Operational Amplifiers Circuits (Inverting, Non-Inverting, Differentiator and Integrator Op-Amp) 2/2

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In our previous video, I examined the structure and working principle of operational amplifiers (Op-Amps). In this video, we will examine the structure and operating principle of inverting, non-inverting, differential and integrator operational amplifier circuits. If you have not watched our previous video, I recommend you to look at it first.
00:00 Introductor
00:20 Inverting Circuit
04:03 Non-Inverting Circuit
07:25 Differentiator Circuit
07:41 Integrator Circuit
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Опубликовано:

6 июл 2024

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Комментарии : 32

@KrishanKumar-hv8fu 5 месяцев назад

The world's best teacher thanks sir

@muwanguzidavid7697 2 месяца назад

Brief and contentful 💪👏👏👏🥳

@pukaseek 2 месяца назад

Great video. Kept talking to a minimum with great efficiency of explanation. I worked years in electronics and this is by far the best explanation video. Thank you sir.

@lemusgeorge69 3 месяца назад

Best explication I have found

@willieriggi 9 месяцев назад

Really cool and we'll explained. Thanks.

@digitalelectronicsacademy5485 Год назад

Thanks alot

@arashyusefi1889 6 месяцев назад

Thanks you so much ❤️😊👍🙏💖💘☺️🥰

@rmssantos1314 3 месяца назад

Great

@hasantamer9199 4 месяца назад

good

@stephenkamanu8258 Год назад

Keep it up i like your video

@eeapplications Год назад

Thank you so much 🙏

@yousaftoki1599 7 месяцев назад

Amazing video sir ji

@eeapplications 7 месяцев назад

Thank you so much 😊

@deekondasaikumarsaikumar8564 Год назад

Thanks for videos make a more videos plZ and how to work wireless remote control RF circuit plz make a video ..,

@eeapplications Год назад

Hello. Thank you very much ☺️🙏🏻 Making a video takes a lot of time. Unfortunately, I can't produce more content 😔

@d614gakadoug9 8 месяцев назад

A differential amplifier and a differentiator are VERY different things! A differential amplifier amplifies the instantaneous magnitude difference between to signals. A differentiator produces an output that proportional to the rate of change of the input signal - the differential of the input signal with respect to time, written as dV/dt (though properly each d is a Greek small delta character), if the input is a voltage.

@jancenj2218 Год назад

On the inverter, why is the output negative when the supply is DC? What was actually inverted? I know for AC input, the phase was inverted 180 degrees.

@eeapplications Год назад

Hello. While there is a positive-negative change in DC, it happens in the form of a 180-degrees phase shift in AC.

@memirandawong Год назад

Great video. Well done!! Only one question, two actually. (at 6:23 in the video) 1.) Does it matter that you're not considering the true RMS value for AC inputs when calculating the output value? Or am I still confused as usual??? and, 2.) I think in an earlier video you stated one of the fundamentals is that the voltage at each input is for all practical purposes the same. Is that how you arrived the voltage (2V) to use in the non-inverting example? (4:55 in the video) Or, in the same example how does 2V appear at both input pins 2 and 3?

@eeapplications Год назад

Thank you so much. I'm glad you liked the video. My preference is to use the effective value in your 1st question. You can also do it over the maximum value if you want. Unfortunately, I couldn't understand your second question. I'm sorry.

@d614gakadoug9 8 месяцев назад

old question, but since it didn't get a reply: Yes, arguably THE most important concept in op amps is that there is a "virtual short circuit" between the inverting and non-inverting inputs when the amp is being operated with feedback. There is no current flowing between the inputs, they are just kept at the same voltage by currents flowing in the external circuit.The feedback makes the voltage at the inverting input equal to the voltage at the non-inverting input. That is, the non-inverting input "sets the voltage" for both inputs. There will be some very small difference in voltage between the inputs, but for lots of circuits the difference can be ignored. The other very important thing to remember is that the current into or out of the inputs of the amplifier itself are extremely small. Like the voltage difference between the inputs, these tiny currents can be pretty much ignored for lots of applications, though in some circuits they must be considered and can actually be quite a big issue. In the video, both inputs will be +2 V - the NII made that way directly and the II via the feedback/gain network. If the II is at +2 V, then the current through R1 must be 2 mA by Ohm's Law, flowing from right to left (using "conventional current" which is considered to flow from positive to negative). Since no current goes into or out of the actual input pin, that 2 mA _must_ be coming via the feedback resistor and it must be flowing in the same direction. 2 mA through 4.7 k gives a voltage of 9.4 volts. The II voltage we know will be +2 V, so the output voltage must be (+2 + +9.4) = +11.4 volts. Of course there can be situations where the op amp just can't do what is asked of if. If just a bit more gain were required in the circuit in the video, or the voltage at the NII were just a bit higher, the amp wouldn't be able to do the job because its output voltage would have to be higher than its positive supply voltage. The voltage at the non-inverting input couldn't be driven high enough to match the voltage at the NII. In fact lots of op amps wouldn't even be able to get to 11.4 volts with a +12 volt positive supply.