you all probably dont care at all but does anyone know a tool to log back into an instagram account?? I stupidly forgot the login password. I would appreciate any help you can offer me!
God bless you Professor, you remind me so much of my 2nd year @ uni and also my Professor and the Teaching Assistant we had. You guys have so much in common. You are a very good teacher and I can guarantee you even the weakest [(I don't really believe in weak & strong abilities. I do put a time derivative on the rate of comprehension for every human to achieve. This implies everybody would be able to reach that point with time. The only difference is the time it takes them to reach. Looking at the way you teach it won't take them too long to reach that level. From experience, I wasn't the brightest of students but I became very strong because of my lecturers and that what you remind me so much of)] students wouldn't struggle too much to follow your lectures and make it through their exams. Please keep the good work up.
Greetings Dr. Biezen your videos are awesome, I learn a lot from them... thanks a million :) One advanced math concept which does not contain much resources is tensor calculus and analysis, I would greatly appreciate it if you started a series on this topic (and I'm sure many others would as well). The sources I've seen make it seem extremely complex and don't do any examples for practice, as appose to your teaching style which makes things much easier to understand.
Hello dear sir :) Ur videos are amazing nd I learn a lot from 'em , omg u don't even know how much helpful these vdos were nd how ezy u made it seem to be Also, Me along with tens of Thousands of other physics enthusiasts are eagerly w8ing for ur continuation of dis course.....Seems lyk u forgot to continue it ever :( It wud mean the world to me if u finish both Lagrange nd Hamiltonian Mechanics sir Thank you
We appreciate your comment. We haven't forgotten, but we are short on time, with our multiple jobs and other responsibilities. We will try to get back to them as soon as possible.
Mocht u in de gelegenheid zijn de serie te voltooien zou dat heel erg prettig zijn. Langrangiaanse en Hamiltoniaanse mechanica maken helaas geen onderdeel uit van de ingenieursopleidingen, dus komt het aan op zelfstudie. Uw video-colleges zijn daarbij een welkome aanvulling op boeken. Ik blijf in ieder geval duimen dat u er in de komende tijd aan toe komt deze serie af te maken. :-)
Thank you so much!! I have my analytical mechanics final tomorrow and I feel so much better about this section. Please do more upper level physics videos when you have the time! (also a big fan of your astrophysics videos)
We intend to go back and produce more videos on the Langrangian and the Hamiltonian, but at this point we are very busy at work and so our time is very limited. Hopefully we can get back to it this summer, along with our electrical engineering videos.
Dear professor, how can I calculate the potential energy in the event that two masses move freely in a circular guide, while connected together by a single spring with constant k?
If we understand your question correctly, the PE of a spring = (1/2) kx^2 And the distance of elongation can be found by F = - kx The force would be the cetripetal force: F = mv^2 / R Therefore x = mv^2 / Rk and then you can find the PE
Yes, that is what I meant. I would like to thank you for your support and effort, which is the way to donate to your channel? Thanks again professor, you’re the best.
He's implicitly doing that. KE of a rotating object = (1/2)Iw^2, where I is the moment of inertia about the axis of rotation (the bottom of the disk in this case). If you plug in parallel axis theorem for this I (I = Icm + MR^2), you get the formula he uses (KE = (1/2)mv^2 + (1/2)Iw^2), where I = Icm. Since he already accounts for this in his KE formula, he doesn't have to also use parallel axis theorem during his moment of inertia calculation.
Hello, is there anyone that could please help me [I really need help :( ] using the Lagrangian equation to find a function of time and theta for a cycloid? Any help is appreciated!
professor Thank you for this videos. this videos help me to understand the lagrangian problem. i am confusing on other problem too.can you make more videos of example like rolling object in incline plane, a mass m is suspended from a spring, a bead of mas m slides freely on a friction less wire and related other cases too please...
Sir, I wanna ask why the solution doesn't contain the "sin(wt)" terms? As the initial condition of X(t=0) may equal zero but cos term doesn't contain that situation!
Hi, everyone, I wonder known why the tangent velocity(V=R x W) of the solid disk is equal to the linear velocity(v)??? The derivative in the video used the same notation.
If a car is driven 1 km, what is the length of the surface of the tire that made contact with the road? (if the circumference of the tire is equal to 2 m, then the tire will make 500 rotations.
The moment of inertia of disk should be (3/2)*M*R^2 since the disk is rolling about its edge and therefore we need to apply parallel axis theorem to get moment of inertia.
Hello Professor, would you be adding more videos to Lagrangian and Hamiltonian in next few weeks? I have an exam in a month's time. Thanks for all your videos. Me and my friends love them!
Hello sir, can you please give me links of next videos of this topic(17th, 18....) As i can't find them. Also can you please suggest me a good book on basics of Lagrangian mech., BASICS.
Professor will the rest of the videos be available in the near time? I'm still waiting for the rest ^^ Thank you these are very helpful, god bless you :)
It won't be in the near time. We are trying to cover everything, but it will take a while to do so. We are doing everything we can to make as many videos as possible.
So the kinetic energy of a thrown solid ball is not 1/2mv^2, but 7/10mv^2, even with or without spinning? All this time we're only using the former formula. Please enlighten me anyone. Thanks! XD
Not necessarily. In the example he gives, the rotation of the ball is related to the translational velocity. This is not always true but tends to be true in cases when a cylinder or ball rolls without slipping. The reason you have more kinetic energy that .5mv^2 is because it requires energy for something to rotate. So, in your example of the solid ball, if the ball is not rotating, you can say that its kinetic energy is .5mv^2, where m represents the mass from the center of mass point.
