Nhi nhi Normal mg ke opposite hi lagta hai but usko balance karta hai to Agar lift rest pe hoti hai to dono equal hote hai Agar lift rest pe nahi hoti to normal mg se Kam ya zyaada hota hai but hame hamara weight normal ki vajah se feel hota h na ki mg ki wajah se isliye normal zyaada to apparent weight zyaada aur normal Kam to apparent weight Kam kyunki apparent weight normal hi hai
You're applying Newton's third law correctly, but missing a crucial point. Normal force (N) is indeed opposite to weight (mg), but: *Normal force is not equal to weight* N ≠ mg (in all cases) When you're standing on a surface: N + mg = 0 (equilibrium) Here: N = normal force (opposite to mg) mg = weight (force due to gravity) Now, when normal force increases: *It doesn't mean your weight increases* Instead: *The surface is exerting more force on you* This can happen when: 1. You're on an inclined surface. 2. You're experiencing an upward acceleration (e.g., elevator). 3. The surface is applying more pressure. In these cases: N > mg Your weight remains the same (mg), but the normal force adjusts to balance the forces. *Weight remains constant* Weight is determined by: mg = mass × acceleration due to gravity Which doesn't change unless: 1. You gain/lose mass. 2. You're in a different gravitational field. Did you got it now?
@@subratasarkhel7505 no dear. I just ask him to check again and Delete the video and He can upload again, Sabkey pass Wrong information pahuchane ly sey better , sabhi ko bataa diyaa jaaye.
Than pseudo force act in downward direction So equation become N - mg = ma N= mg +ma For detail explanation you can visit my channel video elevator problem
Coz there we already calculated that there was a downward deceleration of. 20 m/s2 and the force of weight is 98m/s2 which makes normal force to be 98 - 20 =78 m/s2 hope this helps u after 2yrs 😂😂
