@@FireBoy-qn4jsAray bhai itna purana comment😂😂. A* aya tha Alhumdulliallah brother. Iss banday ki videos bahut achi hai bas dake kr practice krtay raho inshallah apka bhi aye ga🤝. Best of luck
When you have the equation of the line: y = 2x - 2, it is easy to find passing points. In the video. I assume X = 0 (replace x = 0 in the equation), Y will be -2. So that gives me Point (0, -2) Then, I assumed Y = 0 (replace y = 0 in the equation), X will be 1, so that gives me Point (1, 0) So now I can draw my line on the graph.
@@OALevelMathematics can you please teach me how you found that point by using dy/dx so that if similar paper comes with similar curve I can draw it's min point
This is derived from the cosine rule. Since the angle in between (G) is obtuse. The opposite side, C² > (a² + b²) cosine rule: cos G = a² + b² - c² ___________ 2 * a * b