Physics, Kinematics, Free Fall (12 of 12) Maximum Height

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Shows how to used free fall kinematics to determine the maximum height of an object that is projected vertically from a known height with a known initial velocity. You can link to all my videos at my website: www.stepbystep...
Links to my other free fall videos below:
(1) Free Fall: An Explanation
• Physics, Kinematics (1...
(2) Solving for Time to Fall from a Known Height
• Physics, Kinematics, F...
(3) Solving for Final Velocity from Known Time to Fall
• Physics, Kinematics, F...
(4) Solving for Height from Known Time to Fall
• Physics, Kinematics, F...
(5) solving for Final Velocity when Falling from a Known Height
• Physics, Kinematics, F...
(6) Solving for Maximum Height when Launched Up with a Known Initial Velocity
• Physics, Kinematics, F...
(7) Solving for Initial Velocity Needed to Reach a Known Height
• Physics, Kinematics, F...
(8) Solving for Total Time in the Air when Launch Up with a Known Initial Velocity
• Physics, Kinematics, F...
(9) Solving for Initial Velocity when form a Known Total Time in the Air
• Physics, Kinematics, F...
(10) Solving for Maximum Height when Launch Up from a Surface Above the Ground
• Physics, Kinematics, F...
(11) Solving for Total Time in the Air when Launch Up from a Surface Above the Ground
• Physics, Kinematics, F...
(12) Solving for Final Velocity when Launch Up from a Surface Above the Ground
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14 окт 2024

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Комментарии : 107

@TriciaM-hy8gx 7 дней назад

Watched all of the 12 videos in the span of one day since I have a test tomorrow and this really helped a lot.

@stepbystepscience 5 дней назад

Good luck, glad the vids were helpful!

@hanatekletekle7121 7 лет назад

I'm in my sophomore year in collage and I was really struggling. Thank you so much for this.

@ashleythomas6822 8 лет назад

Thank you so much for these videos! I love that you have a visual and that it is step by step so I can follow you and even pause the video and try to reach the answer and then press play to check my work. You are awesome!

@stepbystepscience 8 лет назад

Great and thank you for the very nice comment. You can see a listing of all my videos at my website, www.stepbystepscience.com

@nekopi9518 6 лет назад

OMG...THANK YOU SO, SO MUCH!!! I just watched all of your videos regarding Kinematics and it really helped me on my preparation for a college entrance exam! Gosh, I feel like a genius already, thank you so much again, hope you do more step-by-step videos like these! Plus, you earned a new subscriber!

@stepbystepscience 6 лет назад

Great, I hope the entrance goes very well. Thank for watching, commenting and subscribing.

@bchis200724 3 года назад

I have been trying to understand this for weeks. Thank you so much!

@stepbystepscience 3 года назад

You are so welcome! Glad to have helped.

@suhailpanjwani8956 7 лет назад

Thanks to you i am now officially done with Physics, Kinematics, Free Fall. I understand everything so well, time to move on to projectile motion, WOHOOO :)

@stepbystepscience 7 лет назад

Glad that you made it through Free Fall, good luck with projectile motion...and thanks for the comments.

@sarwinderkaur3888 7 лет назад

Just in time for my test. Thank you so much. god bless!

@riunysan1460 2 года назад

I dearly appreciate these videos thank you so much!!I understand fully free fall thanks to you!

@stepbystepscience 2 года назад

I'm so glad to be of help! Best wishes.

@DimFX09 6 лет назад

Thank you so much sir! Excellent 12 parts!

@stepbystepscience 6 лет назад

Thank you very much for watching and commenting.

@sk-hx7dv 2 года назад

Thank you SO much! I finally understand how to do Free Fall. Physics was so confusing until I found your series! My free fall quiz is in a few hours, and these videos prepared me enough for it. Thanks again! My professor could never lolol 😭😭😭

@stepbystepscience 2 года назад

Glad I could help and good luck on the quiz!

@sk-hx7dv 2 года назад

@@stepbystepscience I got a 100 on my quiz and the midterm thanks to your kinematics and free fall videos!!

@Shadow4wrath Месяц назад

Finally finished free fall series! I feel a bit more confident now for the upcoming quiz on physics! I hope to come here to your channel more in the future hoping my lessons will align in your video, your best in explaining things (and suprisingly even 9 years has passed bro is still standing 🫡, subscribed ofc for this absolute chad of his effort for us) Question: I dont recall if you used the 1st equation among the four equations presented (or I just fail to remember it)... so it means that if you have 4 of the given (with "a") you will have an option to use that equation and also the other equation with it at the same time? (Sorry if my question is a bit confusing because it was rushed, my mom already asked me to sleep a few times while I was watching the vids one by one)

@latifaal-dhaheri690 4 года назад

you helped so much, i have a final tmwr. wish me luck and THANKU ! 💕

@stepbystepscience 4 года назад

Thanks for all the great positive comments, good luck with the final tomorrow!

@Mikej1592 8 лет назад

no, thank YOU, this helps me understand so much, just in time for my midterm tomorrow. You're a grade saver, man! (I hope) I might let you know how I did when I get my grade. My professor and the book are horrible, the book is overly complex by trying to simplify things and makes me more confused. The teacher asks questions first then tells us how to answer them. His homework assignments are on material he hasn't covered yet so I have no idea how to find the information and I don't have time to read the whole book, I work full time. But I love youtube, and your explanation covered what he tried to explain over 2 weeks... Yeah. So, I look forward to watching the rest of your videos. Too bad you weren't around 30 some odd years ago when I was in high school, maybe I would have enjoyed school.

@stepbystepscience 8 лет назад

Thanks for the great comment. It means a lot to me that you let how it is going. Let me know how your grade goes. You can see a listing of all my videos from my website, www.stepbystepscience.com

@699nta 9 лет назад

Watched all three videos. Nicely done, clear and concise. Thanks.

@stepbystepscience 9 лет назад

Nizam Taleb Great thanks for watching and thanks for commenting.

@AikoSilver 6 лет назад

Extremely helpful. Thanks for getting straight to the point

@stepbystepscience 6 лет назад

no reason to waste a bunch of time talking about nothing

@cyxhe 4 года назад

I am a Science Olympiad team member with the Elastic Launched Glider event, and on the flight log it tells you to find the maximum height of the glider. I searched all over the internet to find a video that isn’t too complicated, because I am a middle schooler.

@markhernandez7851 6 лет назад

Thank you so much for these videos! They are absolutely helpful!

@stepbystepscience 6 лет назад

You are very welcome and thanks for commenting!

@dhev5187 4 года назад

thank you for your help!! exams are next week and my lecturers were not very helpful

@stepbystepscience 4 года назад

Thanks for the comment and I hope the exams go well.

@shuvashishsharma1299 4 года назад

thanks a lot for 12 videos

@stepbystepscience 4 года назад

You are very welcome, thankful watching and commenting.

@westsmith3890 7 лет назад

How did you get 11.5? Every-time I try to enter it into a calculator I keep getting 10826.5?

@ricecream 3 года назад

Yeah, dont type it all at once, break it down top to bottom then divide.

@josechristiankylegoza4617 5 лет назад

Sir ? I just wanna ask something. Why you using -9.8m/s squared when the object is drop down or falling down ?

@stepbystepscience 5 лет назад

Because it is moving down and down is the negative direction

@nessonsy9724 Год назад

How did u get the 11.5m sir? Can u elaborate the calculation?

@yuriezelshin7550 8 лет назад

Thumbs up! Exam 2morrow, i hope this can help me :) I put all of my hopes in ur lessons :)

@stepbystepscience 8 лет назад

I hope the exam went well, thank you for the comments. You can see a listing of all my videos at my website, www.stepbystepscience.com

@fvckjenny 9 лет назад

thank u for existing

@stepbystepscience 9 лет назад

+Jenny J I live to serve you! Thanks for commenting.

@vk0981 6 лет назад

Here in this problem why we are taking a = - 9.81m/s^2. We are calcuting the upward motion of object. so it has to be a = 9.81m/s^2

@stepbystepscience 6 лет назад

Common mistake, but.....no, the acceleration due to gravity (g) is always negative because it point down which we take to be the negative direction. Does that help?

@joshphilip1062 4 года назад

sir you are a life saver, thanks a bunch!

@stepbystepscience 4 года назад

Happy to help and thanks for the great comment.

@luqp9834 2 года назад

Thank you!😊 This video is very helpful.

@stepbystepscience 2 года назад

Glad it was helpful!

@ricecream 3 года назад

You are the best!

@stepbystepscience 3 года назад

Thanks

@blessingsmuyunda2792 Год назад

Thanks you very much

@stepbystepscience Год назад

Welcome!

@yami100jsy 8 лет назад

..It is nice , clear explanation from well versed professional thanks alot

@stepbystepscience 8 лет назад

+‫جاسم اليامي‬‎ Thank you for the comment. You can see a full listing of my videos at my websitem www.stepbystepscience.com

@yami100jsy 8 лет назад

Sure I will be happy to do so...thx

@TwixedHD 4 года назад

how would i solve this if the ball was projected from the ground with an unknown velocity, and i observed the ball from 17m heigh with 15m/s velocity?

@urcomprehend6660 5 лет назад

Thank you ! I have subscribed, liked and commented.

@Jacob-ww7km 5 лет назад

Shouldn't the maximum height be 28.5m plus the initial height 17m??

@stepbystepscience 5 лет назад

No, when you solve the equation shown in the video you get 11.5 m but then you have to add the initial height of 17.0 m to that. So the total is 28.5 m.

@moeishadixon3555 4 года назад

How to do a free fall problem if my only given the height and i need to find out the time something traveled

@stepbystepscience 4 года назад

I believe you do it like all of the others. Maybe only the height is stated in the problem, but you also know that the initial velocity is 0 m/s and that the acceleration is equal to the acceleration due to gravity which is 9.81 m/s2. Does that help?

@moeishadixon3555 4 года назад

@@stepbystepscience yes i got that far but i honestly dont know which equations i start with

@moeishadixon3555 4 года назад

do i need to now find the final velocity and time? because they gave me 4m for the height which im guessing is the displacement

@rhomelynmalana1892 7 лет назад

thank you so much . your video is very helpful

@lamnguyen-bi8jm 7 лет назад

I have a question. When you calculated the total time the ball stays in the air. Why did you only use delta y = 17m?. Should we use 28.5 to calculate the total time the ball stay in the air since 28.5m is the total distance that the ball stay in the air? Thank you.

@stepbystepscience 7 лет назад

lam nguyen good question, Delta Y is really the change in Position not the distance. From where the ball starts to where it ends there is a change in position of -17m

@lamnguyen-bi8jm 7 лет назад

uhm! It seems a little bit counter-intuitive to use the change in position, not the actual distance the ball stay in the air, to calculate the time the ball stays in the air. Anyway, thank you very much for your promt respond.

@smoothjr12 5 лет назад

I have a question about another problem how can you assist me with that?

@hizamalik3761 6 лет назад

THANK YOU

@stepbystepscience 6 лет назад

Your are very welcome

@amagwijo4542 7 лет назад

thank you your video was very helpful

@stepbystepscience 7 лет назад

Thanks for the comment.

@ihatemattmurdock 5 месяцев назад

you have helped me so much in understanding physics i love u

@stepbystepscience 5 месяцев назад

Thanks so much, I'm really happy to help. Best wishes.

@mariafeluntoco7379 4 года назад

Where can I find part 2 and 3????

@stepbystepscience 4 года назад

Here you go: Part 2: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-Wd36d2C-iaA.html Part 3: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-Fb1TDt_XA7.html

@mariafeluntoco7379 4 года назад

@@stepbystepscience thank you so much, sir Brian🥰

@wesammuneer8926 3 года назад

thanks man

@stepbystepscience 3 года назад

Any time

@coolkorsah1 3 года назад

How did you get 11.5m? I plugged in the same calculations yet I got a number that's far beyond what was posted in the video. EDIT: Nevermind. I understand how you did it. If a person crammed the entire calculation in one go, they'll get a crazy number.

@Ra3d12 7 лет назад

if i throw a 100 kg object from a height 1000 meters how strong it will hit the ground ?? how much force? please if somebody knows tell me what equation be used to know the forces acting upon falling bodies

@asfagul8786 6 лет назад

Force = mass × acceleration due to gravity & vf²=vi²+ 2gH

@maiyaelise601 3 года назад

I don’t have an initial height for my equation so what am I supposed to add?

@James-ko1hj 3 года назад

if its not given then its zero

@antivenomplays2355 5 лет назад

you are the best thx

@stepbystepscience 5 лет назад

You are very welcome, thanks for taking the time to comment.

@nayantararanganatha6083 8 лет назад

I have a question. Why is the inicial velocity negative in the calculations?

@stepbystepscience 8 лет назад

Good question...because when you solve the equation for the height you have to subtract the initial velocity from both sides and therfore you have minus initial velocity squared. Does that help? You can see a listing of all my videos at my website, www.stepbystepscience.com

@nayantararanganatha6083 8 лет назад

Thank you!