A simplified explanation of when EMF (Electromotive Force) is and how it affects calculations in circuits and Internal resistance. It's made so simple, even a 3-year-old would understand... Lol. Enjoy!!!
this is me in 2024 ready to become the future medical student , thank you so much uncle if i was rich i would have bought you a car😅, but i know if i put more effort in my studies and then inject some of your best videos , who knows ,i will find myself in stellenbosch and taking a picture with you and sharing a testimony of your best work , dont stop , i promise you will go far. thank you so much uncle. although i am a bit scared i know i will make it, as they say some things look hard until you do go through them.
Mr Nkosi ❤ I'm forever grateful... i saw these videos and downloaded them for my matriculating sister. I watched them too and wow🤧❤ you're fantastic .. sometimes i can't explain to her that well coz i did my matric in 2019. And this is the best help she could get
God will bless you sir. I hope i can one day be of some kind of use to you as well. I can't believe i used to think electricity was hard. You are the best.
Sir you are the best. i just listened to your explanation at the beginning of the video and the previous videos on resistors in series and parallel. i tried to do this question by myself before seeing how you did it and i applied everything you taught and i got everything correct. this was once a difficult section for but i can assure you that with how you explained it, it is now one of the best. thank you🥰
Thanks man you made physics as simple as L.O I wish you were my teacher I've could past physics with excellent I wish all the best on your career keep helping children god and your ancestors will bless you with many years.
Hi Mlungisi I've been watching your videos and they are very helpful however I've been researching what would be considered a bad internal resistance for a battery for instance if I have a 2V Cell with internal resistance of 0.25 mili ohms what but when I test the IR I get something like 0.75 mili ohms would you say that's Bad or my battery still has some life in it
Ideally what you would like is to have zero internal resistance… However, that’s impractical in real life. What you do want though is for most of the power to be utilised towards whatever load the battery is trying to supply.
Hey sir please do prelim past question papers . I have been watching all of your videos and I should say that I understand Physics better now. Thank you.
sir for question 3 I did the following: current in A2: V2/R : 14.4/45 = 0.32Ampere. then current through 10 ohm resistor = total current - current in A2 = 0.48A V3=IR 0.48 X 10 = 4.8V?
For V2 I started by calculate voltage across 12ohm resistor because the current that flows there is the total current which is 0,8A then I got the answer of 9,6V thereafter I said Vexternal which is 24 minus 9,6 then I still got 14.4v as my V2... Many ways to kill a cat. However I learnt a new trick from you sir. Your work is much appreciated will definitely be referring my students to this channel.
You're so right... Many ways to tackle circuits. Thank you so much sir. Your learners are most welcome. It will save from a lot of work on revision for the prelims
Hy Mr mlungisi...what will happen to a voltmeter reading..if you connect a negligible conductor ..let's say maybe they gave u point p and q and that where the negligible conductor is connected
That would've been the case if we didn't have the 12ohm resistor on the side... Some of the potential goes to that 12ohm resistor. Therefore the voltage across V2 cannot equal Vext (Vtotal)
@@thando7786 emf - Vext = Vinternal (the voltage across the internal resistance) You may subsequently calculate the internal resistance: Vinternal = Ir (I is the total current)
@@MlungisiNkosi i believe they meant to ask why when calculating V3 you use 10 ohms and not 18 ohms(R//) like you did for V2 and id like to know why we used 30 ohms(R ext) and not 18 ohms(R//) for I2(A2)
