I’m a 3rd year elec. student.. I found this very helpful. Your method is short sweet, clear and concise.. thank you for this! Would love to see more of the upcoming curriculum!!
thank you for going into detail on how we are able to still power 3 phase motors and etc, even with a missing coil. Never quite understand the mathematical concept other than I've seen about a half a dozen of these systems on farm settings, where the farmer had mostly single phase equipment with a few 3 phase 240 volt motors. This situation will be a high leg configuration to power the 120 volt circuits just like your much more common 120/240 v split phase service. Just have to be aware of the high leg because if you're not paying attention it's easy to install a single pole breaker on the high leg when you want 120 volts, in which case you will smoke up equipment because you will be giving it 208V. So always use a multimeter to make sure the voltages are what you think they are. Incidentally the NEC requires the high leg be orange or other effective means, but I wouldn't trust my life to that, without verifying with a meter.
What u loose is the KVA rating in the bank in the absence of the third winding. So the net rating of the bank is a function of the two remaining pots (transformers).
i have now created the third phase by using two 240 volt to 240 volt isolation transformers the primaries are connected to each phase and to the neutral the secondaries are connected in series and one connection going to the neutral the other going to the load the two supply phases are connected to the primaries then directly to the load the set up works perfectly with perfect voltages and phase angles it is a variation of the open wye open delta connection
Good morning , for the 3 transformers installation in Delta to have the high leg, please, can you tell me if all 3 transformers must have same Power output ?
Understandably confused. When adding these voltages we have to account for the angle of the voltages. While it is 240 plus 240, it's actually 240@60° plus 240@180°. The resultant phasor will equal the missing 240v @ 120°. Hopefully that helps and doesn't confuse things further.
That's a bit different. You have an impedance device in that situation between all your bonded components and the point where the neutral connects to the system. With that high impedance component, higher fault currents do not develop in a line to ground fault.
Hi I have a open delta line 240v the question is when i measure each leg to ground i have the result are line 1 @264c ,line 2 @256v and line 3 only 38v does it indicate my system is losing phrase?
in my workshop i have two phases of a true 3 phase system ie phase to phase 415 v and phase to neutral 240v 120 degrees phase angle can i obtain the missing phase by using an open delta step up transformer 240v to 415v and connecting the two phases and the neutral to the primary side of the transformer
@@schulerruler I HAVE NOW CREATED THE THIRD PHASE BY USING TWO 240 VOLT TO 240 VOLT ISOLATION TRANSFORMERS THE PRIMARIES ARE CONNECTED TO EACH PHASE AND TO THE NEUTRAL THE SECONDARIES ARE CONNECTED IN SERIES AND ONE CONNECTION GOING TO NEUTRAL THE OTHER GOING TO THE LOAD THE TWO SUPPLY PHASES ARE CONNECTED TO THE PRIMARIES THEN DIRECTLY TO THE LOAD THE SET UP WORKS PERFECTLY WITH PERFECT VOLTAGES AND PHASE ANGLES IT IS A VARIATION OF THE OPEN WYE OPEN DELTA CONNECTION
Thanks for watching! Its called a lightboard. There is an LED strip around the glass which illuminates the writing. Then the image is flipped so it looks normal on camera.
The double subscript notation indicates polarity or rather the direction we "travel" when combining voltages. When adding these voltages we have to account for the angle of the voltages. While it is 240 plus 240, it's actually 240@60° plus 240@180°. The resultant phasor will equal the missing 240v @ 120°. Hopefully that helps and doesn't confuse things further.
