One to one and onto functions | Relations and Functions | Class XII | Mathematics | Khan Academy

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In this video, we will learn what one to one and onto functions are.
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Created by
Aakash Singh Bagga

Опубликовано:

15 сен 2024

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Комментарии : 89

@tanujpandey9233 7 месяцев назад

Your explanation power is excellent I hope you will grow much higher than you want

@NarendraSisodiya-pt7uj 11 месяцев назад

Thank you so much sir for your neat explaination in less time

@neilkathed 21 день назад

Best explanation ever literally ❤ Thanks brother

@akshintl5025 Год назад

U made it really esy to understand sir , thanks a ton

@DicotOP Год назад

Thanks sir,really appreciate your work,once again thank you,you are helping lot of students ❤

@Anime_Bazaar_23 9 месяцев назад

Thank you so much sir

@pctech053 10 месяцев назад

Good enough to revise quickly

@ManishaKumari-q8k Месяц назад

Thank you sir

@tareksheikh4187 8 дней назад

Thanks Sir❤ explained very well

@roufmalik8074 3 месяца назад

Great!....this was quite interesting and helpful....

@abhisarthak975 6 месяцев назад

Thank you sir for your dumbful explanation

@HridoyIslam2024 3 месяца назад

Excellent Tutorial SIr ❤❤

@anshumanrajput6287 11 месяцев назад

Thank you sir dil se❤❤

@Zaildarmp3 8 месяцев назад

Thanks 😇 sir saved my time

@RanaUsman466 5 месяцев назад

Top Notch ❤ Very well Explained ✨ Stay Blessed Regards from Pak ❤️

@1smile697 Год назад

Sir please please tell how to solve dpp's graphs questions?? Even you also not teach in your lesson. So how ?

@syzlgamingofficial7738 Год назад

Thank you😊

@NetraBikramBudhaMagar 18 дней назад

Thank you so much ❤❤❤❤

@N_SGamingYT 3 месяца назад

Sir bahot badhiya samjhaya aapne

@user-hf9ei1uj1s 3 месяца назад

Thank you bhai❤❤

@tanjiro3390 11 месяцев назад

Bhaiya kitna pyara bataya ♥️♥️♥️

@SajidaSiddiqueIzhar Месяц назад

Thanks sir awesome lecture 😊

@shivajikhochare1590 4 месяца назад

Thanks sir ❤❤❤❤❤

@pramodji1968 Год назад

Thank You Sir Ji 🙏❤️

@bhumiganotra312 18 дней назад

Very informative video ❤

@user-gw4ly4pu4s Год назад

Thanks a million sir.

@villainjohn7125 Год назад

Hello! Good day.

@TONY99501 6 месяцев назад

Thanks 😂😂😂😂 exam or shirf 30 minutes 😢😢😢

@AAKANKASHA 8 месяцев назад

Thank!!!!❤❤❤

@srajanrai3144 Месяц назад

Best Explanation 🎉❤❤

@harnishkaur6495 6 месяцев назад

Very very nice explanation

@aliahmadrehan3102 4 месяца назад

Very helpful video

@AsadKhan-s5b7x Месяц назад

Best lecture 😊

@ThirumalaKandadi 20 дней назад

TQ sir

@anubhavbakshi1336 2 месяца назад

Amazing video

@user-ym5bm6tw1b 2 месяца назад

Thanks🎉

@strikeout7371 6 дней назад

Sir doubt hai 😭. One one function me ek domain ka ek hi image hoga Aisa aapne bataya. But ek yt. Channel hai dear sir karke unke video me to kuch or bataya gya hai 😢

@Styla-es7dk 5 месяцев назад

Agr set A main koi akela reh jaye to kya wo one to one function kehlaiye ga?

@sqnldrhadi 5 месяцев назад

If in a set \( X \), one element is not related to any element in set \( Y \), then the relation between \( X \) and \( Y \) cannot be a function. In a function, each element in the domain (set \( X \)) must be related to exactly one element in the codomain (set \( Y \)). If there exists an element in \( X \) that is not related to any element in \( Y \), then the relation does not satisfy this requirement of a function. In other words, for every element \( x \) in \( X \), there must be exactly one element \( y \) in \( Y \) such that \( (x, y) \) is in the function. If there's an \( x \) that does not have any corresponding \( y \), it violates the definition of a function. So, the type of relation you described would not be a function. It could be a relation, but it wouldn't meet the criteria for a function.