweirdguy9785
@aweirdguy9785 5 лет назад
FINALLY! someone that explains really how an op amp is modeled and how to get to the gain formula
@aweirdguy9785
@aweirdguy9785 5 лет назад
I've been searching for that explanation for 2 days. All I wanted was the math behind
@VidarrKerr
@VidarrKerr 5 лет назад
@@aweirdguy9785 Yes. Unfortunately his algebra is a sloppy mess.
@Myox_
@Myox_ 3 года назад
Thank you !! Best explantation i found on the internet:)
@dipanjanbiswas1105
@dipanjanbiswas1105 6 лет назад
Amazing explanation Sir. Thanks a lot!
@samilnaml7636
@samilnaml7636 2 года назад
Thanks a lot for your clear explanation!
@RAndrewNeal
@RAndrewNeal 4 года назад
Before you started doing anything, I tried to see if I could come up with how to set the gain myself. And I came up with Gain=R1/R2+1, which is equal to R1+R2/R2. I also did it by simple ratios of the resistors, but added the 1 because the gain value is greater than the ratio of the resistors by 1. A gain of 1 would just be a voltage follower, while a gain of 2 doubles the voltage. So a ratio of 1 would be a gain of 2 because it halves the output voltage, while the voltages on both inputs must be the same, therefore, the voltage on the output must be double that of the input so as to make the halved output voltage equal the input voltage.
@jobliar937
@jobliar937 Год назад
Doesn’t that depend on resistors
@samarthtandale9121
@samarthtandale9121 3 года назад
Love Your Videos Sir, Always prefer khan academy videos first . A big fan!
@memirandawong
@memirandawong Год назад
I'm visually oriented but this time the math made more sense to me. I haven't seen another basic op amp video that derives the formulas this way 9for beginners) Nice!
@user-rr7xc9ih3r
@user-rr7xc9ih3r Год назад
tysm u just fixed my nightmare, cant thank u enough!
@anuraagbarde
@anuraagbarde 6 лет назад
You make life easy. Thank you very much 😁😁😁
@adityavarshney6450
@adityavarshney6450 7 лет назад
Since we are using ideal op-amps, we know that V+ = V-. The fastest way to get to the answer given, is to use the voltage divider and this property. V+ = V_in V- = (R2 / (R1 + R2)) * V_0 By the V+ = V- property, we get: V_in = (R2 / (R2 + R1)) * V_0 Getting V_0 as the lone term: V_0 = V_in * (R1 + R2) / R2.
@tomc642
@tomc642 5 лет назад
Aditya Varshney Ok, but try to explain to a novice what a virtual ground is. For that you would need to know about differential amplifiers and feedback circuits. That is why the instructor chose the longer explanation.
@ertreri
@ertreri 2 месяца назад
Thanks, explanation super clear.
@sujeewa8067
@sujeewa8067 5 лет назад
Thanks pal this helped me a lot! :)
@mumersohailkhan9148
@mumersohailkhan9148 6 лет назад
great job khan academy
@hashtagharris7126
@hashtagharris7126 4 года назад
Thanx alot....explained well😊😍
@jatinkadge7297
@jatinkadge7297 7 лет назад
awesome explaination
@zcq0730
@zcq0730 7 лет назад
Very nice video!
@cryonix380
@cryonix380 4 года назад
Your videos can easily replace the best electrical engineering textbooks when it comes to teaching fundamentals.
@ladytalksalot4097
@ladytalksalot4097 4 года назад
Can confirm. My professor's a great teacher in person, but teaching online isn't his forte whatsoever. Videos like this are the only reason I have a clue what's going on.
@unitedelectrician4334
@unitedelectrician4334 7 лет назад
Wow you are a genius. I am cracking my head with both difference arrangement of formula one is (voltage divider rule menthol) one is (KCL law to solve the equation) then suddenly u make the voltage crystal clear at the point you explain dependent (not really sure wat it means at first but you mention voltage divider rule!! Bingo !!! i got what you mean!!! thousand thanks
@andreavillanuevalechuga2343
@andreavillanuevalechuga2343 4 года назад
how do you know which resistor to put on top using the voltage divider? (Why R2 instead of R1 in the numerator?)
@maxdestil7812
@maxdestil7812 3 года назад
You put the resistor closest to ground as the top resistor in the voltage divider.
@cxx6666
@cxx6666 6 лет назад
I would to have a video with the digital circuits of opamp please
@ismaellayth
@ismaellayth 5 лет назад
thank you sir.
@shivajipatil1991
@shivajipatil1991 5 лет назад
Thank you very much
@prakhyavrajesh
@prakhyavrajesh Год назад
how does v+ become vin later in the equation
@davidecalaminici2937
@davidecalaminici2937 7 лет назад
There's a way to contact the professor? Great work!
@qzorn4440
@qzorn4440 3 года назад
op-amps are still cool... thanks..:)
@davidglendaleardenaso8735
@davidglendaleardenaso8735 Год назад
what about ideal non-inverting? would they just be 0 since v- and v+ seem to be important here
@at2824
@at2824 11 месяцев назад
why can’t I have teachers that explain like this at school?
@luisgomes1814
@luisgomes1814 7 лет назад
Amazing
@fettishferrubbish8012
@fettishferrubbish8012 7 лет назад
Awesome
@blackcat-mp7kh
@blackcat-mp7kh 4 года назад
@7.42 v+ is vin but there is resister so no voltage drop ?
@rahulgautam3705
@rahulgautam3705 7 лет назад
Vin comes twice? one that is supplied as V+ and the other one as difeerence of V+ and V- . Whats the differnce ?
@kunalsingh1944
@kunalsingh1944 4 года назад
Why do we substitute V+ with Vin.
@osamahafez1232
@osamahafez1232 7 лет назад
in the previous video you said that Vin= V+ - V- so why here Vin = V+ ??
@sushantgulati
@sushantgulati 7 лет назад
Osama Hafez V- is not connected to a voltage source. that's why
@zcq0730
@zcq0730 7 лет назад
Hey, Here is only a problem of definition. In previous video, Vin defined as V+ -V-. But in this specific vedio, Vin was defined as V+ ONLY. I think if you use another name would be easier for understanding. In this video, V+ Only means Vsource , the voltage source you want to measure. (Here used Vin stand for Vsource, and you probably mixed it up). ;)
@Ashish-dj2di
@Ashish-dj2di 6 лет назад
Osama .... you can see that V- in 'grounded'...so V-=0....therefore final expression for Vin becomes Vin=V+ - 0=V+
@benedictvos8088
@benedictvos8088 6 лет назад
Yes the explanation in video is a bit confusing because the name of external voltage source is vin. it is much clearer if the name of external voltage source is changed to Vex for example. Since Vex is connected to pin v+ of amp, its clear that Vex = v+ (the point in video at 7:32 till 7:40)
@tuna3226
@tuna3226 6 лет назад
I was confused too, thanks for pointing this ;)
@shaktisrivastava4883
@shaktisrivastava4883 6 лет назад
Please give details about inverting and non inverting operational amplifiers in details
@clairedoherty732
@clairedoherty732 4 года назад
Thanks, had a good understanding from lectures but this blows most explanations out the water.
@shadon_official2510
@shadon_official2510 3 года назад
How come you changed v+ to vin?
@yasshossain7465
@yasshossain7465 4 года назад
Why is v+ substituted for v-in at 7:46 of the video
@kunalsingh1944
@kunalsingh1944 4 года назад
I have the same doubt
@brianm1916
@brianm1916 2 года назад
Because v-in is going directly into the v+ input of the op amp.
@rohanrayakar2257
@rohanrayakar2257 7 лет назад
I am a first timer at opamps and was trying to get the non inverting amplifier to work. I connected V+ to +5v and V- to gnd( since I will be using it for DC). I am continuously getting a high output voltage of 4.44v. I even tried the offset null circuit but the output voltage remains constant at 4.44v. The feedback resistor is 1Mohm and R1 is 100kohm. Can anyone guide me here as to what could be going wrong? Is the negative power supply absolutely necessary for the opamp to work?
@mecnunatbas7950
@mecnunatbas7950 6 лет назад
if you feed opamp around 5V to 0. The opamp will compare 2.5V Dc best. Your signal Vp must be around 2.5 V for best . Otherwise you will always get 5V
@Nanook128
@Nanook128 3 года назад
Why is he able to say (R1+R2)/R2 is 2? That would only work if they have the same values of resistance right?
@danielisaksen1524
@danielisaksen1524 7 лет назад
I don't get how gain A can be "really, really big (10⁶)" and at the same time only the ratio of the resistors, which normally isn't a very big number. Can someone please explain this?
@danielisaksen1524
@danielisaksen1524 7 лет назад
Ahh.. Is the gain of the opamp near infinite while the gain of the circuit is the ratio of resistors?
@peterhall7972
@peterhall7972 7 лет назад
this is the neat thing about op amps you buy one and you choose the gain you want by choosing the values of those 2 resistors
@jeffsam5495
@jeffsam5495 6 лет назад
and why is that? how is that possible??
@TwaritWaikar
@TwaritWaikar 6 лет назад
1/0.0001 = 10000. Here 1 and 0.0001 are not so huge but their ratio is
@sanketshah9759
@sanketshah9759 5 лет назад
can someone tell me why gain will be a very very big number?
@phathelamashudu9979
@phathelamashudu9979 4 года назад
How did he get 1
@rohannimbalkar7884
@rohannimbalkar7884 7 лет назад
Sir, How did you the equation that v- =v°R2/R1+ R2 ?
@parvatkishan3850
@parvatkishan3850 7 лет назад
Ronny Official it's a voltage divider equation. search on RU-vid for voltage divider circuit, you'll find your answer there!😃
@ahmadislam2364
@ahmadislam2364 7 лет назад
Why it is V- = Vo * ( R2/(R1+R2), not V- = Vo * ( R1/(R1+R2))?
@phuphatoonkamtoey7888
@phuphatoonkamtoey7888 6 лет назад
If you want to measure the voltage at V- .You need voltmeter to measure across R2 and ground right? So that's why the voltage at V- = Vr2.
@KatherinePierce_81
@KatherinePierce_81 5 лет назад
Phupha Toonkamtoey thanks I had the same question
@lasinduwickramaarachchi6217
@lasinduwickramaarachchi6217 3 года назад
What if there's a resistor between the voltage source and V+? How would the equations change, then?
@bmbiz
@bmbiz 2 года назад
There's no current flowing so it won't do anything (is my guess...I'm just learning this stuff myself).
@garvitsharma6763
@garvitsharma6763 5 лет назад
What is the use of R2 here
@VidarrKerr
@VidarrKerr 5 лет назад
Pull down resistor.
@antoneliasson9045
@antoneliasson9045 7 лет назад
If V- = Vo * ( R2/(R1+R2)), shouldn't Vo = V- * ((R1+R2)/R2) ?
@marcotngsn
@marcotngsn 6 лет назад
Yes its correct. V+=V-=Vin(source) in this op amp
@pebre79
@pebre79 6 лет назад
I dont understand how you can have i+ = i- = 0 you put a voltage/signal?
@neehalramchund2643
@neehalramchund2643 6 лет назад
pebre79 it's a characteristic of the op amp, high input inpedance meaning there is a high opposition to current
@rolfw2336
@rolfw2336 6 лет назад
[] is correct. It might help if you think about the input current not as exactly zero but instead as close to zero (i.e. very very tiny!). Then, we can approximate and just call it zero.
@jeffsam5495
@jeffsam5495 6 лет назад
i have a huge question to ask which is bugging me, according to the first equation Vnot = A(V+ - V-), later it was said that V+ = Vinput . again in the last equation it was said Vnot= [(R1+R2) / R2]*Vinput. according to that if we compare the two equations A= [(R1+R2)/R2] . @?!@!@ can someone please explain what im missing. it would be much appreciated if you can help.
@willymcallister5852
@willymcallister5852 6 лет назад
Jeff and Gary, Thank you for pointing out an error in the video.I mentioned "vin" twice with different meanings. What a goof. The video makes sense if you completely ignore the "green vin". Go all the way back to 1:58 and pretend I never wrote the green vin. I'm always talking about the blue vin (printed or cursive, its the same vin). I needed the green vin in earlier videos, but not this one. In this video, the only vin is the input to the circuit.
@jeffsam5495
@jeffsam5495 6 лет назад
Thank you soo much Gary :)
@spinningnumbers9960
@spinningnumbers9960 6 лет назад
I just posted a repaired video to ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-ZpUZlIjcOzA.html. It's a small change: Just before 2:00 there is no longer the notoriously confusing "green vin".
@jeffsam5495
@jeffsam5495 6 лет назад
thank you Willy McAllister :) your teaching is awesome
@rajasakthikumarrajendran3459
@rajasakthikumarrajendran3459 7 лет назад
sir can we consider (r1+r2)/r2 as total gain=A+(r1+r2)/r2
@mechanicclemont4799
@mechanicclemont4799 2 года назад
not=ex) I'm not a US citizen. Variable in electrical engineering is naught...
@Throneos
@Throneos 5 лет назад
it would be more elegant if you just divied the whole expression at 9:49 with a, then it would be 1/A and that is more logical to be able to just leave out
@SirFancyPantsMcee
@SirFancyPantsMcee 3 года назад
I was with you till about 6:20 and I have no idea where and how you manipulated the equation.
@omsushantkarki
@omsushantkarki 7 лет назад
wtf
@RoseMyLast
@RoseMyLast 7 лет назад
Can anyone test this out and give feedback? Search: 'Circuit Solver' on Google Play.
@firstoptionhomeinspection9040
@firstoptionhomeinspection9040 7 лет назад
explanation is not so good check out Michel Van Biezen much better
@rlibby404
@rlibby404 7 лет назад
Can the narrator PLEASE do something where I don't have to hear all the saliva in his mouth? Every flick of the tongue and smack of the lips? It's disgusting.
@osamaishtiak6135
@osamaishtiak6135 7 лет назад
mate its free stuff. if you don't like it the don't watch. that simple really
@VidarrKerr
@VidarrKerr 5 лет назад
I agree.
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