u are literally the best chem tutor on yt!! ur teaching style is great and soo easy to understand. i wish the future would have more teachers like you sir, thanks for all you do
You speak slower than my chem teacher and explain the concepts incredibly clearly, and simply even with the correct language. I learnt more in your 30 minute lesson and understood much more than I did in my school teachers 3 lessons. You are amazing!
That's lovely to know! Thanks for the feedback 😀 This is a link document to all my videos. I'm continually adding to it. docs.google.com/document/d/1JfmOcGMNEMJzmxOx5AEoQqD74lAHC2FS/edit?usp=drivesdk&ouid=108041655224173585816&rtpof=true&sd=true
Sir there are some questions that are asked in this topic like the oxidation number of some rxns I think , can u plzzz help me with that . Thank u , u r wonderful teacher ever🙂
Lovely to hear from you! I'm glad the videos are useful. Oxidation States tend to come in more in the redox topic, along with group 2 and group 7. I've done a video about redox: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-bjtO_PEgd64.html
@@chemistrytutor Just wondering, are there any other online tutors that you used personally or like? For maths, physics or chemistry. Thank you. Oh and the first dip caused in ionisation energy, is not only due to the higher energy level of the p subshell but also because it has additional shielding from the 3s² electrons
Greetings!! Thank you very much for helping students like me with such helpful videos! Also, I noticed that access to the document you have with all your videos is not given, kindly check the settings to ensure anyone with the link is able to open the document. Thanks for this video again!!
Hi, so sorry... this must have slipped through the net! I've updated the settings and it should work, please let me know if it doesn't! drive.google.com/file/d/1s3I5prjbJRR1U1lcKpXO9TQpQMaVoP66/view
@@justsomeone5660 well, I've already made some videos about these topics. They're exam question focused, so whilst I don't go through all the facts one at a time, they deliberately cover a lot of the content drive.google.com/file/d/1s3I5prjbJRR1U1lcKpXO9TQpQMaVoP66/view?usp=drivesdk
so electronegativity decreases down a group because there’s more energy levels -> causing a wider distance between outer electrons and nucleus -> therefore less pull from the nucleus. but if the effective nuclear charge stays the same down a group, how can the nucleus have less pull? is effective nuclear charge and the nuclear charge mentioned in the video different?
It's that nuclear charge (which does increase as you said) becomes less significant than the increase in distance down the group along with the extra shielding. The decrease in attraction caused by these two things is much more significant
You're correct, shielding can definitely affect those properties. However, when considering the pattern across a period (which is what periodicity looks at) the elements in a particular period all have the same shielding, so that wouldn't explain any changes you observe. If we'd been looking at a pattern down a group you would be correct to mention an increase in shielding
Great question. I think there is, slightly, but its masked by the s orbital being closer to the nucleus than p. So the repulsion is outweighed by being closer to the nucleus that has a higher nuclear charge
I'm really pleased it's useful 😀 It's not for any exam board in particular. It's inorganic Chemistry, so I think for CIE that starts at topic 9? Chemical Periodicity
26:24 So would you say the reason why P, S and Cl have slightly higher mps than argon is due to the covalent bonds being present which need energy to be broken aswell as vdw forces too, while argon only and only has vdw forces to break?
No, I'm afraid that's not it. When you melt something you don't break any Covalent bonds. Think about ice... its solid H2O, water is liquid H2O. All the bonds are still intact. It's due to the Molecules that you mentioned being larger than an argon atom there is additional surface area so the vdw forces between Molecules are stronger. Stronger (or more) vdw forces means that more energy needs to be put in to break them
You've asked a really simple sounding question that actually has a number of very complicated answers. You don't need to know if for a level but the explanation that ties in with something you do need is that its to do with shielding (some places call it screening) and electron-electron interactions. The deeper you go into electron orbitals the more our model gets refined by quantum mechanics. So if you want to go further, that's the direction to go.
@@chemistrytutor thanks, im gonna hold that thought bc I have an AS chem mock and a maths one tomorrow.(praying they dont lower my predicted grade from an A)
@huzaifakhan2798 thanks for your comment. Making the slides into a document isn't a quick job so I wanted to find out how useful it would be as to whether it was the best thing to prioritise 😀
