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Physics 18 Gravity (13 of 20) Keppler's 3rd Law 

Michel van Biezen
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25 окт 2024

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Комментарии : 36   
@aayushimahajan855
@aayushimahajan855 7 лет назад
sir you are the best teacher of astronomy in this whole world..............................
@nepalji2123
@nepalji2123 5 лет назад
Kya bat h... Just magnificent.... A class..
@juanvillotasanchez214
@juanvillotasanchez214 7 лет назад
you're saving my physics grade, thank you so much
@steffenleo5997
@steffenleo5997 Год назад
Good Day Prof Biezen, in your video 5;29 you mentioned ratio of T square by R cube is always equal to 1.Could you please explained more details why is always equal to 1?is this also for other planet like Saturn, Uranus or mercury and venus? Happy Thanksgiving Day and have a nice weekend.. 👍👍
@MichelvanBiezen
@MichelvanBiezen Год назад
Yes, when we use "astronomical units" for distance and "years" for time, Kepler's 3rd law simplifies to the ratio of T^2 / R^3 = 1 for all the planets in our solar system.
@anzatzi
@anzatzi 5 лет назад
Michel,it seems like American schools are hostile to the idea of the centrifugal "psuedoforce ". I like it because it is descriptive of the force diagram.
@MichelvanBiezen
@MichelvanBiezen 5 лет назад
I think it is up to the individual teacher or professor and not a universal condition in all schools. I know a few professors who do not like to use "centrifugal" force.
@gabrielsuys7041
@gabrielsuys7041 Год назад
Hey, why did you say devided by 2.0E...in 3:37? why arent you multiplying?
@MichelvanBiezen
@MichelvanBiezen Год назад
Isn't the calculation correct?
@gabrielsuys7041
@gabrielsuys7041 Год назад
Probablly yes, but then i still don’t understand the following: In the formula (2:58) you are multiplying the G constante with the mass of earth. And when you eventually put the numbers in your calculator, you say: 4π squared devided by G and again devided by M. Why was it not 4πsquared /G•M?
@MichelvanBiezen
@MichelvanBiezen Год назад
I use a cheap $8 calculator and thus I use a specific technique to perform the calculations. Be assured that the result is as you indicated.
@johnmifsud6814
@johnmifsud6814 3 года назад
He has taken the orbit to be circular which is not - its an ellipse. All Physics textbooks claim centrifugal force does not exist ?
@MichelvanBiezen
@MichelvanBiezen 3 года назад
The orbits are indeed elliptical and not circular. If you are interested in Kepler's equations for elliptical orbits, we have videos on that in our Astrophysics playlist. The centrifugal force is indeed a fictitious force (doesn't exist) just like the Coriolis force, but thinking of them as forces helps us solve problems.
@ironuranium3927
@ironuranium3927 6 лет назад
can we apply low of conservation of angular momentum in lieu of kepler 3rd law?
@MichelvanBiezen
@MichelvanBiezen 6 лет назад
Keppler's second law in essence is a formulation of the conservation of angular momentum. The third law simply states the relationship between the orbital period and the orbital radius.
@alfinuralbab114
@alfinuralbab114 4 года назад
I have the same question. I notice that in 2nd kepler's law: conservation anguler momentum, r is inversely proportional to v. But, in 3rd kepler's law, r is inversely proportional to square of v
@gulfcoaster5
@gulfcoaster5 9 лет назад
For the velocity equation, why did you use d = 2*pi*r instead of the perimeter equation for an ellipse (d ≈ 2*pi*sqrt[ (a^2+b^2)/2 ] or even a series expansion)? that would give you a slightly better approximation for the AU, right?
@MichelvanBiezen
@MichelvanBiezen 9 лет назад
gulfcoaster5 Using the perimeter of a circle is good enough for illustration. The difference between the circumference of a circle and of an ellipse at the eccentricity of the Earth is very small. Go ahead and calculate it, you'll see.
@Rohitkumar-yo8js
@Rohitkumar-yo8js 7 лет назад
sir,here if unit of distance we take is in meter then what will be the unit of time period here???
@MichelvanBiezen
@MichelvanBiezen 7 лет назад
The standard units is seconds and that is what is used in all the equations. Sometimes it is easier to relate to the time by converting it to days or years.
@MostafaTawfeek--
@MostafaTawfeek-- 6 лет назад
but this law or the prove is applied to circular path because u used constant R so which R in the ellipse
@MichelvanBiezen
@MichelvanBiezen 6 лет назад
Yes, when the orbit is elliptical there will be some adjustments, but for most planets this works just fine when the ellipticity is small.
@tumelomatlakeng6416
@tumelomatlakeng6416 5 лет назад
why is the center seeking force going out of the arc ?
@MichelvanBiezen
@MichelvanBiezen 5 лет назад
The centripetal force (center seeking force) acts inward and is caused by the force of gravity. The fictitious (non-existing) force called the centrifugal force has the same magnitude as the centripetal force but is thought of as acting outward because of the sensation that objects are pushed outward when they travel in a circle.
@tumelomatlakeng6416
@tumelomatlakeng6416 5 лет назад
@@MichelvanBiezen so that makes Fc Centrifugal?
@MichelvanBiezen
@MichelvanBiezen 5 лет назад
Using the centrifugal force makes it easier to visualize the situation.
@angelinatsa
@angelinatsa 6 лет назад
How come at 3:16 you said we're going to multiple the gravitation constant to the mass of the Earth, but at 3:30 you say we're using the mass of the Sun?
@MichelvanBiezen
@MichelvanBiezen 6 лет назад
I misspoke at 3:16. I should have said the mass of the Sun since the Earth revolves around the Sun.
@saidioussama2837
@saidioussama2837 7 лет назад
is R the distance from center to center ?
@MichelvanBiezen
@MichelvanBiezen 7 лет назад
Yes, it is the distance from the center of mass to the center of mass.
@prabhavnarang7109
@prabhavnarang7109 8 лет назад
Isn't R the lengh of the semi major axis? Pls reply asap sir!
@MichelvanBiezen
@MichelvanBiezen 8 лет назад
Yes it is.
@aamirazam5229
@aamirazam5229 8 лет назад
OK fine Kepler gave a law. A useful law. But why do we have to prove it? Cant we just trust the poor man? I hate proving things already proven by others
@mido9545
@mido9545 7 лет назад
many experiments are made from the hypothesis, we keep testing it because we want to improve the efficiency result ( chemistry) or accurate law ( physics) . Nothing is 100% and a man-made theory could be imperfect for all objects
@Jackthesmilingblack
@Jackthesmilingblack 10 лет назад
Kepler, watch the spelling.
@MichelvanBiezen
@MichelvanBiezen 10 лет назад
Jack, Thanks for the correction.
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