Normal Force on a Hill, Centripetal Force, Roller Coaster Problem, Vertical Circular Motion, Physics

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This physics video tutorial explains how to calculate the normal force at the bottom and at the top of the hill given the speed and radius of the circular hill. This video provides the free body diagram needed to derive the formulas to calculate the normal force at those positions. In addition, this tutorial discusses how to find the minimum speed that a roller coaster must have so passengers don't fall out and the maximum speed an object can travel on top of a hill without losing contact with the surface. The normal force provides the centripetal force in these problems. This video contains plenty of examples and vertical circular motion practice problems.
Circular Motion - Formula Sheet:
bit.ly/4gIUL3r
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Static Friction & Centripetal Force:
• Static Friction, Centr...
Normal Force on a Hill:
• Normal Force on a Hill...
Banked Turn Physics Problems:
• Banked turn Physics Pr...
Non-Uniform Circular Motion:
• Non-Uniform Circular M...
Gravitational Force:
• Gravity, Universal Gra...
______________________________
Universal Law of Gravitation:
• Gravity and the Univer...
Gravitational Acceleration:
• Gravitational Accelera...
Gravitational Field Strength:
• Gravitational Field St...
Satellite Speed:
• Speed of a Satellite i...
Kepler's Third Law of Motion:
• Kepler's Third Law of ...
Circular Motion Review:
• Centripetal Accelerati...
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Kinetic Energy and Potential Energy:
• Kinetic Energy and Pot...
Work, Energy, and Power:
• Work, Energy, and Powe...
Final Exams and Video Playlists:
www.video-tuto...
Full-Length Videos and Worksheets:
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Physics PDF Worksheets:
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Опубликовано:

21 окт 2024

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Комментарии : 87

@TheOrganicChemistryTutor Год назад

Circular Motion - Formula Sheet: bit.ly/4gIUL3r Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html Full-Length Videos & Exams: www.patreon.com/MathScienceTutor/collections Next Video: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-FWXT-IzgbP0.html

@chaseassaker7227 4 года назад

This man, by himself, teaches me physics, chemistry, and calculus; all better than any of my professors. Honestly I'm so grateful to have you as a recourse JG! you have no idea how much it helps

@realphy6656 3 года назад

50+ circular motion solved problems - : ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-SlJmzMCiHn8.html

@vrishabzaidgaming3959 2 года назад

He is so good at explaining that I a 12 year old can even understand it

@Mrblobfish2 10 месяцев назад

why are you taking physics one as a 12 year old?@@vrishabzaidgaming3959

@angkorgo 3 года назад

Absolutely wonderful! I spent about two hours digging through dense textbooks with incomprehensible explanations - and all my professors were useless in describing the normal force when centripital forces were at play. Thanks so much!!!!

@isabellaholland2165 5 лет назад

Thank you so much for this video, I have watched a few times to properly understand what I'm doing, but it was a real help in solving some (what now seem) simple problems!!! I love your videos so much, they really are beneficial!!

@lucasyong9322 4 года назад

same this helped me so much

@estrellasirio 3 года назад

Muchas gracias. Has explicado mejor que nadie el asunto de la mecánica de la montaña rusa. Enhorabuena. Soy profesor de Física y conozco muchas explicaciones de libros, cursos de universidades , etc.. y tu eres, sin duda, el que mejor lo hace. Estamos en deuda contigo, gracias desde Madrid.

@Il_Chigol 3 года назад

Your physics videos made me understand every single thing way more better than any of my uni's teachers. I'm so grateful. Please go on!

@torphedo6286 15 дней назад

12:00 Thanks, I had the weight force sign backwards. I thought the centripetal force didn't include the weight and I needed to account for it by adding it to the normal force.

@davidkelly79354 4 года назад

Thanks so much for this. My applied maths teacher didnt explain that you should think of the centripetal force as the resultant and I got it from your diagrams within the first 2 minutes

@sphystius9031 4 года назад

Sometimes the simplest things mean the most, I really appreciate your help. Thank you.🧡

@aanyajain7843 Год назад

Thankyou very much sir .I used to be so much confused in this topic but now it's crystal clear thankyou.......!!!!!

@masoud6398 Год назад

Im gonna watch all of em. So well explained

@Aristothink Год назад

You covered many parts here. Great video. Our educational system needs more high quality videos like yours.

@SSN1907 5 месяцев назад

you are always thanking us for watching, but it should be the other way around, so thank you so much for every video🤜

@BigPosay 3 месяца назад

DADDYYYY YOU ATE THHAT I FINALLY UNDERSTAND WHAT IT MEANS WHEN NORMALCONTACT FORCE= 0 PAPI I LOVE YOU

@ghinahmaidosh5457 Год назад

This man has never disappointed me

@JZFeser Год назад

Thank you for saving me! Physics final tomorrow!

@dudeisawesome7202 5 лет назад

Thanks dude!! The 2nd problem really helped me understand about the required speed!!

@totetoteable 2 года назад

2022 and still it great video, man you explained so well the centripedal normal force, lovu

@allisonbenjamin6020 4 года назад

Great review for the AP Physics 1 exam, thank you!

@fizixx 3 года назад

In the first example you have "mg" as positive at position A, and at position B you have "-mg" but they both point in the same direction.

@oooooo-x9c 9 месяцев назад

what an amazing explanation love you from great country Ethiopia💪

@brenda8164 Год назад

I FUCKING LOVE U, MAN. I WAS STRUGGLING WITH THIS TOPIC ON IB PHYSIC AND NOW I UNDERSTOOD. THANK YOU SOOOOOOOOOOOOOOO MUCH

@Patrick-ky7ez 2 года назад

This man single handedly saves my every Physics grade

@madridboy3590 Год назад

I truly appreciate your effort. ❤

@Leptonite 3 года назад

Very helpful video. I will probably spend a lot of time on your channel lol

@tsoojbaterdene7793 3 года назад

Thank you very much,man It helps me a lot.

@awanderer7201 4 года назад

Thank you, this was very helpful😊

@ellielyndon1645 6 лет назад

Thank you so very much . Now i understand and do my test

Год назад

Very good explanation! (Muito boa explicação!)👏

@rosstheboss8633 Год назад

Brasileiro!

@honestman276 3 года назад

Thanks. From Bangladesh.

@SimonWei-b8l Год назад

Thanks!

@laurachiriac1336 5 лет назад

Thank you this was really helpful

@williambrown1703 4 года назад

Thank you so very much

@johnandrzejewski5907 4 года назад

thanks for the clutch

@noyadrori4620 Год назад

thank you. so much.

@dhrubadutta856 3 года назад

hey try to make some experimental videos in physics

@vnana2991 4 года назад

This is so so cool!

@jark7812 4 года назад

Thank you very much!!!!!!!!!!!!!

@babyrossbaby2354 10 месяцев назад

on roller coaster case, what if the cart is not sitting upside down but sitting on top of the loop? the textbook said Fn is still pointing towards the center, which i dont understand. as i thought that would be similar to the box on top of hill case, Fn is pointing upward, not downward to center.

@LawrenceNdelemani-k6z 3 месяца назад

Thank you

@BobtheBuilder249 2 года назад

thanks bro

@JakePlayz07 Год назад

Hi is there a way to calculate the speed at the bottom of the loop?

@jeffreystockdale8292 Год назад

paused the video and was bangin my head for 20 minutes until "r=2m" was given, Thanks! 🤬

@surajnayak4256 3 года назад

thanks

@gayathrirajanpaluvai Год назад

In roller coaster problem , how did the normal force acted downwards ? Can you explain?

@Crystalluss 5 лет назад

Thank you! This was very helpful. :)

@luphiax4239 Год назад

Is the centripetal force the same during the whole motion in the loop the loop?

@geogaddi84 4 года назад

It’s been a very long time since I’ve done one of these. the sum of forces in the X dir=0, correct?

@tomatrix7525 4 года назад

Adam Chavez In these roller coaster problems, assuming there is no acceleration, yes, no net force would mean a constant speed, so you would be correct. If there was acceleration, there would be a net force forwards towards positive x values, so the sum in the x direction wold equal some positive number.

@Amathsrule 4 года назад

Can i ask why the normal force is downwards for the 2nd question?

@alicebeckett8727 3 года назад

This is a pretty late reply but I've been searching for the answer myself - I'm fairly sure that the normal force is down because the surface (track) is above the cart; a surface such as a track can only "push on a object" so the reaction of this must go downward. Hope this makes sense : )

@chiasa4334 3 года назад

@@alicebeckett8727 I have been browsing internet for this answer. Thanks for explaining. Your reasoning make sense even though u r not sure.

@gehadyasser1001 5 лет назад

Thankuuu so so much!!

@Limbaugh_ 2 года назад

I just don’t understand how centripetal force and gravity are pointing down but the normal force is lesser

@anilkumarsharma8901 3 года назад

Show tangent energy impact on the Hill and each one atmospheric pressure Per meter of weight

@woodychelton5590 2 года назад

why does normal force point down on the roller coaster problem? What upward forces are acting in that problem? Why is there no FBD?

@simz-n-science7610 4 года назад

what relationship is there interms of acceleration and ac, when a vehicle moves up and down the hill?

@lhliang5849 3 года назад

Thanks for the video. Got 1 question really confused me. When a car is travelling over a speed bumper at a higher speed, isnt the centripetal force gonna be larger? But why the car will fly off when the speed is higher?

@NewmanWaters 3 года назад

There is a maximum speed. If the car is to over the max speed, the car will leave the ground. If we treat the speed bump as an arc of a circle, we could say that the centripetal force is equal to mg - R (as they act in opposite directions). => (mv^2)/r = mg - R. If the car is to leave the ground, R will equal 0 since there is no contact. Using R=0, we can calculate the max speed by rearranging the expression to give v = root (gr), which is the maximum speed that a car can go over the speed bump without flying - it does not simply get attracted more to the speed bump with higher speed.

@NewmanWaters 3 года назад

R is the reaction/normal force

@jadenshah 4 года назад

Which way does centripetal force go in?

@mukundathakali5281 6 лет назад

thank you :D

@SyedFahadAhmedShahEB_ 4 года назад

how you decide if the direction of force is down the force is negative ?

@racedayrecap6295 3 года назад

Yes, if the force acts down, its negative. If it acts up, its positive I think

@Ray_Yang182 4 года назад

Hi! What is the normal force exerted by a road inclined 8 degrees above the horizontal on a 1500 kg car travelling at a constant speed V? I am fine calculating the normal force when the car is stationary, but when the car travels at a constant speed V, I have no idea. Would you please help me? Thanks a lot.

@azmatrayan8861 4 года назад

2:27. What if you aren't given the radius?

@niranjanwagh5767 3 года назад

Its really messed up that we take downward gravity positive and downward acceleration negative. In figure we can see mg and Ac both are in same direction. Still there sign comes out different at 4:20

@woodychelton5590 2 года назад

in that first problem, how come there is no centripetal force, just a centripetal acceleration?

@ella-gm6bz 6 лет назад

how is this different to tension?

@yackamajez 6 лет назад

it's basically the same thing

@quantum5775 5 лет назад

Fn is basically the tension substitute.

@phyarth8082 4 года назад

Better use geometry cosine function, because you wrong per sqrt(2) times example if plane flies forward part of energy is used to fly forward and part of energy used to lift off from the ground same principle and here, normal force is not equal to zero.

@poisonedcheeseproductions 6 лет назад

@11:30 im pretty sure the centripetal force is positive whenever it points to the center of the circle. So when you wrote those equations the way you did by making all of the signs negative, it was an unnecessary step (u could multiply the entire equation by negative 1 and re-organize it to still get the same result). there are actually alot of extra unnecessary steps in these videos. its confusing. or maybe im just dumb